不需要任何额外的NPM包

//...
const BackendPageListing = () => {
    
    const [ myData, setMyData] = useState( {
        id: 1,
        content: "abc"
    })

    const myFunction = ( x ) => {
        
        setPagenateInfo({
        ...myData,
        content: x
        })

        console.log(myData) // not reflecting change immediately

        let myDataNew = {...myData, content: x };
        
        console.log(myDataNew) // Reflecting change immediately

    }

    return (
        <>
            <button onClick={()=>{ myFunction("New Content")} }>Update MyData</button>
        </>
    )

var [state,setState]=useState(defaultValue)

useEffect(()=>{
   var updatedState
   setState(currentState=>{    // Do not change the state by get the updated state
      updateState=currentState
      return currentState
   })
   alert(updateState) // the current state.
})

我知道已经有很好的答案了。但我想给另一个想法如何解决同样的问题，并访问最新的'电影'状态，使用我的模块react-useStateRef。

正如你所理解的，通过使用React状态，你可以在每次状态改变时渲染页面。但是通过使用React ref，你总是可以得到最新的值。

模块react-useStateRef让你同时使用状态和ref。它与React向后兼容。useState，所以你可以替换import语句

const { useEffect } = React
import { useState } from 'react-usestateref'

  const [movies, setMovies] = useState(initialValue);

  useEffect(() => {
    (async function() {
      try {

        const result = [
          {
            id: "1546514491119",
          },
        ];
        console.log("result =", result);
        setMovies(result);
        console.log("movies =", movies.current); // will give you the latest results
      } catch (e) {
        console.error(e);
      }
    })();
  }, []);

更多信息:

react-usestsateref

并不是说要这样做，但是没有useEffect做OP要求的事情并不难。

使用promise来解析setter函数体中的新状态:

const getState = <T>(
  setState: React.Dispatch<React.SetStateAction<T>>
): Promise<T> => {
  return new Promise((resolve) => {
    setState((currentState: T) => {
      resolve(currentState);
      return currentState;
    });
  });
};

这就是你如何使用它(示例显示了count和outOfSyncCount/syncCount在UI渲染中的比较):

const App: React.FC = () => {
  const [count, setCount] = useState(0);
  const [outOfSyncCount, setOutOfSyncCount] = useState(0);
  const [syncCount, setSyncCount] = useState(0);

  const handleOnClick = async () => {
    setCount(count + 1);

    // Doesn't work
    setOutOfSyncCount(count);

    // Works
    const newCount = await getState(setCount);
    setSyncCount(newCount);
  };

  return (
    <>
      <h2>Count = {count}</h2>
      <h2>Synced count = {syncCount}</h2>
      <h2>Out of sync count = {outOfSyncCount}</h2>
      <button onClick={handleOnClick}>Increment</button>
    </>
  );
};

之前答案的附加细节:

虽然React的setState是异步的(类和钩子都是异步的)，而且很容易用这个事实来解释观察到的行为，但这并不是它发生的原因。

TLDR:原因是围绕不可变const值的闭包作用域。

解决方案:

read the value in render function (not inside nested functions): useEffect(() => { setMovies(result) }, []) console.log(movies) add the variable into dependencies (and use the react-hooks/exhaustive-deps eslint rule): useEffect(() => { setMovies(result) }, []) useEffect(() => { console.log(movies) }, [movies]) use a temporary variable: useEffect(() => { const newMovies = result console.log(newMovies) setMovies(newMovies) }, []) use a mutable reference (if we don't need a state and only want to remember the value - updating a ref doesn't trigger re-render): const moviesRef = useRef(initialValue) useEffect(() => { moviesRef.current = result console.log(moviesRef.current) }, [])

解释为什么会这样:

如果async是唯一的原因，那么可以等待setState()。

然而，道具和状态都假定在1渲染期间不变。

对待这个问题。状态，仿佛它是不可变的。

对于钩子，通过使用常量值和const关键字来加强这个假设:

const [state, setState] = useState('initial')

该值在2个渲染之间可能不同，但在渲染本身和任何闭包(即使在渲染完成后仍然存在更长的函数，例如useEffect，事件处理程序，在任何Promise或setTimeout内)中保持不变。

考虑以下伪的，但是同步的，类似react的实现:

// sync implementation: let internalState let renderAgain const setState = (updateFn) => { internalState = updateFn(internalState) renderAgain() } const useState = (defaultState) => { if (!internalState) { internalState = defaultState } return [internalState, setState] } const render = (component, node) => { const {html, handleClick} = component() node.innerHTML = html renderAgain = () => render(component, node) return handleClick } // test: const MyComponent = () => { const [x, setX] = useState(1) console.log('in render:', x) // ✅ const handleClick = () => { setX(current => current + 1) console.log('in handler/effect/Promise/setTimeout:', x) // ❌ NOT updated } return { html: `<button>${x}</button>`, handleClick } } const triggerClick = render(MyComponent, document.getElementById('root')) triggerClick() triggerClick() triggerClick() <div id="root"></div>

React的useEffect有自己的状态/生命周期。它与状态突变有关，直到效果被破坏才会更新状态。

只要在参数状态中传递一个参数或留下一个黑色数组，它就会完美地工作。

React.useEffect(() => {
    console.log("effect");
    (async () => {
        try {
            let result = await fetch("/query/countries");
            const res = await result.json();
            let result1 = await fetch("/query/projects");
            const res1 = await result1.json();
            let result11 = await fetch("/query/regions");
            const res11 = await result11.json();
            setData({
                countries: res,
                projects: res1,
                regions: res11
            });
        } catch {}
    })(data)
}, [setData])
# or use this
useEffect(() => {
    (async () => {
        try {
            await Promise.all([
                fetch("/query/countries").then((response) => response.json()),
                fetch("/query/projects").then((response) => response.json()),
                fetch("/query/regions").then((response) => response.json())
            ]).then(([country, project, region]) => {
                // console.log(country, project, region);
                setData({
                    countries: country,
                    projects: project,
                    regions: region
                });
            })
        } catch {
            console.log("data fetch error")
        }
    })()
}, [setData]);

或者，您可以尝试React. useref()在React钩子中进行即时更改。

const movies = React.useRef(null);
useEffect(() => {
movies.current='values';
console.log(movies.current)
}, [])