一个简单而优雅的解决方案是使用_。isEqual，它执行深度比较:

Var a = {}; Var b = {}; A.prop1 = 2; A.prop2 = {prop3: 2}; B.prop1 = 2; B.prop2 = {prop3: 3}; console.log(_。isEqual (a, b));//如果不同则返回false < script src = " https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.4/lodash.min.js " > < /脚本>

然而，这个解决方案并没有显示哪个属性是不同的。

如果你只需要键比较:

 _.reduce(a, function(result, value, key) {
     return b[key] === undefined ? key : []
  }, []);

这段代码返回一个具有不同值的所有属性的对象，以及两个对象的值。对记录差异很有用。

var allkeys = _.union(_.keys(obj1), _.keys(obj2));
var difference = _.reduce(allkeys, function (result, key) {
  if ( !_.isEqual(obj1[key], obj2[key]) ) {
    result[key] = {obj1: obj1[key], obj2: obj2[key]}
  }
  return result;
}, {});

我尝试了Adam Boduch的代码来输出一个很深的差异-这完全没有经过测试，但碎片在那里:

function diff (obj1, obj2, path) {
    obj1 = obj1 || {};
    obj2 = obj2 || {};

    return _.reduce(obj1, function(result, value, key) {
        var p = path ? path + '.' + key : key;
        if (_.isObject(value)) {
            var d = diff(value, obj2[key], p);
            return d.length ? result.concat(d) : result;
        }
        return _.isEqual(value, obj2[key]) ? result : result.concat(p);
    }, []);
}

diff({ foo: 'lol', bar: { baz: true }}, {}) // returns ["foo", "bar.baz"]

As it was asked, here's a recursive object comparison function. And a bit more. Assuming that primary use of such function is object inspection, I have something to say. Complete deep comparison is a bad idea when some differences are irrelevant. For example, blind deep comparison in TDD assertions makes tests unnecessary brittle. For that reason, I'd like to introduce a much more valuable partial diff. It is a recursive analogue of a previous contribution to this thread. It ignores keys not present in a

var bdiff = (a, b) =>
    _.reduce(a, (res, val, key) =>
        res.concat((_.isPlainObject(val) || _.isArray(val)) && b
            ? bdiff(val, b[key]).map(x => key + '.' + x) 
            : (!b || val != b[key] ? [key] : [])),
        []);

BDiff允许检查期望值，同时容忍其他属性，这正是您想要的自动检查。这允许构建各种高级断言。例如:

var diff = bdiff(expected, actual);
// all expected properties match
console.assert(diff.length == 0, "Objects differ", diff, expected, actual);
// controlled inequality
console.assert(diff.length < 3, "Too many differences", diff, expected, actual);

回到完整的解决方案。使用bdiff构建一个完整的传统diff是很简单的:

function diff(a, b) {
    var u = bdiff(a, b), v = bdiff(b, a);
    return u.filter(x=>!v.includes(x)).map(x=>' < ' + x)
    .concat(u.filter(x=>v.includes(x)).map(x=>' | ' + x))
    .concat(v.filter(x=>!u.includes(x)).map(x=>' > ' + x));
};

在两个复杂对象上运行上述函数将输出类似于下面的内容:

 [
  " < components.0.components.1.components.1.isNew",
  " < components.0.cryptoKey",
  " | components.0.components.2.components.2.components.2.FFT.min",
  " | components.0.components.2.components.2.components.2.FFT.max",
  " > components.0.components.1.components.1.merkleTree",
  " > components.0.components.2.components.2.components.2.merkleTree",
  " > components.0.components.3.FFTResult"
 ]

最后，为了了解值之间的差异，我们可能需要直接eval() diff输出。为此，我们需要一个更丑的bdiff版本，输出语法正确的路径:

// provides syntactically correct output
var bdiff = (a, b) =>
    _.reduce(a, (res, val, key) =>
        res.concat((_.isPlainObject(val) || _.isArray(val)) && b
            ? bdiff(val, b[key]).map(x => 
                key + (key.trim ? '':']') + (x.search(/^\d/)? '.':'[') + x)
            : (!b || val != b[key] ? [key + (key.trim ? '':']')] : [])),
        []);

// now we can eval output of the diff fuction that we left unchanged
diff(a, b).filter(x=>x[1] == '|').map(x=>[x].concat([a, b].map(y=>((z) =>eval('z.' + x.substr(3))).call(this, y)))));

这将输出类似于下面的内容:

[" | components[0].components[2].components[2].components[2].FFT.min", 0, 3]
[" | components[0].components[2].components[2].components[2].FFT.max", 100, 50]

“一族”许可

下面是一个使用Lodash的简单解决方案:

_.differenceWith(a, b, _.isEqual);

注意，两个输入都需要是数组(可能是一个对象的数组)。