给出两条绝对路径,例如
/var/data/stuff/xyz.dat
/var/data
如何创建一个以第二条路径为基础的相对路径?在上面的例子中,结果应该是:./stuff/xyz.dat
给出两条绝对路径,例如
/var/data/stuff/xyz.dat
/var/data
如何创建一个以第二条路径为基础的相对路径?在上面的例子中,结果应该是:./stuff/xyz.dat
当前回答
ant有一个带有getRelativePath方法的FileUtils类。我自己还没有尝试过,但是值得一试。
http://javadoc.haefelinger.it/org.apache.ant/1.7.1/org/apache/tools/ant/util/FileUtils.html getRelativePath (java.io.File java.io.File)
其他回答
酷! !我需要一些类似这样的代码,但用于比较Linux机器上的目录路径。我发现这在父目录为目标的情况下不起作用。
下面是该方法的目录友好版本:
public static String getRelativePath(String targetPath, String basePath,
String pathSeparator) {
boolean isDir = false;
{
File f = new File(targetPath);
isDir = f.isDirectory();
}
// We need the -1 argument to split to make sure we get a trailing
// "" token if the base ends in the path separator and is therefore
// a directory. We require directory paths to end in the path
// separator -- otherwise they are indistinguishable from files.
String[] base = basePath.split(Pattern.quote(pathSeparator), -1);
String[] target = targetPath.split(Pattern.quote(pathSeparator), 0);
// First get all the common elements. Store them as a string,
// and also count how many of them there are.
String common = "";
int commonIndex = 0;
for (int i = 0; i < target.length && i < base.length; i++) {
if (target[i].equals(base[i])) {
common += target[i] + pathSeparator;
commonIndex++;
}
else break;
}
if (commonIndex == 0)
{
// Whoops -- not even a single common path element. This most
// likely indicates differing drive letters, like C: and D:.
// These paths cannot be relativized. Return the target path.
return targetPath;
// This should never happen when all absolute paths
// begin with / as in *nix.
}
String relative = "";
if (base.length == commonIndex) {
// Comment this out if you prefer that a relative path not start with ./
relative = "." + pathSeparator;
}
else {
int numDirsUp = base.length - commonIndex - (isDir?0:1); /* only subtract 1 if it is a file. */
// The number of directories we have to backtrack is the length of
// the base path MINUS the number of common path elements, minus
// one because the last element in the path isn't a directory.
for (int i = 1; i <= (numDirsUp); i++) {
relative += ".." + pathSeparator;
}
}
//if we are comparing directories then we
if (targetPath.length() > common.length()) {
//it's OK, it isn't a directory
relative += targetPath.substring(common.length());
}
return relative;
}
如果你知道第二个字符串是第一个字符串的一部分:
String s1 = "/var/data/stuff/xyz.dat";
String s2 = "/var/data";
String s3 = s1.substring(s2.length());
或者,如果你真的想把句号放在开头,就像你的例子中那样:
String s3 = ".".concat(s1.substring(s2.length()));
这里已经有很多答案了,但我发现他们并不能处理所有的情况,比如基地和目标是相同的。这个函数接受一个基本目录和一个目标路径,并返回相对路径。如果不存在相对路径,则返回目标路径。文件。分隔符是不必要的。
public static String getRelativePath (String baseDir, String targetPath) {
String[] base = baseDir.replace('\\', '/').split("\\/");
targetPath = targetPath.replace('\\', '/');
String[] target = targetPath.split("\\/");
// Count common elements and their length.
int commonCount = 0, commonLength = 0, maxCount = Math.min(target.length, base.length);
while (commonCount < maxCount) {
String targetElement = target[commonCount];
if (!targetElement.equals(base[commonCount])) break;
commonCount++;
commonLength += targetElement.length() + 1; // Directory name length plus slash.
}
if (commonCount == 0) return targetPath; // No common path element.
int targetLength = targetPath.length();
int dirsUp = base.length - commonCount;
StringBuffer relative = new StringBuffer(dirsUp * 3 + targetLength - commonLength + 1);
for (int i = 0; i < dirsUp; i++)
relative.append("../");
if (commonLength < targetLength) relative.append(targetPath.substring(commonLength));
return relative.toString();
}
在撰写本文时(2010年6月),这是唯一通过我的测试用例的解决方案。我不能保证这个解决方案没有错误,但是它确实通过了包含的测试用例。我所编写的方法和测试依赖于Apache公共IO中的FilenameUtils类。
该解决方案使用Java 1.4进行了测试。如果你正在使用Java 1.5(或更高版本),你应该考虑用StringBuilder代替StringBuffer(如果你还在使用Java 1.4,你应该考虑换一个雇主)。
import java.io.File;
import java.util.regex.Pattern;
import org.apache.commons.io.FilenameUtils;
public class ResourceUtils {
/**
* Get the relative path from one file to another, specifying the directory separator.
* If one of the provided resources does not exist, it is assumed to be a file unless it ends with '/' or
* '\'.
*
* @param targetPath targetPath is calculated to this file
* @param basePath basePath is calculated from this file
* @param pathSeparator directory separator. The platform default is not assumed so that we can test Unix behaviour when running on Windows (for example)
* @return
*/
public static String getRelativePath(String targetPath, String basePath, String pathSeparator) {
// Normalize the paths
String normalizedTargetPath = FilenameUtils.normalizeNoEndSeparator(targetPath);
String normalizedBasePath = FilenameUtils.normalizeNoEndSeparator(basePath);
// Undo the changes to the separators made by normalization
if (pathSeparator.equals("/")) {
normalizedTargetPath = FilenameUtils.separatorsToUnix(normalizedTargetPath);
normalizedBasePath = FilenameUtils.separatorsToUnix(normalizedBasePath);
} else if (pathSeparator.equals("\\")) {
normalizedTargetPath = FilenameUtils.separatorsToWindows(normalizedTargetPath);
normalizedBasePath = FilenameUtils.separatorsToWindows(normalizedBasePath);
} else {
throw new IllegalArgumentException("Unrecognised dir separator '" + pathSeparator + "'");
}
String[] base = normalizedBasePath.split(Pattern.quote(pathSeparator));
String[] target = normalizedTargetPath.split(Pattern.quote(pathSeparator));
// First get all the common elements. Store them as a string,
// and also count how many of them there are.
