我知道有大量的$_SERVER变量头可用于IP地址检索。我想知道是否有一个普遍的共识,如何最准确地检索用户的真实IP地址(好知道没有方法是完美的)使用上述变量?

我花了一些时间试图找到一个深入的解决方案,并根据一些来源提出了以下代码。如果有人能在答案中找出漏洞,或者提供一些更准确的信息,我会很高兴。

edit包含来自@Alix的优化

 /**
  * Retrieves the best guess of the client's actual IP address.
  * Takes into account numerous HTTP proxy headers due to variations
  * in how different ISPs handle IP addresses in headers between hops.
  */
 public function get_ip_address() {
  // Check for shared internet/ISP IP
  if (!empty($_SERVER['HTTP_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_CLIENT_IP']))
   return $_SERVER['HTTP_CLIENT_IP'];

  // Check for IPs passing through proxies
  if (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) {
   // Check if multiple IP addresses exist in var
    $iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
    foreach ($iplist as $ip) {
     if ($this->validate_ip($ip))
      return $ip;
    }
   }
  }
  if (!empty($_SERVER['HTTP_X_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_X_FORWARDED']))
   return $_SERVER['HTTP_X_FORWARDED'];
  if (!empty($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']) && $this->validate_ip($_SERVER['HTTP_X_CLUSTER_CLIENT_IP']))
   return $_SERVER['HTTP_X_CLUSTER_CLIENT_IP'];
  if (!empty($_SERVER['HTTP_FORWARDED_FOR']) && $this->validate_ip($_SERVER['HTTP_FORWARDED_FOR']))
   return $_SERVER['HTTP_FORWARDED_FOR'];
  if (!empty($_SERVER['HTTP_FORWARDED']) && $this->validate_ip($_SERVER['HTTP_FORWARDED']))
   return $_SERVER['HTTP_FORWARDED'];

  // Return unreliable IP address since all else failed
  return $_SERVER['REMOTE_ADDR'];
 }

 /**
  * Ensures an IP address is both a valid IP address and does not fall within
  * a private network range.
  *
  * @access public
  * @param string $ip
  */
 public function validate_ip($ip) {
     if (filter_var($ip, FILTER_VALIDATE_IP, 
                         FILTER_FLAG_IPV4 | 
                         FILTER_FLAG_IPV6 |
                         FILTER_FLAG_NO_PRIV_RANGE | 
                         FILTER_FLAG_NO_RES_RANGE) === false)
         return false;
     self::$ip = $ip;
     return true;
 }

警告之词(更新)

REMOTE_ADDR仍然表示最可靠的IP地址来源。这里提到的其他$_SERVER变量很容易被远程客户端欺骗。此解决方案的目的是试图确定位于代理后面的客户机的IP地址。出于一般目的,您可以考虑将其与直接从$_SERVER['REMOTE_ADDR']返回的IP地址结合使用,并存储两者。

对于99.9%的用户,这个解决方案将完美地满足您的需求。它不能保护您免受0.1%的恶意用户通过注入他们自己的请求头来滥用您的系统。如果某些关键任务依赖于IP地址,请使用REMOTE_ADDR,而不必费心满足代理背后的需求。


当前回答

我想知道也许你应该在爆炸的HTTP_X_FORWARDED_FOR以相反的顺序迭代,因为我的经验是,用户的IP地址结束在逗号分隔的列表的末尾,所以从头的开始,你更有可能得到一个返回的代理的IP地址,这可能仍然允许会话劫持,因为许多用户可能通过该代理。

其他回答

谢谢,非常有用。

如果代码在语法上是正确的,这将会有所帮助。在第20行有一个{too many。这恐怕意味着没人真正尝试过。

我可能疯了,但在尝试了一些有效和无效的地址后,validate_ip()唯一有效的版本是这样的:

    public function validate_ip($ip)
    {
        if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE) === false)
            return false;
        if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_RES_RANGE) === false)
            return false;
        if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_IPV4) === false && filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_IPV6) === false)
            return false;

        return true;
    }
/**
 * Sanitizes IPv4 address according to Ilia Alshanetsky's book
 * "php|architect?s Guide to PHP Security", chapter 2, page 67.
 *
 * @param string $ip An IPv4 address
 */
public static function sanitizeIpAddress($ip = '')
{
if ($ip == '')
    {
    $rtnStr = '0.0.0.0';
    }
else
    {
    $rtnStr = long2ip(ip2long($ip));
    }

return $rtnStr;
}

//---------------------------------------------------

/**
 * Returns the sanitized HTTP_X_FORWARDED_FOR server variable.
 *
 */
public static function getXForwardedFor()
{
if (isset($_SERVER['HTTP_X_FORWARDED_FOR']))
    {
    $rtnStr = $_SERVER['HTTP_X_FORWARDED_FOR'];
    }
elseif (isset($HTTP_SERVER_VARS['HTTP_X_FORWARDED_FOR']))
    {
    $rtnStr = $HTTP_SERVER_VARS['HTTP_X_FORWARDED_FOR'];
    }
elseif (getenv('HTTP_X_FORWARDED_FOR'))
    {
    $rtnStr = getenv('HTTP_X_FORWARDED_FOR');
    }
else
    {
    $rtnStr = '';
    }

