要递归地显示一个对象与其他对象的不同之处，可以使用_。Reduce与_结合。isEqual和_.isPlainObject。在这种情况下，你可以比较a与b的不同，或者b与a的不同:

const objectA = { a: { 1: "SAME WILL BE MISSING IN RESULT", 2: "BBB", 3: [1, 2, 3] }, b: "not", c: "foo bar" }; const objectB = { a: { 1: "SAME WILL BE MISSING IN RESULT", 2: [1, 2] }, b: "foo", c: "bar" }; const diff = function(obj1, obj2) { return _.reduce(obj1, function(result, value, key) { if (_.isPlainObject(value)) { result[key] = diff(value, obj2[key]); } else if (!_.isEqual(value, obj2[key])) { result[key] = value; } return result; }, {}); }; const diffAOverB = diff(objectA, objectB); const diffBOverA = diff(objectA, objectB); console.log(diffAOverB); console.log(diffBOverA); <script src="https://cdn.jsdelivr.net/npm/lodash@4.17.4/lodash.min.js"></script>

简单使用_。isEqual方法，它将适用于所有比较…

注意:此方法支持比较数组、数组缓冲区、 布尔值、 *日期对象，错误对象，地图，数字，对象对象，正则表达式， *集合、字符串、符号和类型化数组。对象对象进行比较 *通过自身的，不可继承的，可枚举的属性。函数和DOM *节点不支持。

所以如果你有以下情况:

 const firstName = {name: "Alireza"};
 const otherName = {name: "Alireza"};

如果是:_。isEqual (firstName, otherName);

它会返回true

如果const fullName = {firstName: "Alireza"， familyName: "Dezfoolian"};

如果是:_。isEqual (firstName, fullName);

将返回false

As it was asked, here's a recursive object comparison function. And a bit more. Assuming that primary use of such function is object inspection, I have something to say. Complete deep comparison is a bad idea when some differences are irrelevant. For example, blind deep comparison in TDD assertions makes tests unnecessary brittle. For that reason, I'd like to introduce a much more valuable partial diff. It is a recursive analogue of a previous contribution to this thread. It ignores keys not present in a

var bdiff = (a, b) =>
    _.reduce(a, (res, val, key) =>
        res.concat((_.isPlainObject(val) || _.isArray(val)) && b
            ? bdiff(val, b[key]).map(x => key + '.' + x) 
            : (!b || val != b[key] ? [key] : [])),
        []);

BDiff允许检查期望值，同时容忍其他属性，这正是您想要的自动检查。这允许构建各种高级断言。例如:

var diff = bdiff(expected, actual);
// all expected properties match
console.assert(diff.length == 0, "Objects differ", diff, expected, actual);
// controlled inequality
console.assert(diff.length < 3, "Too many differences", diff, expected, actual);

回到完整的解决方案。使用bdiff构建一个完整的传统diff是很简单的:

function diff(a, b) {
    var u = bdiff(a, b), v = bdiff(b, a);
    return u.filter(x=>!v.includes(x)).map(x=>' < ' + x)
    .concat(u.filter(x=>v.includes(x)).map(x=>' | ' + x))
    .concat(v.filter(x=>!u.includes(x)).map(x=>' > ' + x));
};

在两个复杂对象上运行上述函数将输出类似于下面的内容:

 [
  " < components.0.components.1.components.1.isNew",
  " < components.0.cryptoKey",
  " | components.0.components.2.components.2.components.2.FFT.min",
  " | components.0.components.2.components.2.components.2.FFT.max",
  " > components.0.components.1.components.1.merkleTree",
  " > components.0.components.2.components.2.components.2.merkleTree",
  " > components.0.components.3.FFTResult"
 ]

最后，为了了解值之间的差异，我们可能需要直接eval() diff输出。为此，我们需要一个更丑的bdiff版本，输出语法正确的路径:

// provides syntactically correct output
var bdiff = (a, b) =>
    _.reduce(a, (res, val, key) =>
        res.concat((_.isPlainObject(val) || _.isArray(val)) && b
            ? bdiff(val, b[key]).map(x => 
                key + (key.trim ? '':']') + (x.search(/^\d/)? '.':'[') + x)
            : (!b || val != b[key] ? [key + (key.trim ? '':']')] : [])),
        []);

