这是我对这个问题的解决办法

const _ = require('lodash');

var objects = [{ 'x': 1, 'y': 2, 'z':3, a:{b:1, c:2, d:{n:0}}, p:[1, 2, 3]  }, { 'x': 2, 'y': 1, z:3, a:{b:2, c:2,d:{n:1}}, p:[1,3], m:3  }];

const diffFn=(a,b, path='')=>_.reduce(a, function(result, value, key) {

    if(_.isObjectLike(value)){
      if(_.isEqual(value, b[key])){
        return result;
      }else{

return result.concat(diffFn(value, b[key], path?(`${path}.${key}`):key))
      }
    }else{
return _.isEqual(value, b[key]) ?
        result : result.concat(path?(`${path}.${key}`):key);
    }
    
}, []);

const diffKeys1=diffFn(objects[0], objects[1])
const diffKeys2=diffFn(objects[1], objects[0])
const diffKeys=_.union(diffKeys1, diffKeys2)
const res={};

_.forEach(diffKeys, (key)=>_.assign(res, {[key]:{ old: _.get(objects[0], key), new:_.get(objects[1], key)} }))

res
/*
Returns
{
  x: { old: 1, new: 2 },
  y: { old: 2, new: 1 },
  'a.b': { old: 1, new: 2 },
  'a.d.n': { old: 0, new: 1 },
  'p.1': { old: 2, new: 3 },
  'p.2': { old: 3, new: undefined },
  m: { old: undefined, new: 3 }
}
*/

对于无意中发现这条线索的人，这里有一个更完整的解决方案。它将比较两个对象，并给出所有属性的键，这些属性要么只存在于object1中，要么只存在于object2中，要么同时存在于object1和object2中，但值不同:

/*
 * Compare two objects by reducing an array of keys in obj1, having the
 * keys in obj2 as the intial value of the result. Key points:
 *
 * - All keys of obj2 are initially in the result.
 *
 * - If the loop finds a key (from obj1, remember) not in obj2, it adds
 *   it to the result.
 *
 * - If the loop finds a key that are both in obj1 and obj2, it compares
 *   the value. If it's the same value, the key is removed from the result.
 */
function getObjectDiff(obj1, obj2) {
    const diff = Object.keys(obj1).reduce((result, key) => {
        if (!obj2.hasOwnProperty(key)) {
            result.push(key);
        } else if (_.isEqual(obj1[key], obj2[key])) {
            const resultKeyIndex = result.indexOf(key);
            result.splice(resultKeyIndex, 1);
        }
        return result;
    }, Object.keys(obj2));

    return diff;
}

下面是一个输出示例:

// Test
let obj1 = {
    a: 1,
    b: 2,
    c: { foo: 1, bar: 2},
    d: { baz: 1, bat: 2 }
}

let obj2 = {
    b: 2, 
    c: { foo: 1, bar: 'monkey'}, 
    d: { baz: 1, bat: 2 }
    e: 1
}
getObjectDiff(obj1, obj2)
// ["c", "e", "a"]

如果你不关心嵌套对象并且想要跳过lodash，你可以替换_。isEqual用于正常的值比较，例如obj1[key] === obj2[key]。

一个简单而优雅的解决方案是使用_。isEqual，它执行深度比较:

Var a = {}; Var b = {}; A.prop1 = 2; A.prop2 = {prop3: 2}; B.prop1 = 2; B.prop2 = {prop3: 3}; console.log(_。isEqual (a, b));//如果不同则返回false < script src = " https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js " > < /脚本>

然而，这个解决方案并没有显示哪个属性是不同的。

我知道这并不能直接回答OP的问题，但我是通过搜索如何删除lodash被引导到这里的。希望这能帮助到和我处境相似的人。

这要归功于@JohanPersson。我在这个答案的基础上实现了对深度嵌套值的比较，并获得对差异的键引用

getObjectDiff = (obj1, obj2) => { const obj1Props = Object.keys(obj1); const obj2Props = Object.keys(obj2); const keysWithDiffValue = obj1Props.reduce((keysWithDiffValueAccumulator, key) => { const propExistsOnObj2 = obj2.hasOwnProperty(key); const hasNestedValue = obj1[key] instanceof Object && obj2[key] instanceof Object; const keyValuePairBetweenBothObjectsIsEqual = obj1[key] === obj2[key]; if (!propExistsOnObj2) { keysWithDiffValueAccumulator.push(key); } else if (hasNestedValue) { const keyIndex = keysWithDiffValueAccumulator.indexOf(key); if (keyIndex >= 0) { keysWithDiffValueAccumulator.splice(keyIndex, 1); } const nestedDiffs = getObjectDiff(obj1[key], obj2[key]); for (let diff of nestedDiffs) { keysWithDiffValueAccumulator.push(`${key}.${diff}`); } } else if (keyValuePairBetweenBothObjectsIsEqual) { const equalValueKeyIndex = keysWithDiffValueAccumulator.indexOf(key); keysWithDiffValueAccumulator.splice(equalValueKeyIndex, 1); } return keysWithDiffValueAccumulator; }, obj2Props); return keysWithDiffValue; } const obj1 = {a0: {a1: {a2: {a3: 'Im here'}}}}; const obj2 = {a0: {a1: {a2: {a3: 'Not here', b3: 'some'}}}}; console.log('final', getObjectDiff(obj1, obj2));

