我有相当多的控件分散在我的表格中的许多表格单元格中,我想知道是否有一种更简单的方法来消除键盘,而不必循环遍历所有的控件并将它们全部辞职为第一响应器。我想问题是…我如何得到当前的第一个响应器的键盘?


当前回答

用swift:

self.view.endEditing(true)

其他回答

@Nicholas Riley &@Kendall Helmstetter Geln & @cannyboy:

绝对的辉煌!

谢谢你!

考虑到你和其他人在这篇文章中的建议,以下是我所做的:

使用时的样子:

[[self appDelegate]解聘键盘];(注意:我添加了appDelegate作为NSObject的补充,所以我可以在任何地方使用任何东西)

引擎盖下的样子:

- (void)dismissKeyboard 
{
    UITextField *tempTextField = [[[UITextField alloc] initWithFrame:CGRectZero] autorelease];
    tempTextField.enabled = NO;
    [myRootViewController.view addSubview:tempTextField];
    [tempTextField becomeFirstResponder];
    [tempTextField resignFirstResponder];
    [tempTextField removeFromSuperview];
}

EDIT

修正我的回答包括tempTextField。enabled = NO;。禁用文本字段将阻止UIKeyboardWillShowNotification和UIKeyboardWillHideNotification键盘通知发送,如果你在整个应用程序中依赖这些通知。

你必须使用其中一种方法,

[self.view endEditing:YES];

or

[self.textField resignFirstResponder];

老实说,我对这里提出的任何解决方案都不感兴趣。我确实发现了一种使用TapGestureRecognizer的好方法,我认为它解决了问题的核心:当你点击键盘以外的任何东西时,忽略键盘。

In viewDidLoad, register to receive keyboard notifications and create a UITapGestureRecognizer: NSNotificationCenter *nc = [NSNotificationCenter defaultCenter]; [nc addObserver:self selector:@selector(keyboardWillShow:) name: UIKeyboardWillShowNotification object:nil]; [nc addObserver:self selector:@selector(keyboardWillHide:) name: UIKeyboardWillHideNotification object:nil]; tapRecognizer = [[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(didTapAnywhere:)]; Add the keyboard show/hide responders. There you add and remove the TapGestureRecognizer to the UIView that should dismiss the keyboard when tapped. Note: You do not have to add it to all of the sub-views or controls. -(void) keyboardWillShow:(NSNotification *) note { [self.view addGestureRecognizer:tapRecognizer]; } -(void) keyboardWillHide:(NSNotification *) note { [self.view removeGestureRecognizer:tapRecognizer]; } The TapGestureRecognizer will call your function when it gets a tap and you can dismiss the keyboard like this: -(void)didTapAnywhere: (UITapGestureRecognizer*) recognizer { [textField resignFirstResponder]; }

这个解决方案的优点是它只过滤轻敲,而不是滑动。因此,如果你在键盘上方有滚动内容,滑动仍然会滚动并显示键盘。通过在键盘消失后移除手势识别器,未来在视图上的点击将被正常处理。

子类化你的文本字段…还有textviews

在子类中放入此代码..

-(void)conformsToKeyboardDismissNotification{

    [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(dismissKeyBoard) name:KEYBOARD_DISMISS object:nil];
}

-(void)deConformsToKeyboardDismissNotification{

    [[NSNotificationCenter defaultCenter] removeObserver:self name:KEYBOARD_DISMISS object:nil];
}

- (void)dealloc{
    [[NSNotificationCenter defaultCenter] removeObserver:self];
    [self resignFirstResponder];
}

在textfield委托中(类似于textview委托)

-(void)textFieldDidBeginEditing:(JCPTextField *)textField{
     [textField conformsToKeyboardDismissNotification];
}


- (void)textFieldDidEndEditing:(JCPTextField *)textField{
    [textField deConformsToKeyboardDismissNotification];
}

都准备好了. .现在只需从代码中的任何地方发布通知。它将放弃任何键盘。

我讨厌没有“全局”的方法在不使用私有API调用的情况下以编程方式取消键盘。我经常需要在不知道哪个对象是第一个响应器的情况下以编程方式关闭键盘。我使用Objective-C运行时API检查self,枚举它的所有属性,取出那些类型为UITextField的属性,并将resignFirstResponder消息发送给它们。

做这件事不应该这么难…