// now we can eval output of the diff fuction that we left unchanged
diff(a, b).filter(x=>x[1] == '|').map(x=>[x].concat([a, b].map(y=>((z) =>eval('z.' + x.substr(3))).call(this, y)))));

这将输出类似于下面的内容:

[" | components[0].components[2].components[2].components[2].FFT.min", 0, 3]
[" | components[0].components[2].components[2].components[2].FFT.max", 100, 50]

“一族”许可

以Sridhar Gudimela的回答为基础，下面以一种使用TypeScript的方式进行了更新:

///  U T I L S

interface LooseObjectInterface {
  [key: string]: any;
};

type inputOptions = LooseObjectInterface | any[];



///  E X P O R T

export const objectCompare = (objectA: inputOptions, objectB: inputOptions): LooseObjectInterface => {
  let diffObj: LooseObjectInterface = {};

  switch(true) {
    case (Array.isArray(objectA)):
      objectA.forEach((elem: any, index: number) => {
        if (!Array.isArray(diffObj))
          diffObj = [];

        diffObj[index] = objectCompare(elem, (objectB || [])[index]);
      });

      break;

    case (objectA !== null && typeof objectA === "object"):
      Object.keys(objectA).forEach((key: any) => {
        if (Array.isArray(objectA[key])) {
          let arr = objectCompare(objectA[key], objectB[key]);

          if (!Array.isArray(arr))
            arr = [];

          arr.forEach((elem: any, index: number) => {
            if (!Array.isArray(diffObj[key]))
              diffObj[key] = [];

            diffObj[key][index] = elem;
          });
        } else if (typeof objectA[key] === "object")
          diffObj[key] = objectCompare(objectA[key], objectB[key]);
        else if (objectA[key] !== (objectB || {})[key])
          diffObj[key] = objectA[key];
        else if (objectA[key] === (objectB || {})[key])
          delete objectA[key];
      });

      break;

    default:
      break;
  }

  Object.keys(diffObj).forEach((key: any) => {
    if (typeof diffObj[key] === "object" && JSON.stringify(diffObj[key]) === "{}")
      delete diffObj[key];
  });

  return diffObj;
};

编辑:我最初的回答使用了Flow，因此被否决了(我猜，或者可能是因为我的回答没有使用Lodash……)然而，有一个类似问题的答案也无妨)。

作为对亚当·博杜赫的回答的补充，这个问题考虑到了性质的差异

const differenceOfKeys = (...objects) =>
  _.difference(...objects.map(obj => Object.keys(obj)));
const differenceObj = (a, b) => 
  _.reduce(a, (result, value, key) => (
    _.isEqual(value, b[key]) ? result : [...result, key]
  ), differenceOfKeys(b, a));

对于无意中发现这条线索的人，这里有一个更完整的解决方案。它将比较两个对象，并给出所有属性的键，这些属性要么只存在于object1中，要么只存在于object2中，要么同时存在于object1和object2中，但值不同:

/*
 * Compare two objects by reducing an array of keys in obj1, having the
 * keys in obj2 as the intial value of the result. Key points:
 *
 * - All keys of obj2 are initially in the result.
 *
 * - If the loop finds a key (from obj1, remember) not in obj2, it adds
 *   it to the result.
 *
 * - If the loop finds a key that are both in obj1 and obj2, it compares
 *   the value. If it's the same value, the key is removed from the result.
 */
function getObjectDiff(obj1, obj2) {
    const diff = Object.keys(obj1).reduce((result, key) => {
        if (!obj2.hasOwnProperty(key)) {
            result.push(key);
        } else if (_.isEqual(obj1[key], obj2[key])) {
            const resultKeyIndex = result.indexOf(key);
            result.splice(resultKeyIndex, 1);
        }
        return result;
    }, Object.keys(obj2));

    return diff;
}

下面是一个输出示例:

// Test
let obj1 = {
    a: 1,
    b: 2,
    c: { foo: 1, bar: 2},
    d: { baz: 1, bat: 2 }
}

let obj2 = {
    b: 2, 
    c: { foo: 1, bar: 'monkey'}, 
    d: { baz: 1, bat: 2 }
    e: 1
}
getObjectDiff(obj1, obj2)
// ["c", "e", "a"]

如果你不关心嵌套对象并且想要跳过lodash，你可以替换_。isEqual用于正常的值比较，例如obj1[key] === obj2[key]。