基本上,就像标题说的那样。我想知道如何添加1天的NSDate。
如果它是:
21st February 2011
它将变成:
22nd February 2011
或者如果它是:
31st December 2011
它将变成:
1st January 2012.
基本上,就像标题说的那样。我想知道如何添加1天的NSDate。
如果它是:
21st February 2011
它将变成:
22nd February 2011
或者如果它是:
31st December 2011
它将变成:
1st January 2012.
当前回答
你可以使用NSDate的方法- (id)dateByAddingTimeInterval:(NSTimeInterval)秒,其中秒为60 * 60 * 24 = 86400
其他回答
使用下面的函数,并使用days参数来获取日期daysAhead/daysBehind,只需将参数传递为正,表示未来日期,为负,表示之前日期:
+ (NSDate *) getDate:(NSDate *)fromDate daysAhead:(NSUInteger)days
{
NSDateComponents *dateComponents = [[NSDateComponents alloc] init];
dateComponents.day = days;
NSCalendar *calendar = [NSCalendar currentCalendar];
NSDate *previousDate = [calendar dateByAddingComponents:dateComponents
toDate:fromDate
options:0];
[dateComponents release];
return previousDate;
}
使用以下代码:
NSDate *now = [NSDate date];
int daysToAdd = 1;
NSDate *newDate1 = [now dateByAddingTimeInterval:60*60*24*daysToAdd];
As
addTimeInterval
现在已弃用。
在斯威夫特
var dayComponenet = NSDateComponents()
dayComponenet.day = 1
var theCalendar = NSCalendar.currentCalendar()
var nextDate = theCalendar.dateByAddingComponents(dayComponenet, toDate: NSDate(), options: nil)
Swift 5.0:
var dayComponent = DateComponents()
dayComponent.day = 1 // For removing one day (yesterday): -1
let theCalendar = Calendar.current
let nextDate = theCalendar.date(byAdding: dayComponent, to: Date())
print("nextDate : \(nextDate)")
目标C:
NSDateComponents *dayComponent = [[NSDateComponents alloc] init];
dayComponent.day = 1;
NSCalendar *theCalendar = [NSCalendar currentCalendar];
NSDate *nextDate = [theCalendar dateByAddingComponents:dayComponent toDate:[NSDate date] options:0];
NSLog(@"nextDate: %@ ...", nextDate);
这应该是不言而喻的。
在swift中,您可以在NSDate中添加扩展方法
extension NSDate {
func addNoOfDays(noOfDays:Int) -> NSDate! {
let cal:NSCalendar = NSCalendar.currentCalendar()
cal.timeZone = NSTimeZone(abbreviation: "UTC")!
let comps:NSDateComponents = NSDateComponents()
comps.day = noOfDays
return cal.dateByAddingComponents(comps, toDate: self, options: nil)
}
}
你可以用这个
NSDate().addNoOfDays(3)