使用你的界面就可以做到

class Modal() {
  constructor(public iModal: IModal) {
   //You now have access to all your interface variables using this.iModal object,
   //you don't need to define the properties at all, constructor does it for you.
  }
}

如果你在其他地方创建了“modal”变量，并想告诉TypeScript它将全部完成，你可以使用:

declare const modal: IModal;

如果你想创建一个实际上是TypeScript中IModal实例的变量，你需要完整地定义它。

const modal: IModal = {
    content: '',
    form: '',
    href: '',
    $form: null,
    $message: null,
    $modal: null,
    $submits: null
};

或者撒谎，使用类型断言，但是你会失去类型安全，因为你现在会在意想不到的地方得到未定义，并且可能在访问modal时出现运行时错误。内容等(合同规定的属性)。

const modal = {} as IModal;

示例类

class Modal implements IModal {
    content: string;
    form: string;
    href: string;
    $form: JQuery;
    $message: JQuery;
    $modal: JQuery;
    $submits: JQuery;
}

const modal = new Modal();

你可能会想“嘿，这真的是一个重复的界面”-你是正确的。如果Modal类是IModal接口的唯一实现，你可能想要删除整个接口并使用…

const modal: Modal = new Modal();

而不是

const modal: IModal = new Modal();

如果你正在使用React，解析器会被传统的强制转换语法阻塞，所以在.tsx文件中引入了一种替代方法

let a = {} as MyInterface;

https://www.typescriptlang.org/docs/handbook/jsx.html

实际上，创建对象并不需要类。你可以直接这样做:

interface IModal {
    content: string;
    form: string;
}

onButtonSaveClick() {
    let myModalClass: IModal = {
        content: 'foo content',
        form: 'foo form'
    }
}

该界面有5种使用方式。

 interface IStudent {
          Id: number;
          name: string;
        }
        
        
        Method 1. all fields must assign data.
         const  obj1: IStudent = { Id: 1, name: 'Naveed' };  
        
        Method 2. my favorite one
        const obj2 = { name: 'Naveed' } as IStudent ;
        
        Method 3.
        const obj3 = <IStudent >{name: 'Naveed'}; 
        
        Method 4. use partial interface if all fields not required.
        const  obj4: Partial<IStudent > = { name: 'Naveed' };  
        
        Method 5. use ? Mark with interface fields if all fields not required.
        const  obj5: IStudent = {  name: 'Naveed' };  

下面是另一种方法:

你可以像这样简单地创建一个ESLint友好的对象

const modal: IModal = {} as IModal;

或者基于接口的默认实例，如果有默认值的话

const defaultModal: IModal = {
    content: "",
    form: "",
    href: "",
    $form: {} as JQuery,
    $message: {} as JQuery,
    $modal: {} as JQuery,
    $submits: {} as JQuery
};

然后通过重写一些属性来改变默认实例

const confirmationModal: IModal = {
    ...defaultModal,     // all properties/values from defaultModal
    form: "confirmForm"  // override form only
}