我有几个方法返回不同的泛型列表。
在。net中存在任何类静态方法或将任何列表转换为数据表?我唯一能想到的是使用反射来做到这一点。
如果我有这个:
List<Whatever> whatever = new List<Whatever>();
(这下代码当然不工作,但我想有这样的可能性:
DataTable dt = (DataTable) whatever;
我有几个方法返回不同的泛型列表。
在。net中存在任何类静态方法或将任何列表转换为数据表?我唯一能想到的是使用反射来做到这一点。
如果我有这个:
List<Whatever> whatever = new List<Whatever>();
(这下代码当然不工作,但我想有这样的可能性:
DataTable dt = (DataTable) whatever;
当前回答
2019年的答案,如果你正在使用。net Core——使用Nuget ToDataTable库。优点:
性能优于FastMember 还可以创建结构化的SqlParameters作为SQL Server表值参数
免责声明-我是ToDataTable的作者
性能——我扩展了一些Benchmark . net测试,并将它们包含在ToDataTable repo中。结果如下:
创建100,000行数据表:
MacOS Windows
Reflection 818.5 ms 818.3 ms
FastMember from 1105.5 ms 976.4 ms
Mark's answer
Improved FastMember 524.6 ms 456.4 ms
ToDataTable 449.0 ms 376.5 ms
Marc回答中建议的FastMember方法的性能似乎比Mary使用反射的回答差,但我使用FastMember TypeAccessor滚动了另一个方法,它的性能要好得多。尽管如此,ToDataTable包的性能还是优于其他包。
其他回答
这是清单上的另一个。Cinchoo ETL -一个将枚举转换为数据表的开源库。
List<Whatever> whatever = new List<Whatever>();
var dt = whatever.AsDataTable();
免责声明:我是这个库的作者。
这是一个简单的控制台应用程序,用于将列表转换为数据表。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.ComponentModel;
namespace ConvertListToDataTable
{
public static class Program
{
public static void Main(string[] args)
{
List<MyObject> list = new List<MyObject>();
for (int i = 0; i < 5; i++)
{
list.Add(new MyObject { Sno = i, Name = i.ToString() + "-KarthiK", Dat = DateTime.Now.AddSeconds(i) });
}
DataTable dt = ConvertListToDataTable(list);
foreach (DataRow row in dt.Rows)
{
Console.WriteLine();
for (int x = 0; x < dt.Columns.Count; x++)
{
Console.Write(row[x].ToString() + " ");
}
}
Console.ReadLine();
}
public class MyObject
{
public int Sno { get; set; }
public string Name { get; set; }
public DateTime Dat { get; set; }
}
public static DataTable ConvertListToDataTable<T>(this List<T> iList)
{
DataTable dataTable = new DataTable();
PropertyDescriptorCollection props = TypeDescriptor.GetProperties(typeof(T));
for (int i = 0; i < props.Count; i++)
{
PropertyDescriptor propertyDescriptor = props[i];
Type type = propertyDescriptor.PropertyType;
if (type.IsGenericType && type.GetGenericTypeDefinition() == typeof(Nullable<>))
type = Nullable.GetUnderlyingType(type);
dataTable.Columns.Add(propertyDescriptor.Name, type);
}
object[] values = new object[props.Count];
foreach (T iListItem in iList)
{
for (int i = 0; i < values.Length; i++)
{
values[i] = props[i].GetValue(iListItem);
}
dataTable.Rows.Add(values);
}
return dataTable;
}
}
}
如果你想使用反射并设置列的顺序/只包括一些列/排除一些列,试试这个:
private static DataTable ConvertToDataTable<T>(IList<T> data, string[] fieldsToInclude = null,
string[] fieldsToExclude = null)
{
PropertyDescriptorCollection properties = TypeDescriptor.GetProperties(typeof(T));
DataTable table = new DataTable();
foreach (PropertyDescriptor prop in properties)
{
if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
continue;
table.Columns.Add(prop.Name, Nullable.GetUnderlyingType(prop.PropertyType) ?? prop.PropertyType);
}
foreach (T item in data)
{
var atLeastOnePropertyExists = false;
DataRow row = table.NewRow();
foreach (PropertyDescriptor prop in properties)
{
if ((fieldsToInclude != null && !fieldsToInclude.Contains(prop.Name)) ||
(fieldsToExclude != null && fieldsToExclude.Contains(prop.Name)))
continue;
row[prop.Name] = prop.GetValue(item) ?? DBNull.Value;
atLeastOnePropertyExists = true;
}
if(atLeastOnePropertyExists) table.Rows.Add(row);
}
if (fieldsToInclude != null)
SetColumnsOrder(table, fieldsToInclude);
return table;
}
private static void SetColumnsOrder(DataTable table, params String[] columnNames)
{
int columnIndex = 0;
foreach (var columnName in columnNames)
{
table.Columns[columnName].SetOrdinal(columnIndex);
columnIndex++;
}
}
It's also possible through XmlSerialization.
The idea is - serialize to `XML` and then `readXml` method of `DataSet`.
I use this code (from an answer in SO, forgot where)
public static string SerializeXml<T>(T value) where T : class
{
if (value == null)
{
return null;
}
XmlSerializer serializer = new XmlSerializer(typeof(T));
XmlWriterSettings settings = new XmlWriterSettings();
settings.Encoding = new UnicodeEncoding(false, false);
settings.Indent = false;
settings.OmitXmlDeclaration = false;
// no BOM in a .NET string
using (StringWriter textWriter = new StringWriter())
{
using (XmlWriter xmlWriter = XmlWriter.Create(textWriter, settings))
{
serializer.Serialize(xmlWriter, value);
}
return textWriter.ToString();
}
}
so then it's as simple as:
string xmlString = Utility.SerializeXml(trans.InnerList);
DataSet ds = new DataSet("New_DataSet");
using (XmlReader reader = XmlReader.Create(new StringReader(xmlString)))
{
ds.Locale = System.Threading.Thread.CurrentThread.CurrentCulture;
ds.ReadXml(reader);
}
Not sure how it stands against all the other answers to this post, but it's also a possibility.
要将泛型列表转换为数据表,可以使用DataTableGenerator
这个库允许您将列表转换为具有多种功能的数据表,如
翻译数据表头 指定要显示的列