ECHO %String%| FINDSTR /C:"%Substring%" && (Instructions)

对我来说最好的方法是:

call :findInString "HelloWorld" "World"

:findInString
ECHO.%1 | FIND /I %2>Nul && ( 
  Echo.Found
) || (
  Echo.Not found
)

更好的答案是:

set "i=hello " world"
set i|find """" >nul && echo contains || echo not_contains

ECHO %String%| FINDSTR /C:"%Substring%" && (Instructions)

我通常是这样做的:

Echo.%1 | findstr /C:"%2">nul && (
    REM TRUE
) || (
    REM FALSE
)

例子:

Echo.Hello world | findstr /C:"world">nul && (
    Echo.TRUE
) || (
    Echo.FALSE
)

Echo.Hello world | findstr /C:"World">nul && (Echo.TRUE) || (Echo.FALSE)

输出:

TRUE
FALSE

我不知道这是不是最好的办法。

您可以将源字符串输送到findstr，并检查ERRORLEVEL的值，以查看是否找到了模式字符串。值为0表示成功，并且找到了模式。这里有一个例子:

::
: Y.CMD - Test if pattern in string
: P1 - the pattern
: P2 - the string to check
::
@echo off

echo.%2 | findstr /C:"%1" 1>nul

if errorlevel 1 (
  echo. got one - pattern not found
) ELSE (
  echo. got zero - found pattern
)

当在CMD.EXE中运行时，我们得到:

C:\DemoDev>y pqrs "abc def pqr 123"
 got one - pattern not found

C:\DemoDev>y pqr "abc def pqr 123" 
 got zero - found pattern