如何将一个数组列表(size=1000)拆分为多个相同大小(=10)的数组列表?
ArrayList<Integer> results;
如何将一个数组列表(size=1000)拆分为多个相同大小(=10)的数组列表?
ArrayList<Integer> results;
当前回答
您可以将Guava库添加到项目中并使用列表。划分方法,例如:
List<Integer> bigList = ...
List<List<Integer>> smallerLists = Lists.partition(bigList, 10);
其他回答
private ArrayList<List<String>> chunkArrayList(ArrayList<String> arrayToChunk, int chunkSize) {
ArrayList<List<String>> chunkList = new ArrayList<>();
int guide = arrayToChunk.size();
int index = 0;
int tale = chunkSize;
while (tale < arrayToChunk.size()){
chunkList.add(arrayToChunk.subList(index, tale));
guide = guide - chunkSize;
index = index + chunkSize;
tale = tale + chunkSize;
}
if (guide >0) {
chunkList.add(arrayToChunk.subList(index, index + guide));
}
Log.i("Chunked Array: " , chunkList.toString());
return chunkList;
}
例子
ArrayList<String> test = new ArrayList<>();
for (int i=1; i<=1000; i++){
test.add(String.valueOf(i));
}
chunkArrayList(test,10);
输出
分块:[[1,2,3,4,5,6,7,8,9,10),(11、12、13、14、15、16、17、18、19、20],[21日,22日,23日,24日,25日,26日,27日,28日,29日,30日],[第三十一条、第三十二条、第三十三,34岁,35岁,36岁,37岁,38岁,39岁,40],[41、42、43、44、45、46岁,47岁,48岁,49岁,50],[51岁,52岁,53岁,54岁,55岁,56岁,57岁的58岁的59岁60],[61,62,63,64,65,66,67,68,69,70],[71,72,73,74,75,76,77,78,79,80],[81,82,83,84,85,86,87,88,89,90],[91,92,93,94,95,96,97,98,99,100 ], .........
你会在日志里看到的
您可以将Guava库添加到项目中并使用列表。划分方法,例如:
List<Integer> bigList = ...
List<List<Integer>> smallerLists = Lists.partition(bigList, 10);
Apache Commons Collections 4在ListUtils类中有一个分区方法。下面是它的工作原理:
import org.apache.commons.collections4.ListUtils;
...
int targetSize = 100;
List<Integer> largeList = ...
List<List<Integer>> output = ListUtils.partition(largeList, targetSize);
只是要明确一点,这还需要更多的测试…
public class Splitter {
public static <T> List<List<T>> splitList(List<T> listTobeSplit, int size) {
List<List<T>> sublists= new LinkedList<>();
if(listTobeSplit.size()>size) {
int counter=0;
boolean lastListadded=false;
List<T> subList=new LinkedList<>();
for(T t: listTobeSplit) {
if (counter==0) {
subList =new LinkedList<>();
subList.add(t);
counter++;
lastListadded=false;
}
else if(counter>0 && counter<size-1) {
subList.add(t);
counter++;
}
else {
lastListadded=true;
subList.add(t);
sublists.add(subList);
counter=0;
}
}
if(lastListadded==false)
sublists.add(subList);
}
else {
sublists.add(listTobeSplit);
}
log.debug("sublists: "+sublists);
return sublists;
}
}
您需要知道您划分列表的块大小。假设您有一个包含108个条目的列表,您需要25个块大小。因此,你最终会得到5个列表:
4项各有25项; 有8个元素的。
代码:
public static void main(String[] args) {
List<Integer> list = new ArrayList<Integer>();
for (int i=0; i<108; i++){
list.add(i);
}
int size= list.size();
int j=0;
List< List<Integer> > splittedList = new ArrayList<List<Integer>>() ;
List<Integer> tempList = new ArrayList<Integer>();
for(j=0;j<size;j++){
tempList.add(list.get(j));
if((j+1)%25==0){
// chunk of 25 created and clearing tempList
splittedList.add(tempList);
tempList = null;
//intializing it again for new chunk
tempList = new ArrayList<Integer>();
}
}
if(size%25!=0){
//adding the remaining enteries
splittedList.add(tempList);
}
for (int k=0;k<splittedList.size(); k++){
//(k+1) because we started from k=0
System.out.println("Chunk number: "+(k+1)+" has elements = "+splittedList.get(k).size());
}
}