这是我的舱单:

<service android:name=".fcm.PshycoFirebaseMessagingServices">
    <intent-filter>
        <action android:name="com.google.firebase.MESSAGING_EVENT" />
    </intent-filter>
</service>

<service android:name=".fcm.PshycoFirebaseInstanceIDService">
    <intent-filter>
        <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
    </intent-filter>
</service>

当应用程序在后台和通知到达,然后默认通知来,不运行我的onmessagerreceived代码。

这是我的onMessageReceived代码。如果我的应用程序在前台运行,而不是在后台运行,就会调用这个函数。我怎么能运行这段代码时,应用程序是在后台太?

// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
    // TODO(developer): Handle FCM messages here.
    // If the application is in the foreground handle both data and notification messages here.
    // Also if you intend on generating your own notifications as a result of a received FCM
    // message, here is where that should be initiated. See sendNotification method below.
    data = remoteMessage.getData();
    String title = remoteMessage.getNotification().getTitle();
    String message = remoteMessage.getNotification().getBody();
    String imageUrl = (String) data.get("image");
    String action = (String) data.get("action");
    Log.i(TAG, "onMessageReceived: title : "+title);
    Log.i(TAG, "onMessageReceived: message : "+message);
    Log.i(TAG, "onMessageReceived: imageUrl : "+imageUrl);
    Log.i(TAG, "onMessageReceived: action : "+action);

    if (imageUrl == null) {
        sendNotification(title,message,action);
    } else {
        new BigPictureNotification(this,title,message,imageUrl,action);
    }
}
// [END receive_message]

当前回答

我也有同样的问题。经过一些挖掘为什么我的MainActivity被调用意图没有数据,我意识到我的发射器活动(如在Manifest)是SplashActivity。在那里我找到了消息数据,并将它们转发给MainActivity。效果很好。我相信这能帮助到一些人。

谢谢你的回答。

其他回答

要在后台捕获消息,您需要使用BroadcastReceiver

import android.content.Context
import android.content.Intent
import android.util.Log
import androidx.legacy.content.WakefulBroadcastReceiver
import com.google.firebase.messaging.RemoteMessage

class FirebaseBroadcastReceiver : WakefulBroadcastReceiver() {

    val TAG: String = FirebaseBroadcastReceiver::class.java.simpleName

    override fun onReceive(context: Context, intent: Intent) {

        val dataBundle = intent.extras
        if (dataBundle != null)
            for (key in dataBundle.keySet()) {
                Log.d(TAG, "dataBundle: " + key + " : " + dataBundle.get(key))
            }
        val remoteMessage = RemoteMessage(dataBundle)
        }
    }

把这个加到你的舱单上

<receiver
      android:name="MY_PACKAGE_NAME.FirebaseBroadcastReceiver"
      android:exported="true"
      android:permission="com.google.android.c2dm.permission.SEND">
        <intent-filter>
            <action android:name="com.google.android.c2dm.intent.RECEIVE" />
        </intent-filter>
</receiver>

根据文件

Handle messages in a backgrounded app When your app is in the background, Android directs notification messages to the system tray. A user tap on the notification opens the app launcher by default. This includes messages that contain both notification and data payload. In these cases, the notification is delivered to the device's system tray, and the data payload is delivered in the extras of the intent of your launcher Activity. If you want to open your app and perform a specific action, set click_action in the notification payload and map it to an intent filter in the Activity you want to launch. For example, set click_action to OPEN_ACTIVITY_1 to trigger an intent filter like the following:

 <intent-filter>   <action android:name="OPEN_ACTIVITY_1" />  
 <category android:name="android.intent.category.DEFAULT" />
 </intent-filter>

编辑:

基于这个线程:

不能使用Firebase Console设置click_action有效负载。您可以尝试使用curl命令或自定义http服务器进行测试

curl --header "Authorization: key=<YOUR_KEY_GOES_HERE>" 
     --header Content-Type:"application/json" https://fcm.googleapis.com/fcm/send  
     -d "{\"to\":\"/topics/news\",\"notification\": 
         {\"title\": \"Click Action Message\",\"text\": \"Sample message\",
            \"click_action\":\"OPEN_ACTIVITY_1\"}}"

