如果没有UINavigationController,我似乎无法得到最顶端的UIViewController。以下是我目前所掌握的:

UIApplication.sharedApplication().keyWindow?.rootViewController?.presentViewController(vc, animated: true, completion: nil)

然而,它似乎没有做任何事情。keyWindow和rootViewController似乎也不是nil值,所以可选的链接应该不是问题。

注意:这样做不是一个好主意。它打破了MVC模式。


当前回答

iOS13+ //top最多视图控制器

extension UIViewController {
    func topMostViewController() -> UIViewController {
        if self.presentedViewController == nil {
            return self
        }
        if let navigation = self.presentedViewController as? UINavigationController {
            return navigation.visibleViewController!.topMostViewController()
        }
        if let tab = self.presentedViewController as? UITabBarController {
            if let selectedTab = tab.selectedViewController {
                return selectedTab.topMostViewController()
            }
            return tab.topMostViewController()
        }
        return self.presentedViewController!.topMostViewController()
    }
}

extension UIApplication {
    func topMostViewController() -> UIViewController? {
        return UIWindow.key!.rootViewController?.topMostViewController()
    }
}

extension UIWindow {
    static var key: UIWindow? {
        if #available(iOS 13, *) {
            return UIApplication.shared.windows.first { $0.isKeyWindow }
        } else {
            return UIApplication.shared.keyWindow
        }
    }
}

//use let vc = UIApplication.shared.topMostViewController()

// End top Most view Controller

其他回答

基于上面的Bob -c:

斯威夫特3.0

extension UIWindow {


    func visibleViewController() -> UIViewController? {
        if let rootViewController: UIViewController  = self.rootViewController {
            return UIWindow.getVisibleViewControllerFrom(vc: rootViewController)
        }
        return nil
    }

    class func getVisibleViewControllerFrom(vc:UIViewController) -> UIViewController {

        if vc.isKind(of: UINavigationController.self) {

            let navigationController = vc as! UINavigationController
            return UIWindow.getVisibleViewControllerFrom( vc: navigationController.visibleViewController!)

        } else if vc.isKind(of: UITabBarController.self) {

            let tabBarController = vc as! UITabBarController
            return UIWindow.getVisibleViewControllerFrom(vc: tabBarController.selectedViewController!)

        } else {

            if let presentedViewController = vc.presentedViewController {

                return UIWindow.getVisibleViewControllerFrom(vc: presentedViewController)

            } else {

                return vc;
            }
        }
    }
}
    extension UIApplication {
        
       public var mainKeyWindow: UIWindow? {
           if #available(iOS 13, *) {
             return UIApplication.shared.connectedScenes
            .filter { $0.activationState == .foregroundActive }
            .first(where: { $0 is UIWindowScene })
            .flatMap { $0 as? UIWindowScene }?.windows
            .first(where: \.isKeyWindow)
           } else {
              return UIApplication.shared.windows.first { $0.isKeyWindow }
           }
        }
    

    public var rootViewController: UIViewController? {
        guard let keyWindow = UIApplication.shared.mainKeyWindow, let rootViewController = keyWindow.rootViewController else {
            return nil
        }
        return rootViewController
    }

    public func topViewController(controller: UIViewController? = UIApplication.shared.rootViewController) -> UIViewController? {

        if controller == nil {
            return topViewController(controller: rootViewController)
        }
        
        if let navigationController = controller as? UINavigationController {
            return topViewController(controller: navigationController.visibleViewController)
        }

        if let tabController = controller as? UITabBarController {
            if let selectedViewController = tabController.selectedViewController {
                return topViewController(controller: selectedViewController)
            }
        }

        if let presentedViewController = controller?.presentedViewController {
            return topViewController(controller: presentedViewController)
        }

        return controller
    }
}

Swift 5.2及以上版本

太多口味了,但都不是一种反复精心制作的。结合前面的内容:

     func topMostController() -> UIViewController? {
        var from = UIApplication.shared.keyWindow?.rootViewController
        while (from != nil) {
            if let to = (from as? UITabBarController)?.selectedViewController {
                from = to
            } else if let to = (from as? UINavigationController)?.visibleViewController {
                from = to
            } else if let to = from?.presentedViewController {
                from = to
            } else {
                break
            }
        }
        return from
    }

最简单的方法是从视图控制器堆栈中取出最后一个:

if let viewController: UIViewController = navigationController.viewControllers.last {
    // This `viewController` is on the top.
}

我喜欢@dianz的回答,下面是swift 3的版本。它基本上是一样的,但他少了一个大括号,一些语法/变量/方法名已经改变了。所以它就在这里!

extension UIApplication {
    class func topViewController(base: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {
        if let nav = base as? UINavigationController {
            return topViewController(base: nav.visibleViewController)
        }
        if let tab = base as? UITabBarController {
            if let selected = tab.selectedViewController {
                return topViewController(base: selected)
            }
        }
        if let presented = base?.presentedViewController {
            return topViewController(base: presented)
        }
        return base
    }
}

用法仍然是一样的:

if let topController = UIApplication.topViewController() {
    print("The view controller you're looking at is: \(topController)")
}