使用https://www.npmjs.com/package/uri-parse-lib进行此操作

var t = parserURI("http://user:pass@example.com:8080/directory/file.ext?query=1&next=4&sed=5#anchor");

function parseUrl(url) {
    var m = url.match(/^((?:([^:\/?#]+:)(?:\/\/))?((?:([^\/?#:]*):([^\/?#:]*)@)?([^\/?#:]*)(?::([^\/?#:]*))?))?([^?#]*)(\?[^#]*)?(#.*)?$/),
        r = {
            hash: m[10] || "",                   // #asd
            host: m[3] || "",                    // localhost:257
            hostname: m[6] || "",                // localhost
            href: m[0] || "",                    // http://username:password@localhost:257/deploy/?asd=asd#asd
            origin: m[1] || "",                  // http://username:password@localhost:257
            pathname: m[8] || (m[1] ? "/" : ""), // /deploy/
            port: m[7] || "",                    // 257
            protocol: m[2] || "",                // http:
            search: m[9] || "",                  // ?asd=asd
            username: m[4] || "",                // username
            password: m[5] || ""                 // password
        };
    if (r.protocol.length == 2) {
        r.protocol = "file:///" + r.protocol.toUpperCase();
        r.origin = r.protocol + "//" + r.host;
    }
    r.href = r.origin + r.pathname + r.search + r.hash;
    return r;
};
parseUrl("http://username:password@localhost:257/deploy/?asd=asd#asd");

它既适用于绝对url，也适用于相对url

js-uri(在谷歌Code上可用)接受字符串URL并从中解析URI对象:

var some_uri = new URI("http://www.example.com/foo/bar");

alert(some_uri.authority); // www.example.com
alert(some_uri);           // http://www.example.com/foo/bar

var blah      = new URI("blah");
var blah_full = blah.resolve(some_uri);
alert(blah_full);         // http://www.example.com/foo/blah

第一个答案的简单破解

var getLocation = function(href=window.location.href) {
    var l = document.createElement("a");
    l.href = href;
    return l;
};

即使没有参数，也可以使用它来计算当前的主机名 getLocation()。Hostname将给出当前主机名

var getLocation = function(href) {
    var l = document.createElement("a");
    l.href = href;
    return l;
};
var l = getLocation("http://example.com/path");
console.debug(l.hostname)
>> "example.com"
console.debug(l.pathname)
>> "/path"

对于那些正在寻找在IE, Firefox和Chrome中工作的现代解决方案的人:

这些使用超链接元素的解决方案都不会在chrome中起同样的作用。如果你传递一个无效(或空白)的url给chrome，它总是会返回脚本被调用的主机。所以在IE中你会得到空白，而在Chrome中你会得到localhost(或其他什么)。

如果你试图看着推荐人，这是骗人的。你需要确保你返回的主机在原始url中，以处理这个问题:

    function getHostNameFromUrl(url) {
        // <summary>Parses the domain/host from a given url.</summary>
        var a = document.createElement("a");
        a.href = url;

        // Handle chrome which will default to domain where script is called from if invalid
        return url.indexOf(a.hostname) != -1 ? a.hostname : '';
    }