从Python 3.7开始，以下代码工作正常：

from json import dumps
result = {"symbol": "ƒ"}
json_string = dumps(result, sort_keys=True, indent=2, ensure_ascii=False)
print(json_string)

输出：

{"symbol": "ƒ"}

这是一个错误的答案，但了解为什么它是错误的仍然很有用。见注释。

使用unicode转义：

>>> d = {1: "ברי צקלה", 2: u"ברי צקלה"}
>>> json_str = json.dumps(d).decode('unicode-escape').encode('utf8')
>>> print json_str
{"1": "ברי צקלה", "2": "ברי צקלה"}

使用ensure_ascii=False开关到json.dumps（），然后手动将值编码为UTF-8：

>>> json_string = json.dumps("ברי צקלה", ensure_ascii=False).encode('utf8')
>>> json_string
b'"\xd7\x91\xd7\xa8\xd7\x99 \xd7\xa6\xd7\xa7\xd7\x9c\xd7\x94"'
>>> print(json_string.decode())
"ברי צקלה"

如果要写入文件，只需使用json.dump（）并将其留给file对象进行编码：

with open('filename', 'w', encoding='utf8') as json_file:
    json.dump("ברי צקלה", json_file, ensure_ascii=False)

Python 2的注意事项

对于Python 2，还有一些需要注意的事项。如果要将其写入文件，可以使用io.open（）而不是open（）来生成一个文件对象，该对象在写入时为您编码Unicode值，然后使用json.dump（）来写入该文件：

with io.open('filename', 'w', encoding='utf8') as json_file:
    json.dump(u"ברי צקלה", json_file, ensure_ascii=False)

请注意，json模块中存在一个bug，其中ensure_ascii=False标志可以产生unicode和str对象的混合。Python 2的解决方法是：

with io.open('filename', 'w', encoding='utf8') as json_file:
    data = json.dumps(u"ברי צקלה", ensure_ascii=False)
    # unicode(data) auto-decodes data to unicode if str
    json_file.write(unicode(data))

在Python 2中，当使用编码为UTF-8的字节字符串（类型str）时，请确保还设置了编码关键字：

>>> d={ 1: "ברי צקלה", 2: u"ברי צקלה" }
>>> d
{1: '\xd7\x91\xd7\xa8\xd7\x99 \xd7\xa6\xd7\xa7\xd7\x9c\xd7\x94', 2: u'\u05d1\u05e8\u05d9 \u05e6\u05e7\u05dc\u05d4'}

>>> s=json.dumps(d, ensure_ascii=False, encoding='utf8')
>>> s
u'{"1": "\u05d1\u05e8\u05d9 \u05e6\u05e7\u05dc\u05d4", "2": "\u05d1\u05e8\u05d9 \u05e6\u05e7\u05dc\u05d4"}'
>>> json.loads(s)['1']
u'\u05d1\u05e8\u05d9 \u05e6\u05e7\u05dc\u05d4'
>>> json.loads(s)['2']
u'\u05d1\u05e8\u05d9 \u05e6\u05e7\u05dc\u05d4'
>>> print json.loads(s)['1']
ברי צקלה
>>> print json.loads(s)['2']
ברי צקלה

以下是我对上面的var阅读答案和谷歌的理解。

# coding:utf-8
r"""
@update: 2017-01-09 14:44:39
@explain: str, unicode, bytes in python2to3
    #python2 UnicodeDecodeError: 'ascii' codec can't decode byte 0xe4 in position 7: ordinal not in range(128)
    #1.reload
    #importlib,sys
    #importlib.reload(sys)
    #sys.setdefaultencoding('utf-8') #python3 don't have this attribute.
    #not suggest even in python2 #see:http://stackoverflow.com/questions/3828723/why-should-we-not-use-sys-setdefaultencodingutf-8-in-a-py-script
    #2.overwrite /usr/lib/python2.7/sitecustomize.py or (sitecustomize.py and PYTHONPATH=".:$PYTHONPATH" python)
    #too complex
    #3.control by your own (best)
    #==> all string must be unicode like python3 (u'xx'|b'xx'.encode('utf-8')) (unicode 's disappeared in python3)
    #see: http://blog.ernest.me/post/python-setdefaultencoding-unicode-bytes

    #how to Saving utf-8 texts in json.dumps as UTF8, not as \u escape sequence
    #http://stackoverflow.com/questions/18337407/saving-utf-8-texts-in-json-dumps-as-utf8-not-as-u-escape-sequence
"""

from __future__ import print_function
import json

a = {"b": u"中文"}  # add u for python2 compatibility
print('%r' % a)
print('%r' % json.dumps(a))
print('%r' % (json.dumps(a).encode('utf8')))
a = {"b": u"中文"}
print('%r' % json.dumps(a, ensure_ascii=False))
print('%r' % (json.dumps(a, ensure_ascii=False).encode('utf8')))
# print(a.encode('utf8')) #AttributeError: 'dict' object has no attribute 'encode'
print('')

# python2:bytes=str; python3:bytes
b = a['b'].encode('utf-8')
print('%r' % b)
print('%r' % b.decode("utf-8"))
print('')

# python2:unicode; python3:str=unicode
c = b.decode('utf-8')
print('%r' % c)
print('%r' % c.encode('utf-8'))
"""
#python2
{'b': u'\u4e2d\u6587'}
'{"b": "\\u4e2d\\u6587"}'
'{"b": "\\u4e2d\\u6587"}'
u'{"b": "\u4e2d\u6587"}'
'{"b": "\xe4\xb8\xad\xe6\x96\x87"}'

'\xe4\xb8\xad\xe6\x96\x87'
u'\u4e2d\u6587'

u'\u4e2d\u6587'
'\xe4\xb8\xad\xe6\x96\x87'

#python3
{'b': '中文'}
'{"b": "\\u4e2d\\u6587"}'
b'{"b": "\\u4e2d\\u6587"}'
'{"b": "中文"}'
b'{"b": "\xe4\xb8\xad\xe6\x96\x87"}'

b'\xe4\xb8\xad\xe6\x96\x87'
'中文'

'中文'
b'\xe4\xb8\xad\xe6\x96\x87'
"""

Pieters的Python 2解决方案在边缘情况下失败：

d = {u'keyword': u'bad credit  \xe7redit cards'}
with io.open('filename', 'w', encoding='utf8') as json_file:
    data = json.dumps(d, ensure_ascii=False).decode('utf8')
    try:
        json_file.write(data)
    except TypeError:
        # Decode data to Unicode first
        json_file.write(data.decode('utf8'))

UnicodeEncodeError: 'ascii' codec can't encode character u'\xe7' in position 25: ordinal not in range(128)

它在第3行的.decode（'utf8'）部分崩溃。我通过避免该步骤以及ASCII的特殊外壳，使程序更简单，从而解决了这个问题：

with io.open('filename', 'w', encoding='utf8') as json_file:
  data = json.dumps(d, ensure_ascii=False, encoding='utf8')
  json_file.write(unicode(data))

cat filename
{"keyword": "bad credit  çredit cards"}

下面是我使用json.dump（）的解决方案：

def jsonWrite(p, pyobj, ensure_ascii=False, encoding=SYSTEM_ENCODING, **kwargs):
    with codecs.open(p, 'wb', 'utf_8') as fileobj:
        json.dump(pyobj, fileobj, ensure_ascii=ensure_ascii,encoding=encoding, **kwargs)

其中SYSTEM_ENCODING设置为：

locale.setlocale(locale.LC_ALL, '')
SYSTEM_ENCODING = locale.getlocale()[1]