您可以将源字符串输送到findstr，并检查ERRORLEVEL的值，以查看是否找到了模式字符串。值为0表示成功，并且找到了模式。这里有一个例子:

::
: Y.CMD - Test if pattern in string
: P1 - the pattern
: P2 - the string to check
::
@echo off

echo.%2 | findstr /C:"%1" 1>nul

if errorlevel 1 (
  echo. got one - pattern not found
) ELSE (
  echo. got zero - found pattern
)

当在CMD.EXE中运行时，我们得到:

C:\DemoDev>y pqrs "abc def pqr 123"
 got one - pattern not found

C:\DemoDev>y pqr "abc def pqr 123" 
 got zero - found pattern

ECHO %String%| FINDSTR /C:"%Substring%" && (Instructions)

您可以将源字符串输送到findstr，并检查ERRORLEVEL的值，以查看是否找到了模式字符串。值为0表示成功，并且找到了模式。这里有一个例子:

::
: Y.CMD - Test if pattern in string
: P1 - the pattern
: P2 - the string to check
::
@echo off

echo.%2 | findstr /C:"%1" 1>nul

if errorlevel 1 (
  echo. got one - pattern not found
) ELSE (
  echo. got zero - found pattern
)

当在CMD.EXE中运行时，我们得到:

C:\DemoDev>y pqrs "abc def pqr 123"
 got one - pattern not found

C:\DemoDev>y pqr "abc def pqr 123" 
 got zero - found pattern

为了兼容性和易用性，通常最好使用FIND来执行此操作。

还必须考虑是区分大小写匹配还是不区分大小写匹配。

78点的方法(我相信我指的是paxdiablo的帖子)只会匹配大小写敏感，所以你必须为你想要匹配的每个可能迭代的每个大小写变化单独检查。

)真痛苦!只有3个字母，这意味着要完成9个不同的测试!)

此外，很多时候匹配命令输出、循环中的变量或批处理/CMD中指针变量的值更可取。

由于这些原因，这是一个更好的替代方法:

使用方法:查找[/I] [/V] " character to Match"

[/I](不区分大小写) [/V](不能包含字符)

作为单线:

ECHO.%Variable% | FIND /I "ABC">Nul && ( Echo.Found "ABC" ) || ( Echo.Did not find "ABC" )

多行:

ECHO.%Variable%| FIND /I "ABC">Nul && ( 
  Echo.Found "ABC"
) || (
  Echo.Did not find "ABC"
)

如上所述，这对于变量中不允许字符串替换的东西非常有用:

FOR %A IN (
  "Some long string with Spaces does not contain the expected string"
  oihu AljB
  lojkAbCk
  Something_Else
 "Going to evaluate this entire string for ABC as well!"
) DO (
  ECHO.%~A| FIND /I "ABC">Nul && (
    Echo.Found "ABC" in "%A"
  ) || ( Echo.Did not find "ABC" )
)

Output From a command:

    NLTest | FIND /I "ABC">Nul && ( Echo.Found "ABC" ) || ( Echo.Did not find "ABC" )

As you can see this is the superior way to handle the check for multiple reasons.

建立在@user839791的答案上，但我又添加了一些东西。

@echo off
rem --Set variable below--
set var=condition

rem --Uncomment below line to display contents of variable--
::echo The variable is %var%

rem --Change condition to desired string below--
ECHO.%var%| FIND /I "condition">Nul && (  
  rem --Occurs if the string is found--
  Echo.Variable is "condition"
  color C
  pause
) || (
  rem --Occurs if the string isn't found--
  Echo.Variable is not "condition"
  color A
  pause
)

更好的答案是:

set "i=hello " world"
set i|find """" >nul && echo contains || echo not_contains