这是我的舱单:
<service android:name=".fcm.PshycoFirebaseMessagingServices">
<intent-filter>
<action android:name="com.google.firebase.MESSAGING_EVENT" />
</intent-filter>
</service>
<service android:name=".fcm.PshycoFirebaseInstanceIDService">
<intent-filter>
<action android:name="com.google.firebase.INSTANCE_ID_EVENT" />
</intent-filter>
</service>
当应用程序在后台和通知到达，然后默认通知来，不运行我的onmessagerreceived代码。
这是我的onMessageReceived代码。如果我的应用程序在前台运行，而不是在后台运行，就会调用这个函数。我怎么能运行这段代码时，应用程序是在后台太?
// [START receive_message]
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
// TODO(developer): Handle FCM messages here.
// If the application is in the foreground handle both data and notification messages here.
// Also if you intend on generating your own notifications as a result of a received FCM
// message, here is where that should be initiated. See sendNotification method below.
data = remoteMessage.getData();
String title = remoteMessage.getNotification().getTitle();
String message = remoteMessage.getNotification().getBody();
String imageUrl = (String) data.get("image");
String action = (String) data.get("action");
Log.i(TAG, "onMessageReceived: title : "+title);
Log.i(TAG, "onMessageReceived: message : "+message);
Log.i(TAG, "onMessageReceived: imageUrl : "+imageUrl);
Log.i(TAG, "onMessageReceived: action : "+action);
if (imageUrl == null) {
sendNotification(title,message,action);
} else {
new BigPictureNotification(this,title,message,imageUrl,action);
}
}
// [END receive_message]
我觉得所有的响应都是不完整的，但它们都有一些你需要处理的东西，当你的应用程序在后台时，一个有数据的通知。
遵循这些步骤，你将能够在应用程序处于后台时处理通知。
添加一个intent-filter，像这样:
<活动android: name = "。MainActivity”>
<意图过滤器>
<行动android: name = "。MainActivity " / >
<category android:name="android.intent.category. default " />
< /意图过滤器>
到要处理通知数据的活动。
以以下格式发送通知:
｛
“通知”:{
"click_action": "。MainActivity”,
"body": "new Symulti update !"，
"title": "新的Symulti更新!"，
"icon": "ic_notif_symulti"}，
"data":{…}，
"to": "c9Vaa3ReGdk:APA91bH-AuXgg3lDN2WMcBrNhJZoFtYF9"}
这里的关键是加法
"click_action" : ".MainActivity"
其中. mainactivity是您在步骤1中添加的带有intent-filter的活动。
从.MainActivity的onCreate中的通知中获取数据信息:
onCreate(Bundle savedInstanceState)
super.onCreate (savedInstanceState);
setContentView (R.layout.activity_main);
//获取通知数据信息
Bundle Bundle = getIntent().getExtras();
If (bundle != null) {
//bundle必须包含通知的"data"字段发送的所有信息
｝
｝
这就是你需要做的。
2018年6月答案:
你必须确保消息中没有“通知”关键字。只包括“data”，应用程序将能够处理onmessagerreceived中的消息，即使在后台或已杀死。
使用云功能:
const message = {
token: token_id, // obtain device token id by querying data in firebase
data: {
title: "my_custom_title",
body: "my_custom_body_message"
}
}
return admin.messaging().send(message).then(response => {
// handle response
});
然后在onmessagerreceived()中，在你的类中扩展com.google.firebase.messaging.FirebaseMessagingService:
if (data != null) {
Log.d(TAG, "data title is: " + data.get("title");
Log.d(TAG, "data body is: " + data.get("body");
}
// build notification using the body, title, and whatever else you want.
要在后台捕获消息，您需要使用BroadcastReceiver
import android.content.Context
import android.content.Intent
import android.util.Log
import androidx.legacy.content.WakefulBroadcastReceiver
import com.google.firebase.messaging.RemoteMessage
class FirebaseBroadcastReceiver : WakefulBroadcastReceiver() {
val TAG: String = FirebaseBroadcastReceiver::class.java.simpleName
override fun onReceive(context: Context, intent: Intent) {
val dataBundle = intent.extras
if (dataBundle != null)
for (key in dataBundle.keySet()) {
Log.d(TAG, "dataBundle: " + key + " : " + dataBundle.get(key))
}
val remoteMessage = RemoteMessage(dataBundle)
}
}
把这个加到你的舱单上
<receiver
android:name="MY_PACKAGE_NAME.FirebaseBroadcastReceiver"
android:exported="true"
android:permission="com.google.android.c2dm.permission.SEND">
<intent-filter>
<action android:name="com.google.android.c2dm.intent.RECEIVE" />
</intent-filter>
</receiver>
