我已经定义了一个这样的接口:
interface IModal {
content: string;
form: string;
href: string;
$form: JQuery;
$message: JQuery;
$modal: JQuery;
$submits: JQuery;
}
我这样定义一个变量:
var modal: IModal;
然而，当我尝试设置modal属性时，它会给我一个消息说
"cannot set property content of undefined"
是否可以使用接口来描述我的模态对象，如果是这样，我应该如何创建它?
当前回答
下面是另一种方法:
你可以像这样简单地创建一个ESLint友好的对象
const modal: IModal = {} as IModal;
或者基于接口的默认实例，如果有默认值的话
const defaultModal: IModal = {
content: "",
form: "",
href: "",
$form: {} as JQuery,
$message: {} as JQuery,
$modal: {} as JQuery,
$submits: {} as JQuery
};
然后通过重写一些属性来改变默认实例
const confirmationModal: IModal = {
...defaultModal, // all properties/values from defaultModal
form: "confirmForm" // override form only
}
其他回答
实际上，创建对象并不需要类。你可以直接这样做:
interface IModal {
content: string;
form: string;
}
onButtonSaveClick() {
let myModalClass: IModal = {
content: 'foo content',
form: 'foo form'
}
}
这里是我经常使用的另一个解决方案。但是我不确定这是否是好的做法，如果不是，请在下面评论。
/// Interface
export default interface BookInterface {
title: string,
author: string,
id: any
}
/// Creating Class
export class BookClass implements BookInterface {
title: string;
author: string;
id: any;
constructor(title: string, author: string, id: any) {
this.title = title;
this.author = author;
this.id = id;
}
}
/// How to use it
let book: BookInterface = new BookClass(title, author, id);
谢谢:)
let deletedQuestionsDto = { examId: this.examId, questionId: q.id } as DeletedQuestionsDto;
下面是另一种方法:
你可以像这样简单地创建一个ESLint友好的对象
const modal: IModal = {} as IModal;
或者基于接口的默认实例，如果有默认值的话
const defaultModal: IModal = {
content: "",
form: "",
href: "",
$form: {} as JQuery,
$message: {} as JQuery,
$modal: {} as JQuery,
$submits: {} as JQuery
};
然后通过重写一些属性来改变默认实例
const confirmationModal: IModal = {
...defaultModal, // all properties/values from defaultModal
form: "confirmForm" // override form only
}
使用你的界面就可以做到
class Modal() {
constructor(public iModal: IModal) {
//You now have access to all your interface variables using this.iModal object,
//you don't need to define the properties at all, constructor does it for you.
}
}
