@jacob-sobus和@mquander和@Yogurt不完全正确。如果我需要第二天，我通常等待00:00的时间

    public static IEnumerable<DateTime> EachDay(DateTime from, DateTime thru)
    {
        for (var day = from.Date; day.Date <= thru.Date; day = day.NextDay())
            yield return day;
    }

    public static IEnumerable<DateTime> EachMonth(DateTime from, DateTime thru)
    {
        for (var month = from.Date; month.Date <= thru.Date || month.Year == thru.Year && month.Month == thru.Month; month = month.NextMonth())
            yield return month;
    }

    public static IEnumerable<DateTime> EachYear(DateTime from, DateTime thru)
    {
        for (var year = from.Date; year.Date <= thru.Date || year.Year == thru.Year; year = year.NextYear())
            yield return year;
    }

    public static DateTime NextDay(this DateTime date)
    {
        return date.AddTicks(TimeSpan.TicksPerDay - date.TimeOfDay.Ticks);
    }

    public static DateTime NextMonth(this DateTime date)
    {
        return date.AddTicks(TimeSpan.TicksPerDay * DateTime.DaysInMonth(date.Year, date.Month) - (date.TimeOfDay.Ticks + TimeSpan.TicksPerDay * (date.Day - 1)));
    }

    public static DateTime NextYear(this DateTime date)
    {
        var yearTicks = (new DateTime(date.Year + 1, 1, 1) - new DateTime(date.Year, 1, 1)).Ticks;
        var ticks = (date - new DateTime(date.Year, 1, 1)).Ticks;
        return date.AddTicks(yearTicks - ticks);
    }

    public static IEnumerable<DateTime> EachDayTo(this DateTime dateFrom, DateTime dateTo)
    {
        return EachDay(dateFrom, dateTo);
    }

    public static IEnumerable<DateTime> EachMonthTo(this DateTime dateFrom, DateTime dateTo)
    {
        return EachMonth(dateFrom, dateTo);
    }

    public static IEnumerable<DateTime> EachYearTo(this DateTime dateFrom, DateTime dateTo)
    {
        return EachYear(dateFrom, dateTo);
    }

每15分钟迭代一次

DateTime startDate = DateTime.Parse("2018-06-24 06:00");
        DateTime endDate = DateTime.Parse("2018-06-24 11:45");

        while (startDate.AddMinutes(15) <= endDate)
        {

            Console.WriteLine(startDate.ToString("yyyy-MM-dd HH:mm"));
            startDate = startDate.AddMinutes(15);
        }

根据问题你可以试试这个…

// looping between date range    
while (startDate <= endDate)
{
    //here will be your code block...

    startDate = startDate.AddDays(1);
}

谢谢……

一年后，希望它能帮助到某人，

为了更加灵活，这个版本包含了一个谓词。

使用

var today = DateTime.UtcNow;
var birthday = new DateTime(2018, 01, 01);

每天到我生日

var toBirthday = today.RangeTo(birthday);  

每月到我生日，第2步

var toBirthday = today.RangeTo(birthday, x => x.AddMonths(2));

每年我的生日

var toBirthday = today.RangeTo(birthday, x => x.AddYears(1));

使用RangeFrom代替

// same result
var fromToday = birthday.RangeFrom(today);
var toBirthday = today.RangeTo(birthday);

实现

public static class DateTimeExtensions 
{

    public static IEnumerable<DateTime> RangeTo(this DateTime from, DateTime to, Func<DateTime, DateTime> step = null)
    {
        if (step == null)
        {
            step = x => x.AddDays(1);
        }

        while (from < to)
        {
            yield return from;
            from = step(from);
        }
    }

    public static IEnumerable<DateTime> RangeFrom(this DateTime to, DateTime from, Func<DateTime, DateTime> step = null)
    {
        return from.RangeTo(to, step);
    }
}

临时演员

你可以抛出一个异常，如果fromDate > toDate，但我更喜欢返回一个空范围，而不是[]

在这里，你必须小心不要错过日期，因为在循环中，一个更好的解决方案是。

这为您提供了startdate的第一个日期，并在递增之前在循环中使用它，它将处理所有日期，包括enddate的最后一个日期，因此<= enddate。

所以上面的答案是正确的。

while (startdate <= enddate)
{
    // do something with the startdate
    startdate = startdate.adddays(interval);
}

DateTime startDate = new DateTime(2009, 3, 10);
DateTime stopDate = new DateTime(2009, 3, 26);
int interval = 3;

for (DateTime dateTime=startDate;
     dateTime < stopDate; 
     dateTime += TimeSpan.FromDays(interval))
{

}