StringBuffer common = new StringBuffer();
int commonIndex = 0;
while (commonIndex < target.length && commonIndex < base.length
&& target[commonIndex].equals(base[commonIndex])) {
common.append(target[commonIndex] + pathSeparator);
commonIndex++;
}
if (commonIndex == 0) {
// No single common path element. This most
// likely indicates differing drive letters, like C: and D:.
// These paths cannot be relativized.
throw new PathResolutionException("No common path element found for '" + normalizedTargetPath + "' and '" + normalizedBasePath
+ "'");
}
// The number of directories we have to backtrack depends on whether the base is a file or a dir
// For example, the relative path from
//
// /foo/bar/baz/gg/ff to /foo/bar/baz
//
// ".." if ff is a file
// "../.." if ff is a directory
//
// The following is a heuristic to figure out if the base refers to a file or dir. It's not perfect, because
// the resource referred to by this path may not actually exist, but it's the best I can do
boolean baseIsFile = true;
File baseResource = new File(normalizedBasePath);
if (baseResource.exists()) {
baseIsFile = baseResource.isFile();
} else if (basePath.endsWith(pathSeparator)) {
baseIsFile = false;
}
StringBuffer relative = new StringBuffer();
if (base.length != commonIndex) {
int numDirsUp = baseIsFile ? base.length - commonIndex - 1 : base.length - commonIndex;
for (int i = 0; i < numDirsUp; i++) {
relative.append(".." + pathSeparator);
}
}
relative.append(normalizedTargetPath.substring(common.length()));
return relative.toString();
}
static class PathResolutionException extends RuntimeException {
PathResolutionException(String msg) {
super(msg);
}
}
}
这个通过的测试用例是
public void testGetRelativePathsUnix() {
assertEquals("stuff/xyz.dat", ResourceUtils.getRelativePath("/var/data/stuff/xyz.dat", "/var/data/", "/"));
assertEquals("../../b/c", ResourceUtils.getRelativePath("/a/b/c", "/a/x/y/", "/"));
assertEquals("../../b/c", ResourceUtils.getRelativePath("/m/n/o/a/b/c", "/m/n/o/a/x/y/", "/"));
}
public void testGetRelativePathFileToFile() {
String target = "C:\\Windows\\Boot\\Fonts\\chs_boot.ttf";
String base = "C:\\Windows\\Speech\\Common\\sapisvr.exe";
String relPath = ResourceUtils.getRelativePath(target, base, "\\");
assertEquals("..\\..\\Boot\\Fonts\\chs_boot.ttf", relPath);
}
public void testGetRelativePathDirectoryToFile() {
String target = "C:\\Windows\\Boot\\Fonts\\chs_boot.ttf";
String base = "C:\\Windows\\Speech\\Common\\";
String relPath = ResourceUtils.getRelativePath(target, base, "\\");
assertEquals("..\\..\\Boot\\Fonts\\chs_boot.ttf", relPath);
}
public void testGetRelativePathFileToDirectory() {
String target = "C:\\Windows\\Boot\\Fonts";
String base = "C:\\Windows\\Speech\\Common\\foo.txt";
String relPath = ResourceUtils.getRelativePath(target, base, "\\");
assertEquals("..\\..\\Boot\\Fonts", relPath);
}
public void testGetRelativePathDirectoryToDirectory() {
String target = "C:\\Windows\\Boot\\";
String base = "C:\\Windows\\Speech\\Common\\";
String expected = "..\\..\\Boot";
String relPath = ResourceUtils.getRelativePath(target, base, "\\");
assertEquals(expected, relPath);
}
public void testGetRelativePathDifferentDriveLetters() {
String target = "D:\\sources\\recovery\\RecEnv.exe";
String base = "C:\\Java\\workspace\\AcceptanceTests\\Standard test data\\geo\\";
try {
ResourceUtils.getRelativePath(target, base, "\\");
fail();
} catch (PathResolutionException ex) {
// expected exception
}
}
我的版本大致基于马特和史蒂夫的版本:
/**
* Returns the path of one File relative to another.
*
* @param target the target directory
* @param base the base directory
* @return target's path relative to the base directory
* @throws IOException if an error occurs while resolving the files' canonical names
*/
public static File getRelativeFile(File target, File base) throws IOException
{
String[] baseComponents = base.getCanonicalPath().split(Pattern.quote(File.separator));
String[] targetComponents = target.getCanonicalPath().split(Pattern.quote(File.separator));
// skip common components
int index = 0;
for (; index < targetComponents.length && index < baseComponents.length; ++index)
{
if (!targetComponents[index].equals(baseComponents[index]))
break;
}
StringBuilder result = new StringBuilder();
if (index != baseComponents.length)
{
// backtrack to base directory
for (int i = index; i < baseComponents.length; ++i)
result.append(".." + File.separator);
}
for (; index < targetComponents.length; ++index)
result.append(targetComponents[index] + File.separator);
if (!target.getPath().endsWith("/") && !target.getPath().endsWith("\\"))
{
// remove final path separator
result.delete(result.length() - File.separator.length(), result.length());
}
return new File(result.toString());
}