从服务器请求中完全删除通知有效负载。只发送数据并在onmessagerreceived()中处理它,否则当应用程序在后台或被杀死时,你的onmessagerreceived将不会被触发。

这是我从服务器发送的:

{
  "data":{
    "id": 1,
    "missedRequests": 5
    "addAnyDataHere": 123
  },
  "to": "fhiT7evmZk8:APA91bFJq7Tkly4BtLRXdYvqHno2vHCRkzpJT8QZy0TlIGs......"
}

你可以像这样在onMessageReceived(RemoteMessage message)中接收你的数据(假设我需要获取id)

Object obj = message.getData().get("id");
        if (obj != null) {
            int id = Integer.valueOf(obj.toString());
        }

类似地,你可以在onmessagerecreceived()内从服务器获得任何数据。

发送消息的简单方法,即使应用程序是在后台和前台如下:- 要使用API发送消息,您可以使用一个名为AdvancedREST客户端工具,它是一个chrome扩展,并发送带有以下参数的消息。

Rest客户端工具链接:https://chrome.google.com/webstore/detail/advanced-rest-client/hgmloofddffdnphfgcellkdfbfbjeloo

使用这个url:- https://fcm.googleapis.com/fcm/send 内容类型:application / json 授权:key=您的服务器密钥或授权密钥(参见下面的参考)

{ "data": {
    "image": "https://static.pexels.com/photos/4825/red-love-romantic-flowers.jpg",
    "message": "Firebase Push Message Using API"
    "AnotherActivity": "True"
     },
  "to" : "device id Or Device token"
}

授权密钥可以通过访问谷歌开发人员控制台,并单击项目左侧菜单上的凭证按钮来获得。在列出的API密钥中,服务器密钥将是您的授权密钥。

并且您需要将接收者的tokenID放在使用API发送的POST请求的“to”部分。

自2019年以来,谷歌Firebase的api有了很大的变化 我的意思是: “com.google.firebase: firebase-messaging: 18.0.0”

在18.0.0中,他们删除了MyFirebaseInstanceIDService,你需要在MyFirebaseMessagingService中获取令牌,所以你只需要写:

@Override
public void onNewToken(String token) {
    Log.d(TAG, "Refreshed token: " + token);

}

在你的AndroidManifest.xml中,你必须删除:

<service android:name=".service.MyFirebaseInstanceIDService">
        <intent-filter>
            <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
        </intent-filter>
    </service>

此外,建议您设置默认值以自定义通知的外观。您可以指定自定义默认图标和自定义默认颜色,在通知有效负载中没有设置等效值时应用它们。

在应用程序标记中添加这些行来设置自定义默认图标和自定义颜色:

    <meta-data
        android:name="com.google.firebase.messaging.default_notification_icon"
        android:resource="@drawable/ic_notification" />

    <meta-data
        android:name="com.google.firebase.messaging.default_notification_color"
        android:resource="@color/colorAccent" />

    <meta-data
        android:name="com.google.firebase.messaging.default_notification_channel_id"
        android:value="@string/push_channel" />

现在要在后台应用程序中处理通知消息,你应该在你的第一个Activity中定义一个Intent,即使它是SplashScreen。当你的应用程序在后台时,Android将通知消息定向到系统托盘。用户点击通知会默认打开应用启动器。

例如,如果你的Json是这样的:

 "data": {
"message": "2",
"title": "1",
"pushType" : "banner",
"bannerLink": "http://www.google.com",
"image" : "https://www.google.com/images/branding/googlelogo/1x/googlelogo_color_272x92dp.png"}

你只需要写一个简单的意图来获取这些值:

        Bundle extras = intent.getExtras();
        String bannerLink = extras.getString("bannerLink");
        ...
        String channelId = extras.getString("channelId");