// Sanitize IPv4 address (Ilia Alshanetsky):
if ($rtnStr != '')
    {
    $rtnStr = explode(', ', $rtnStr);
    $rtnStr = self::sanitizeIpAddress($rtnStr[0]);
    }

return $rtnStr;
}

//---------------------------------------------------

/**
 * Returns the sanitized REMOTE_ADDR server variable.
 *
 */
public static function getRemoteAddr()
{
if (isset($_SERVER['REMOTE_ADDR']))
    {
    $rtnStr = $_SERVER['REMOTE_ADDR'];
    }
elseif (isset($HTTP_SERVER_VARS['REMOTE_ADDR']))
    {
    $rtnStr = $HTTP_SERVER_VARS['REMOTE_ADDR'];
    }
elseif (getenv('REMOTE_ADDR'))
    {
    $rtnStr = getenv('REMOTE_ADDR');
    }
else
    {
    $rtnStr = '';
    }

// Sanitize IPv4 address (Ilia Alshanetsky):
if ($rtnStr != '')
    {
    $rtnStr = explode(', ', $rtnStr);
    $rtnStr = self::sanitizeIpAddress($rtnStr[0]);
    }

return $rtnStr;
}

//---------------------------------------------------

/**
 * Returns the sanitized remote user and proxy IP addresses.
 *
 */
public static function getIpAndProxy()
{
$xForwarded = self::getXForwardedFor();
$remoteAddr = self::getRemoteAddr();

if ($xForwarded != '')
    {
    $ip    = $xForwarded;
    $proxy = $remoteAddr;
    }
else
    {
    $ip    = $remoteAddr;
    $proxy = '';
    }

return array($ip, $proxy);
}

下面是一种更简洁的获取IP地址的方法:

function get_ip_address(){
    foreach (array('HTTP_CLIENT_IP', 'HTTP_X_FORWARDED_FOR', 'HTTP_X_FORWARDED', 'HTTP_X_CLUSTER_CLIENT_IP', 'HTTP_FORWARDED_FOR', 'HTTP_FORWARDED', 'REMOTE_ADDR') as $key){
        if (array_key_exists($key, $_SERVER) === true){
            foreach (explode(',', $_SERVER[$key]) as $ip){
                $ip = trim($ip); // just to be safe

                if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE) !== false){
                    return $ip;
                }
            }
        }
    }
}

你的代码似乎已经很完整了,我看不到任何可能的错误(除了通常的IP警告),我会改变validate_ip()函数依赖于过滤器扩展:

public function validate_ip($ip)
{
    if (filter_var($ip, FILTER_VALIDATE_IP, FILTER_FLAG_NO_PRIV_RANGE | FILTER_FLAG_NO_RES_RANGE) === false)
    {
        return false;
    }

    self::$ip = sprintf('%u', ip2long($ip)); // you seem to want this

    return true;
}

你的HTTP_X_FORWARDED_FOR代码片段也可以这样简化:

// check for IPs passing through proxies
if (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))
{
    // check if multiple ips exist in var
    if (strpos($_SERVER['HTTP_X_FORWARDED_FOR'], ',') !== false)
    {
        $iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
        
        foreach ($iplist as $ip)
        {
            if ($this->validate_ip($ip))
                return $ip;
        }
    }
    
    else
    {
        if ($this->validate_ip($_SERVER['HTTP_X_FORWARDED_FOR']))
            return $_SERVER['HTTP_X_FORWARDED_FOR'];
    }
}

:

// check for IPs passing through proxies
if (!empty($_SERVER['HTTP_X_FORWARDED_FOR']))
{
    $iplist = explode(',', $_SERVER['HTTP_X_FORWARDED_FOR']);
        
    foreach ($iplist as $ip)
    {
        if ($this->validate_ip($ip))
            return $ip;
    }
}

您可能还想验证IPv6地址。

如果你使用CloudFlare缓存层服务,下面是修改后的版本

function getIP()
{
    $fields = array('HTTP_X_FORWARDED_FOR',
                    'REMOTE_ADDR',
                    'HTTP_CF_CONNECTING_IP',
                    'HTTP_X_CLUSTER_CLIENT_IP');

    foreach($fields as $f)
    {
        $tries = $_SERVER[$f];
        if (empty($tries))
            continue;
        $tries = explode(',',$tries);
        foreach($tries as $try)
        {
            $r = filter_var($try,
                            FILTER_VALIDATE_IP, FILTER_FLAG_IPV4 |
                            FILTER_FLAG_NO_PRIV_RANGE |
                            FILTER_FLAG_NO_RES_RANGE);

            if ($r !== false)
            {
                return $try;
            }
        }
    }
    return false;
}

我知道现在回答已经太晚了。但是你可以试试这些方法:

选项1:(使用curl)

$ch = curl_init();

// set URL and other appropriate options
curl_setopt($ch, CURLOPT_URL, "https://ifconfig.me/");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);

// grab URL and pass it to the browser
$ip = curl_exec($ch);

// close cURL resource, and free up system resources
curl_close($ch);

return $ip;

选项2:(适用于mac)

return trim(shell_exec("dig +short myip.opendns.com @resolver1.opendns.com"));

选项3:(只是使用了一个技巧)

return str_replace('Current IP CheckCurrent IP Address: ', '', strip_tags(file_get_contents('http://checkip.dyndns.com')));

可以作为参考: https://www.tecmint.com/find-linux-server-public-ip-address/