我们需要在两个json更新之间获取delta，以跟踪数据库更新。也许其他人会觉得这很有用。

https://gist.github.com/jp6rt/7fcb6907e159d7851c8d59840b669e3d

const {
  isObject,
  isEqual,
  transform,
  has,
  merge,
} = require('lodash');
const assert = require('assert');

/**
 * Perform a symmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @param {*} invert  - Because this is a symmetric comparison. Some values in the with object
 *                      that doesn't exist on the base will be lost in translation.
 *                      You can execute again the function again with the parameters interchanged.
 *                      However you will lose the reference if the value is from the base or with
 *                      object if you intended to do an assymetric comparison.
 *                      Setting this to true will do make sure the reference is not lost.
 * @returns           - The returned object will label the result of the comparison with the
 *                      value from base and with object.
 */
const diffSym = (baseObj, withObj, invert = false) => transform(baseObj, (result, value, key) => {
  if (isEqual(value, withObj[key])
    && has(withObj, key)) {
    return;
  }

  if (isObject(value)
    && isObject(withObj[key])
    && !Array.isArray(value)) {
    result[key] = diffSym(value, withObj[key], invert);
    return;
  }

  if (!invert) {
    result[key] = {
      base: value,
      with: withObj[key],
    };
    return;
  }

  if (invert) {
    result[key] = {
      base: withObj[key],
      with: value,
    };
  }
});

/**
 * Perform a assymmetric comparison on JSON object.
 * @param {*} baseObj - The base object to be used for comparison against the withObj.
 * @param {*} withObj - The withObject parameter is used as the comparison on the base object.
 * @returns           - The returned object will label the values with
 *                      reference to the base and with object.
 */
const diffJSON = (baseObj, withObj) => {
  // Deep clone the objects so we don't update the reference objects.
  const baseObjClone = JSON.parse(JSON.stringify(baseObj));
  const withObjClone = JSON.parse(JSON.stringify(withObj));

  const beforeDelta = diffSym(baseObjClone, withObjClone);
  const afterDelta = diffSym(withObjClone, baseObjClone, true);

  return merge(afterDelta, beforeDelta);
};

// By Example:

const beforeDataObj = {
  a: 1,
  c: { d: 2, f: 3 },
  g: 4,
  h: 5,
};
const afterDataObj = {
  a: 2,
  b: 3,
  c: { d: 1, e: 1 },
  h: 5,
};

const delta = diffJSON(beforeDataObj, afterDataObj);

// Assert expected result.
assert(isEqual(delta, {
  a: { base: 1, with: 2 },
  b: { base: undefined, with: 3 },
  c: {
    d: { base: 2, with: 1 },
    e: { base: undefined, with: 1 },
    f: { base: 3, with: undefined },
  },
  g: { base: 4, with: undefined },
}));

我需要知道它们的某个嵌套属性是否不同

其他答案为这个问题提供了可能令人满意的解决方案，但它非常困难和常见，似乎有一个非常受欢迎的包来帮助解决这个问题。

要使用这个包，你需要npm i deep-object-diff，然后:

const { diff } = require('deep-object-diff');
var a = {};
var b = {};

a.prop1 = 2;
a.prop2 = { prop3: 2 };

b.prop1 = 2;
b.prop2 = { prop3: 3 };

if (!_.isEqual(a, b)) {
  const abDiff = diff(a, b);
  console.log(abDiff);
  /*
  {
    prop2: {
      prop3: 3
    }
  }
  */
}

// or alternatively
const abDiff = diff(a, b);
if(!_.isEmpty(abDiff)) {
  // if a diff exists then they aren't deeply equal
  // perform needed actions with diff...
}

下面是一个更详细的案例，直接从他们的文档中删除属性:

const lhs = {
  foo: {
    bar: {
      a: ['a', 'b'],
      b: 2,
      c: ['x', 'y'],
      e: 100 // deleted
    }
  },
  buzz: 'world'
};

const rhs = {
  foo: {
    bar: {
      a: ['a'], // index 1 ('b')  deleted
      b: 2, // unchanged
      c: ['x', 'y', 'z'], // 'z' added
      d: 'Hello, world!' // added
    }
  },
  buzz: 'fizz' // updated
};

console.log(diff(lhs, rhs)); // =>
/*
{
  foo: {
    bar: {
      a: {
        '1': undefined
      },
      c: {
        '2': 'z'
      },
      d: 'Hello, world!',
      e: undefined
    }
  },
  buzz: 'fizz'
}
*/

有关实现细节和其他使用信息，请参阅该repo。