我需要在配置文件的末尾添加以下一行:

include "/configs/projectname.conf"

到一个名为lighttpd.conf的文件

我正在研究使用sed来做到这一点,但我不知道如何。

我怎么能只插入它,如果行已经不存在?


当前回答

下面是sed版本:

sed -e '\|include "/configs/projectname.conf"|h; ${x;s/incl//;{g;t};a\' -e 'include "/configs/projectname.conf"' -e '}' file

如果字符串在变量中:

string='include "/configs/projectname.conf"'
sed -e "\|$string|h; \${x;s|$string||;{g;t};a\\" -e "$string" -e "}" file

其他回答

下面是awk的一行代码:

 awk -v s="option=value" '/^option/{f=1;$0=s}7;END{if(!f)print s}' file

这不会对文件进行就地更改,但是您可以:

awk '...' file > tmpfile && mv tmpfile file

下面是sed版本:

sed -e '\|include "/configs/projectname.conf"|h; ${x;s/incl//;{g;t};a\' -e 'include "/configs/projectname.conf"' -e '}' file

如果字符串在变量中:

string='include "/configs/projectname.conf"'
sed -e "\|$string|h; \${x;s|$string||;{g;t};a\\" -e "$string" -e "}" file

使用sed,你可以这样说:

sed -e '/option=/{s/.*/option=value/;:a;n;:ba;q}' -e 'aoption=value' filename

如果参数存在,这将替换它,否则将把它添加到文件的底部。


如果你想就地编辑文件,使用-i选项:

sed -i -e '/option=/{s/.*/option=value/;:a;n;:ba;q}' -e 'aoption=value' filename

使用sed,最简单的语法:

sed \
    -e '/^\(option=\).*/{s//\1value/;:a;n;ba;q}' \
    -e '$aoption=value' filename

如果参数存在,这将替换它,否则将把它添加到文件的底部。

如果您想就地编辑文件,请使用-i选项。


如果你想接受并保留空白,并且除了删除注释之外,如果行已经存在,但被注释掉了,那么写:

sed -i \
    -e '/^#\?\(\s*option\s*=\s*\).*/{s//\1value/;:a;n;ba;q}' \
    -e '$aoption=value' filename

请注意,选项和值都不能包含斜杠/,否则必须将其转义为\/。


要使用bash变量$option和$value,你可以这样写:

sed -i \
    -e '/^#\?\(\s*'${option//\//\\/}'\s*=\s*\).*/{s//\1'${value//\//\\/}'/;:a;n;ba;q}' \
    -e '$a'${option//\//\\/}'='${value//\//\\/} filename

bash表达式${option//\//\\/}引用斜杠,它将所有/替换为\/。

注意:刚刚陷入了一个问题。在bash中,你可以引用"${option//\//\\/}",但在busybox的sh中,这行不通,所以你应该避免使用引号,至少在非boure -shell中是这样。


所有这些组合在一个bash函数中:

# call option with parameters: $1=name $2=value $3=file
function option() {
    name=${1//\//\\/}
    value=${2//\//\\/}
    sed -i \
        -e '/^#\?\(\s*'"${name}"'\s*=\s*\).*/{s//\1'"${value}"'/;:a;n;ba;q}' \
        -e '$a'"${name}"'='"${value}" $3
}

解释:

/^\(option=\).*/: Match lines that start with option= and (.*) ignore everything after the =. The \(…\) encloses the part we will reuse as \1later. /^#?(\s*'"${option//////}"'\s*=\s*).*/: Ignore commented out code with # at the begin of line. \? means «optional». The comment will be removed, because it is outside of the copied part in \(…\). \s* means «any number of white spaces» (space, tabulator). White spaces are copied, since they are within \(…\), so you do not lose formatting. /^\(option=\).*/{…}: If matches a line /…/, then execute the next command. Command to execute is not a single command, but a block {…}. s//…/: Search and replace. Since the search term is empty //, it applies to the last match, which was /^\(option=\).*/. s//\1value/: Replace the last match with everything in (…), referenced by \1and the textvalue` :a;n;ba;q: Set label a, then read next line n, then branch b (or goto) back to label a, that means: read all lines up to the end of file, so after the first match, just fetch all following lines without further processing. Then q quit and therefore ignore everything else. $aoption=value: At the end of file $, append a the text option=value

关于sed和命令概述的更多信息请参阅我的博客:

https://marc.wackerlin.ch/computer/stream-editor-sed-overview-and-reference

如果有一天,其他人不得不将此代码作为“遗留代码”来处理,那么如果您编写了不那么开放的代码,那么这个人将会感激您,例如

grep -q -F 'include "/configs/projectname.conf"' lighttpd.conf
if [ $? -ne 0 ]; then
  echo 'include "/configs/projectname.conf"' >> lighttpd.conf
fi