在解决方案中很可能已经定义了DataSet、DataTable和DataRow的类。如果是这样的话，就不需要DataSetExtensions引用了。

示例:数据集类名称-> CustomSet，数据流类名称-> CustomTableRow(定义列:RowNo，…)

var result = from myRow in myDataTable.Rows.OfType<CustomSet.CustomTableRow>()
             where myRow.RowNo == 1
             select myRow;

或者(随我喜欢)

var result = myDataTable.Rows.OfType<CustomSet.CustomTableRow>().Where(myRow => myRow.RowNo);

var results = from DataRow myRow in myDataTable.Rows
    where (int)myRow["RowNo"] == 1
    select myRow

你可以对Rows集合上的对象使用LINQ，如下所示:

var results = from myRow in myDataTable.Rows where myRow.Field("RowNo") == 1 select myRow;

在我的应用程序中，我发现使用LINQ到数据集的AsEnumerable()扩展数据表，如答案中所建议的是非常慢的。如果你对优化速度感兴趣，可以使用James Newtonking的Json。网上图书馆(http://james.newtonking.com/json/help/index.html)

// Serialize the DataTable to a json string
string serializedTable = JsonConvert.SerializeObject(myDataTable);    
Jarray dataRows = Jarray.Parse(serializedTable);

// Run the LINQ query
List<JToken> results = (from row in dataRows
                    where (int) row["ans_key"] == 42
                    select row).ToList();

// If you need the results to be in a DataTable
string jsonResults = JsonConvert.SerializeObject(results);
DataTable resultsTable = JsonConvert.DeserializeObject<DataTable>(jsonResults);

//Create DataTable 
DataTable dt= new DataTable();
dt.Columns.AddRange(new DataColumn[]
{
   new DataColumn("ID",typeof(System.Int32)),
   new DataColumn("Name",typeof(System.String))

});

//Fill with data

dt.Rows.Add(new Object[]{1,"Test1"});
dt.Rows.Add(new Object[]{2,"Test2"});

//Now  Query DataTable with linq
//To work with linq it should required our source implement IEnumerable interface.
//But DataTable not Implement IEnumerable interface
//So we call DataTable Extension method  i.e AsEnumerable() this will return EnumerableRowCollection<DataRow>


// Now Query DataTable to find Row whoes ID=1

DataRow drow = dt.AsEnumerable().Where(p=>p.Field<Int32>(0)==1).FirstOrDefault();
 // 

VB。代码如下所示:

Dim results = From myRow In myDataTable  
Where myRow.Field(Of Int32)("RowNo") = 1 Select myRow