最干净？

---
version: "2"
services:
  test:
    image: alpine
    entrypoint: ["/bin/sh","-c"]
    command:
    - |
       echo a
       echo b
       echo c

基于Alpine的图像实际上似乎没有安装bash，但您可以使用sh或ash链接到/bin/busybox。

docker-compose.yml示例：

version: "3"
services:

  api:
    restart: unless-stopped
    command: ash -c "flask models init && flask run"

想好了，使用bash-c。

例子：

command: bash -c "python manage.py migrate && python manage.py runserver 0.0.0.0:8000"

多行中的相同示例：

command: >
    bash -c "python manage.py migrate
    && python manage.py runserver 0.0.0.0:8000"

Or:

command: bash -c "
    python manage.py migrate
    && python manage.py runserver 0.0.0.0:8000
  "

这是我解决这个问题的方法：

services:
  mongo1:
    container_name: mongo1
    image: mongo:4.4.4
    restart: always
#    OPTION 01:
#    command: >
#      bash -c "chmod +x /scripts/rs-init.sh
#      && sh /scripts/rs-init.sh"
#    OPTION 02:
    entrypoint: [ "bash", "-c", "chmod +x /scripts/rs-init.sh && sh /scripts/rs-init.sh"]
    ports:
      - "9042:9042"
    networks:
      - mongo-cluster
    volumes:
      - ~/mongors/data1:/data/db
      - ./rs-init.sh:/scripts/rs-init.sh
      - api_vol:/data/db
    environment:
      *env-vars
    depends_on:
      - mongo2
      - mongo3

基于@Bjorn答案，docker最近引入了特殊的依赖规则，允许您等待“init容器”成功退出

db:
  image: postgres
web:
  image: app
  command: python manage.py runserver 0.0.0.0:8000
  depends_on:
    db:
    migration:
      condition: service_completed_successfully
migration:
  build: .
  image: app
  command: python manage.py migrate
  depends_on:
    - db

我不确定你是否还需要buildkit，但在我这边，它可以与

DOCKER_BUILDKIT=1 COMPOSE_DOCKER_CLI_BUILD=1 docker-compose up

这对我有用：

version: '3.1'
services:
  db:
    image: postgres
  web:
    build: .
    command:
      - /bin/bash
      - -c
      - |
        python manage.py migrate
        python manage.py runserver 0.0.0.0:8000

    volumes:
      - .:/code
    ports:
      - "8000:8000"
    links:
      - db

dockercompose尝试在运行命令之前取消对变量的引用，因此如果您希望bash处理变量，则需要通过加倍它们来逃避美元符号。。。

    command:
      - /bin/bash
      - -c
      - |
        var=$$(echo 'foo')
        echo $$var # prints foo

…否则会出现错误：

服务“web”中“命令”选项的插值格式无效：