我需要使用“HTTP Post”与WebClient Post一些数据到特定的URL我有。
现在,我知道这可以用WebRequest完成,但由于某些原因,我想使用WebClient代替。这可能吗?如果是这样,谁能给我举个例子或者给我指出正确的方向?
我需要使用“HTTP Post”与WebClient Post一些数据到特定的URL我有。
现在,我知道这可以用WebRequest完成,但由于某些原因,我想使用WebClient代替。这可能吗?如果是这样,谁能给我举个例子或者给我指出正确的方向?
当前回答
使用简单客户端。UploadString(地址、内容);正常工作很好,但我认为应该记住,如果没有返回HTTP成功状态码,将抛出webeexception。我通常这样处理,打印远程服务器返回的任何异常消息:
try
{
postResult = client.UploadString(address, content);
}
catch (WebException ex)
{
String responseFromServer = ex.Message.ToString() + " ";
if (ex.Response != null)
{
using (WebResponse response = ex.Response)
{
Stream dataRs = response.GetResponseStream();
using (StreamReader reader = new StreamReader(dataRs))
{
responseFromServer += reader.ReadToEnd();
_log.Error("Server Response: " + responseFromServer);
}
}
}
throw;
}
其他回答
使用简单客户端。UploadString(地址、内容);正常工作很好,但我认为应该记住,如果没有返回HTTP成功状态码,将抛出webeexception。我通常这样处理,打印远程服务器返回的任何异常消息:
try
{
postResult = client.UploadString(address, content);
}
catch (WebException ex)
{
String responseFromServer = ex.Message.ToString() + " ";
if (ex.Response != null)
{
using (WebResponse response = ex.Response)
{
Stream dataRs = response.GetResponseStream();
using (StreamReader reader = new StreamReader(dataRs))
{
responseFromServer += reader.ReadToEnd();
_log.Error("Server Response: " + responseFromServer);
}
}
}
throw;
}
使用WebClient。UploadString或WebClient。UploadData可以轻松地将数据POST到服务器。我将展示一个使用UploadData的示例,因为UploadString的使用方式与DownloadString相同。
byte[] bret = client.UploadData("http://www.website.com/post.php", "POST",
System.Text.Encoding.ASCII.GetBytes("field1=value1&field2=value2") );
string sret = System.Text.Encoding.ASCII.GetString(bret);
更多:http://www.daveamenta.com/2008-05/c-webclient-usage/
下面是简单明了的答案:
public String sendSMS(String phone, String token) {
WebClient webClient = WebClient.create(smsServiceUrl);
SMSRequest smsRequest = new SMSRequest();
smsRequest.setMessage(token);
smsRequest.setPhoneNo(phone);
smsRequest.setTokenId(smsServiceTokenId);
Mono<String> response = webClient.post()
.uri(smsServiceEndpoint)
.header(HttpHeaders.CONTENT_TYPE, MediaType.APPLICATION_JSON_VALUE)
.body(Mono.just(smsRequest), SMSRequest.class)
.retrieve().bodyToMono(String.class);
String deliveryResponse = response.block();
if (deliveryResponse.equalsIgnoreCase("success")) {
return deliveryResponse;
}
return null;
}
我刚刚找到了解决方案,是的,它比我想象的要简单:)
这就是解决方案:
string URI = "http://www.myurl.com/post.php";
string myParameters = "param1=value1¶m2=value2¶m3=value3";
using (WebClient wc = new WebClient())
{
wc.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
string HtmlResult = wc.UploadString(URI, myParameters);
}
它很有魅力:)
string URI = "site.com/mail.php";
using (WebClient client = new WebClient())
{
System.Collections.Specialized.NameValueCollection postData =
new System.Collections.Specialized.NameValueCollection()
{
{ "to", emailTo },
{ "subject", currentSubject },
{ "body", currentBody }
};
string pagesource = Encoding.UTF8.GetString(client.UploadValues(URI, postData));
}