这是我的舱单:

<service android:name=".fcm.PshycoFirebaseMessagingServices">
    <intent-filter>
        <action android:name="com.google.firebase.MESSAGING_EVENT" />
    </intent-filter>
</service>

<service android:name=".fcm.PshycoFirebaseInstanceIDService">
    <intent-filter>
        <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
    </intent-filter>
</service>

当应用程序在后台和通知到达,然后默认通知来,不运行我的onmessagerreceived代码。

这是我的onMessageReceived代码。如果我的应用程序在前台运行,而不是在后台运行,就会调用这个函数。我怎么能运行这段代码时,应用程序是在后台太?

// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
    // TODO(developer): Handle FCM messages here.
    // If the application is in the foreground handle both data and notification messages here.
    // Also if you intend on generating your own notifications as a result of a received FCM
    // message, here is where that should be initiated. See sendNotification method below.
    data = remoteMessage.getData();
    String title = remoteMessage.getNotification().getTitle();
    String message = remoteMessage.getNotification().getBody();
    String imageUrl = (String) data.get("image");
    String action = (String) data.get("action");
    Log.i(TAG, "onMessageReceived: title : "+title);
    Log.i(TAG, "onMessageReceived: message : "+message);
    Log.i(TAG, "onMessageReceived: imageUrl : "+imageUrl);
    Log.i(TAG, "onMessageReceived: action : "+action);

    if (imageUrl == null) {
        sendNotification(title,message,action);
    } else {
        new BigPictureNotification(this,title,message,imageUrl,action);
    }
}
// [END receive_message]

当前回答

要在后台捕获消息,您需要使用BroadcastReceiver

import android.content.Context
import android.content.Intent
import android.util.Log
import androidx.legacy.content.WakefulBroadcastReceiver
import com.google.firebase.messaging.RemoteMessage

class FirebaseBroadcastReceiver : WakefulBroadcastReceiver() {

    val TAG: String = FirebaseBroadcastReceiver::class.java.simpleName

    override fun onReceive(context: Context, intent: Intent) {

        val dataBundle = intent.extras
        if (dataBundle != null)
            for (key in dataBundle.keySet()) {
                Log.d(TAG, "dataBundle: " + key + " : " + dataBundle.get(key))
            }
        val remoteMessage = RemoteMessage(dataBundle)
        }
    }

把这个加到你的舱单上

<receiver
      android:name="MY_PACKAGE_NAME.FirebaseBroadcastReceiver"
      android:exported="true"
      android:permission="com.google.android.c2dm.permission.SEND">
        <intent-filter>
            <action android:name="com.google.android.c2dm.intent.RECEIVE" />
        </intent-filter>
</receiver>

其他回答

使用这段代码,你可以在后台/前台获得通知,也可以放置动作:

//Data should come in this format from the notification
{
  "to": "/xyz/Notifications",
  "data": {
      "key1": "title notification",
      "key2": "description notification"
  }
}

在应用程序中使用以下代码:

  @Override
    public void onMessageReceived(RemoteMessage remoteMessage) {
        super.onMessageReceived(remoteMessage);
      String key1Data = remoteMessage.getData().get("key1");
      // use key1Data to according to your need
    }

像这样简单的总结

如果你的应用正在运行; onMessageReceived ()

是触发器。

如果你的应用程序没有运行(通过滑动杀死); onMessageReceived ()

不是直接触发和传递的。如果你有特殊的键值对。它们不工作,因为onmessagerecreceived()不工作。

我找到了这条路;

在你的启动器活动中,放入这样的逻辑,

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState, R.layout.activity_splash);

    if (getIntent().getExtras() != null && getIntent().getExtras().containsKey("PACKAGE_NAME")) {

        // do what you want

        // and this for killing app if we dont want to start
        android.os.Process.killProcess(android.os.Process.myPid());

    } else {

        //continue to app
    }
}

在这个if块中,根据firebase UI搜索你的密钥。

在这个例子中,我的键和值就像上面那样;(对不起,语言=))

当我的代码工作时,我得到“com.rda.note”。

android.os.Process.killProcess(android.os.Process.myPid());

有了这行代码,我关闭了我的应用程序,打开谷歌播放市场

快乐编码=)

下面是关于firebase消息的更清晰的概念。我从他们的支援组找到的。

Firebase有三种消息类型:

通知消息:通知消息工作在后台或前台。当app在后台时,通知消息被传递到系统托盘。如果应用程序在前台,消息由onmessagerreceived()或didReceiveRemoteNotification回调处理。这些实质上就是所谓的显示消息。

数据消息:在Android平台上,数据消息可以工作在后台和前台。数据消息将由onMessageReceived()处理。在Android上,数据有效载荷可以在用于启动你的活动的Intent中检索。具体来说,如果你有"click_action":"launch_Activity_1",你只能通过getIntent()从Activity_1中检索这个意图。

Messages with both notification and data payloads: When in the background, apps receive the notification payload in the notification tray, and only handle the data payload when the user taps on the notification. When in the foreground, your app receives a message object with both payloads available. Secondly, the click_action parameter is often used in notification payload and not in data payload. If used inside data payload, this parameter would be treated as custom key-value pair and therefore you would need to implement custom logic for it to work as intended.

另外,我建议您使用onMessageReceived方法(参见数据消息)来提取数据包。根据您的逻辑,我检查了bundle对象,并没有发现预期的数据内容。这里有一个类似案例的参考,可能会更清楚。

欲了解更多信息,请访问我的这个线程

提供的解决方案对我的情况不起作用。

最后,我发现一些电池优化应用程序允许用户控制应用程序发送通知。在我的例子中,三星的Smart Manager在我的应用被从最近列表中删除后就自动阻止了它。

关闭我的应用程序的这个功能是我能找到的唯一解决办法。

2018年6月答案:

你必须确保消息中没有“通知”关键字。只包括“data”,应用程序将能够处理onmessagerreceived中的消息,即使在后台或已杀死。

使用云功能:

const message = {
    token: token_id,   // obtain device token id by querying data in firebase
    data: {
       title: "my_custom_title",
       body:  "my_custom_body_message"
       }
    }


return admin.messaging().send(message).then(response => {
    // handle response
});

然后在onmessagerreceived()中,在你的类中扩展com.google.firebase.messaging.FirebaseMessagingService:

if (data != null) {
  Log.d(TAG, "data title is: " + data.get("title");
  Log.d(TAG, "data body is: " + data.get("body");
}

// build notification using the body, title, and whatever else you want.