它需要放在一个不同的线程中，允许UI在线程函数执行完成后立即更新:

现代迅速:

DispatchQueue.main.async {
    // Update UI
}

旧版本的Swift，在Swift 3之前。

dispatch_async(dispatch_get_main_queue(){
    // code here
})

objective - c:

dispatch_async(dispatch_get_main_queue(), ^{
    // code here
});

在不使用'dispatch_async'的情况下调试print语句时会得到类似的错误消息 因此，当您得到错误消息时，就可以使用了

斯威夫特4

DispatchQueue.main.async { //code }

斯威夫特3

DispatchQueue.main.async(){ //code }

早期的Swift版本

dispatch_async(dispatch_get_main_queue()){ //code }

我在使用TouchID时遇到了这个问题，如果这对其他人有帮助，包装你的成功逻辑，它可能在主队列中对UI有作用。

你不能在主线程中越位修改UI !UIKit不是线程安全的，所以如果你这样做，上面的问题和其他一些奇怪的问题会出现。应用程序甚至会崩溃。

所以，要做UIKit操作，你需要定义block并让它在主队列上执行:例如，

NSOperationQueue.mainQueue().addOperationWithBlock {

}

You already have the correct code answer from @Mark but, just to share my findings: The issue is that you are requesting a change in the view and assuming that it will happen instantly. In reality, the loading of a view depends on the available resources. If everything loads quickly enough and there are no delays then you don't notice anything. In scenarios, where there is any delay due to the process thread being busy etc, the application runs into a situation where it is supposed to display something even though its not ready yet. Hence, it is advisable to dispatch these requests in a asynchronous queues so, they get executed based on the load.

对我来说，问题是这样的。 确保在主线程上执行performSegueWithIdentifier::

dispatch_async (dispatch_get_main_queue(), ^{
  [self performSegueWithIdentifier:@"ViewController" sender:nil];
});