我对这个游戏已经很晚了，但我一直在与一个类似的问题作斗争，下面的内容似乎为我完美地解决了这个问题，并且让我在守护子线程退出时做一些基本的线程状态检查和清理:

import threading
import time
import atexit

def do_work():

  i = 0
  @atexit.register
  def goodbye():
    print ("'CLEANLY' kill sub-thread with value: %s [THREAD: %s]" %
           (i, threading.currentThread().ident))

  while True:
    print i
    i += 1
    time.sleep(1)

t = threading.Thread(target=do_work)
t.daemon = True
t.start()

def after_timeout():
  print "KILL MAIN THREAD: %s" % threading.currentThread().ident
  raise SystemExit

threading.Timer(2, after_timeout).start()

收益率:

0
1
KILL MAIN THREAD: 140013208254208
'CLEANLY' kill sub-thread with value: 2 [THREAD: 140013674317568]

如果您确实需要终止子任务的能力，请使用另一种实现。Multiprocessing和gevent都支持不加选择地杀死一个“线程”。

Python的线程不支持取消。不要尝试。你的代码很可能死锁、损坏或泄漏内存，或者有其他意想不到的“有趣的”难以调试的效果，这种情况很少发生，而且不确定。

Python版本:3.8

使用守护线程来执行我们想要的，如果我们想要终止守护线程，我们只需要让父线程退出，然后系统就会终止父线程创建的守护线程。

还支持协程和协程函数。

def main():
    start_time = time.perf_counter()
    t1 = ExitThread(time.sleep, (10,), debug=False)
    t1.start()
    time.sleep(0.5)
    t1.exit()
    try:
        print(t1.result_future.result())
    except concurrent.futures.CancelledError:
        pass
    end_time = time.perf_counter()
    print(f"time cost {end_time - start_time:0.2f}")

下面是ExitThread源代码

import concurrent.futures
import threading
import typing
import asyncio


class _WorkItem(object):
    """ concurrent\futures\thread.py

    """

    def __init__(self, future, fn, args, kwargs, *, debug=None):
        self._debug = debug
        self.future = future
        self.fn = fn
        self.args = args
        self.kwargs = kwargs

    def run(self):
        if self._debug:
            print("ExitThread._WorkItem run")
        if not self.future.set_running_or_notify_cancel():
            return

        try:
            coroutine = None
            if asyncio.iscoroutinefunction(self.fn):
                coroutine = self.fn(*self.args, **self.kwargs)
            elif asyncio.iscoroutine(self.fn):
                coroutine = self.fn
            if coroutine is None:
                result = self.fn(*self.args, **self.kwargs)
            else:
                result = asyncio.run(coroutine)
            if self._debug:
                print("_WorkItem done")
        except BaseException as exc:
            self.future.set_exception(exc)
            # Break a reference cycle with the exception 'exc'
            self = None
        else:
            self.future.set_result(result)


class ExitThread:
    """ Like a stoppable thread

    Using coroutine for target then exit before running may cause RuntimeWarning.

    """

    def __init__(self, target: typing.Union[typing.Coroutine, typing.Callable] = None
                 , args=(), kwargs={}, *, daemon=None, debug=None):
        #
        self._debug = debug
        self._parent_thread = threading.Thread(target=self._parent_thread_run, name="ExitThread_parent_thread"
                                               , daemon=daemon)
        self._child_daemon_thread = None
        self.result_future = concurrent.futures.Future()
        self._workItem = _WorkItem(self.result_future, target, args, kwargs, debug=debug)
        self._parent_thread_exit_lock = threading.Lock()
        self._parent_thread_exit_lock.acquire()
        self._parent_thread_exit_lock_released = False  # When done it will be True
        self._started = False
        self._exited = False
        self.result_future.add_done_callback(self._release_parent_thread_exit_lock)

    def _parent_thread_run(self):
        self._child_daemon_thread = threading.Thread(target=self._child_daemon_thread_run
                                                     , name="ExitThread_child_daemon_thread"
                                                     , daemon=True)
        self._child_daemon_thread.start()
        # Block manager thread
        self._parent_thread_exit_lock.acquire()
        self._parent_thread_exit_lock.release()
        if self._debug:
            print("ExitThread._parent_thread_run exit")

    def _release_parent_thread_exit_lock(self, _future):
        if self._debug:
            print(f"ExitThread._release_parent_thread_exit_lock {self._parent_thread_exit_lock_released} {_future}")
        if not self._parent_thread_exit_lock_released:
            self._parent_thread_exit_lock_released = True
            self._parent_thread_exit_lock.release()

    def _child_daemon_thread_run(self):
        self._workItem.run()

    def start(self):
        if self._debug:
            print(f"ExitThread.start {self._started}")
        if not self._started:
            self._started = True
            self._parent_thread.start()

    def exit(self):
        if self._debug:
            print(f"ExitThread.exit exited: {self._exited} lock_released: {self._parent_thread_exit_lock_released}")
        if self._parent_thread_exit_lock_released:
            return
        if not self._exited:
            self._exited = True
            if not self.result_future.cancel():
                if self.result_future.running():
                    self.result_future.set_exception(concurrent.futures.CancelledError())

最简单的方法是:

from threading import Thread
from time import sleep

def do_something():
    global thread_work
    while thread_work:
        print('doing something')
        sleep(5)
    print('Thread stopped')

thread_work = True
Thread(target=do_something).start()
sleep(5)
thread_work = False

另一种方法是使用signal.pthread_kill发送一个停止信号。

from signal import pthread_kill, SIGTSTP
from threading import Thread
from itertools import count
from time import sleep

def target():
    for num in count():
        print(num)
        sleep(1)

thread = Thread(target=target)
thread.start()
sleep(5)
pthread_kill(thread.ident, SIGTSTP)

结果

0
1
2
3
4

[14]+  Stopped

我对这个游戏已经很晚了，但我一直在与一个类似的问题作斗争，下面的内容似乎为我完美地解决了这个问题，并且让我在守护子线程退出时做一些基本的线程状态检查和清理:

import threading
import time
import atexit

def do_work():

  i = 0
  @atexit.register
  def goodbye():
    print ("'CLEANLY' kill sub-thread with value: %s [THREAD: %s]" %
           (i, threading.currentThread().ident))

  while True:
    print i
    i += 1
    time.sleep(1)

t = threading.Thread(target=do_work)
t.daemon = True
t.start()

def after_timeout():
  print "KILL MAIN THREAD: %s" % threading.currentThread().ident
  raise SystemExit

threading.Timer(2, after_timeout).start()

收益率:

0
1
KILL MAIN THREAD: 140013208254208
'CLEANLY' kill sub-thread with value: 2 [THREAD: 140013674317568]