这是我的舱单:

<service android:name=".fcm.PshycoFirebaseMessagingServices">
    <intent-filter>
        <action android:name="com.google.firebase.MESSAGING_EVENT" />
    </intent-filter>
</service>

<service android:name=".fcm.PshycoFirebaseInstanceIDService">
    <intent-filter>
        <action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
    </intent-filter>
</service>

当应用程序在后台和通知到达,然后默认通知来,不运行我的onmessagerreceived代码。

这是我的onMessageReceived代码。如果我的应用程序在前台运行,而不是在后台运行,就会调用这个函数。我怎么能运行这段代码时,应用程序是在后台太?

// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
    // TODO(developer): Handle FCM messages here.
    // If the application is in the foreground handle both data and notification messages here.
    // Also if you intend on generating your own notifications as a result of a received FCM
    // message, here is where that should be initiated. See sendNotification method below.
    data = remoteMessage.getData();
    String title = remoteMessage.getNotification().getTitle();
    String message = remoteMessage.getNotification().getBody();
    String imageUrl = (String) data.get("image");
    String action = (String) data.get("action");
    Log.i(TAG, "onMessageReceived: title : "+title);
    Log.i(TAG, "onMessageReceived: message : "+message);
    Log.i(TAG, "onMessageReceived: imageUrl : "+imageUrl);
    Log.i(TAG, "onMessageReceived: action : "+action);

    if (imageUrl == null) {
        sendNotification(title,message,action);
    } else {
        new BigPictureNotification(this,title,message,imageUrl,action);
    }
}
// [END receive_message]

当前回答

要在后台捕获消息,您需要使用BroadcastReceiver

import android.content.Context
import android.content.Intent
import android.util.Log
import androidx.legacy.content.WakefulBroadcastReceiver
import com.google.firebase.messaging.RemoteMessage

class FirebaseBroadcastReceiver : WakefulBroadcastReceiver() {

    val TAG: String = FirebaseBroadcastReceiver::class.java.simpleName

    override fun onReceive(context: Context, intent: Intent) {

        val dataBundle = intent.extras
        if (dataBundle != null)
            for (key in dataBundle.keySet()) {
                Log.d(TAG, "dataBundle: " + key + " : " + dataBundle.get(key))
            }
        val remoteMessage = RemoteMessage(dataBundle)
        }
    }

把这个加到你的舱单上

<receiver
      android:name="MY_PACKAGE_NAME.FirebaseBroadcastReceiver"
      android:exported="true"
      android:permission="com.google.android.c2dm.permission.SEND">
        <intent-filter>
            <action android:name="com.google.android.c2dm.intent.RECEIVE" />
        </intent-filter>
</receiver>

其他回答

要在后台捕获消息,您需要使用BroadcastReceiver

import android.content.Context
import android.content.Intent
import android.util.Log
import androidx.legacy.content.WakefulBroadcastReceiver
import com.google.firebase.messaging.RemoteMessage

class FirebaseBroadcastReceiver : WakefulBroadcastReceiver() {

    val TAG: String = FirebaseBroadcastReceiver::class.java.simpleName

    override fun onReceive(context: Context, intent: Intent) {

        val dataBundle = intent.extras
        if (dataBundle != null)
            for (key in dataBundle.keySet()) {
                Log.d(TAG, "dataBundle: " + key + " : " + dataBundle.get(key))
            }
        val remoteMessage = RemoteMessage(dataBundle)
        }
    }

把这个加到你的舱单上

<receiver
      android:name="MY_PACKAGE_NAME.FirebaseBroadcastReceiver"
      android:exported="true"
      android:permission="com.google.android.c2dm.permission.SEND">
        <intent-filter>
            <action android:name="com.google.android.c2dm.intent.RECEIVE" />
        </intent-filter>
</receiver>

我觉得所有的响应都是不完整的,但它们都有一些你需要处理的东西,当你的应用程序在后台时,一个有数据的通知。

遵循这些步骤,你将能够在应用程序处于后台时处理通知。

添加一个intent-filter,像这样: <活动android: name = "。MainActivity”> <意图过滤器> <行动android: name = "。MainActivity " / > <category android:name="android.intent.category. default " /> < /意图过滤器>

到要处理通知数据的活动。

以以下格式发送通知: { “通知”:{ "click_action": "。MainActivity”, "body": "new Symulti update !", "title": "新的Symulti更新!", "icon": "ic_notif_symulti"}, "data":{…}, "to": "c9Vaa3ReGdk:APA91bH-AuXgg3lDN2WMcBrNhJZoFtYF9"}

这里的关键是加法

"click_action" : ".MainActivity"

其中. mainactivity是您在步骤1中添加的带有intent-filter的活动。

从.MainActivity的onCreate中的通知中获取数据信息: onCreate(Bundle savedInstanceState) super.onCreate (savedInstanceState); setContentView (R.layout.activity_main); //获取通知数据信息 Bundle Bundle = getIntent().getExtras(); If (bundle != null) { //bundle必须包含通知的"data"字段发送的所有信息 } }

这就是你需要做的。

此情况仅用于firebase管理通知 如果应用程序在后台,则不会触发FirebaseMessagingService

要处理这种情况,请转到launcher activity,检查附加的intent bundle,并使用以下代码打印出所有数据:

 intent?.extras?.let {it->
        for (key in bundle.keySet()) {
            val value = bundle[key]
            Log.d("NotificationData", String.format("%s %s (%s)", key, value.toString(), value!!.javaClass.name))
        }
    }

显示所有数据类型的签入日志;

例子:

我想从通知中获得周和标题将使用这段代码

intent?.extras?.let {it->
        if (it.containsKey("week")){
            
        }
        if (it.containsKey("title")){

        }

2018年6月答案:

你必须确保消息中没有“通知”关键字。只包括“data”,应用程序将能够处理onmessagerreceived中的消息,即使在后台或已杀死。

使用云功能:

const message = {
    token: token_id,   // obtain device token id by querying data in firebase
    data: {
       title: "my_custom_title",
       body:  "my_custom_body_message"
       }
    }


return admin.messaging().send(message).then(response => {
    // handle response
});

然后在onmessagerreceived()中,在你的类中扩展com.google.firebase.messaging.FirebaseMessagingService:

if (data != null) {
  Log.d(TAG, "data title is: " + data.get("title");
  Log.d(TAG, "data body is: " + data.get("body");
}

// build notification using the body, title, and whatever else you want.

我也有同样的问题。经过一些挖掘为什么我的MainActivity被调用意图没有数据,我意识到我的发射器活动(如在Manifest)是SplashActivity。在那里我找到了消息数据,并将它们转发给MainActivity。效果很好。我相信这能帮助到一些人。

谢谢你的回答。