为什么不添加CORS头选项路由允许浏览器访问我的API?

我试图在使用Express.js web框架的Node.js应用程序中支持CORS。我已经阅读了谷歌关于如何处理这个问题的小组讨论，并阅读了一些关于CORS如何工作的文章。首先，我这样做(代码是用CoffeeScript语法写的):

app.options "*", (req, res) ->
  res.header 'Access-Control-Allow-Origin', '*'
  res.header 'Access-Control-Allow-Credentials', true
  # try: 'POST, GET, PUT, DELETE, OPTIONS'
  res.header 'Access-Control-Allow-Methods', 'GET, OPTIONS'
  # try: 'X-Requested-With, X-HTTP-Method-Override, Content-Type, Accept'
  res.header 'Access-Control-Allow-Headers', 'Content-Type'
  # ...

这似乎不管用。似乎我的浏览器(Chrome)没有发送最初的选项请求。当我刚刚更新了块的资源，我需要提交一个跨起源GET请求:

app.get "/somethingelse", (req, res) ->
  # ...
  res.header 'Access-Control-Allow-Origin', '*'
  res.header 'Access-Control-Allow-Credentials', true
  res.header 'Access-Control-Allow-Methods', 'POST, GET, PUT, DELETE, OPTIONS'
  res.header 'Access-Control-Allow-Headers', 'Content-Type'
  # ...

它工作(在Chrome)。这也适用于Safari。

我听说……

在实现CORS的浏览器中，每个跨源GET或POST请求之前都有一个OPTIONS请求，用于检查GET或POST是否正常。

所以我的主要问题是，为什么这种情况在我身上没有发生?为什么我的app。options块没有被调用?为什么我需要在我的主app.get块设置标题?

当前回答

我对Express 4.2.0的最简单的解决方案(编辑:在4.3.0中似乎不起作用)是:

function supportCrossOriginScript(req, res, next) {
    res.status(200);
    res.header("Access-Control-Allow-Origin", "*");
    res.header("Access-Control-Allow-Headers", "Content-Type");

    // res.header("Access-Control-Allow-Headers", "Origin");
    // res.header("Access-Control-Allow-Headers", "Origin, X-Requested-With, Content-Type, Accept");
    // res.header("Access-Control-Allow-Methods","POST, OPTIONS");
    // res.header("Access-Control-Allow-Methods","POST, GET, OPTIONS, DELETE, PUT, HEAD");
    // res.header("Access-Control-Max-Age","1728000");
    next();
}

// Support CORS
app.options('/result', supportCrossOriginScript);

app.post('/result', supportCrossOriginScript, function(req, res) {
    res.send('received');
    // do stuff with req
});

我想做app.all('/result'，…)也可以…

2014-05-05 23:47:25

其他回答

我们可以避免CORS，而是将请求转发到另一个服务器:

// config:
var public_folder = __dirname + '/public'
var apiServerHost = 'http://other.server'

// code:
console.log("starting server...");

var express = require('express');
var app = express();
var request = require('request');

// serve static files
app.use(express.static(public_folder));

// if not found, serve from another server
app.use(function(req, res) {
    var url = apiServerHost + req.url;
    req.pipe(request(url)).pipe(res);
});

app.listen(80, function(){
    console.log("server ready");
});

2016-05-15 08:45:22

以下是我的工作，希望它能帮助到别人!

const express = require('express');
const cors = require('cors');
let app = express();

app.use(cors({ origin: true }));

从https://expressjs.com/en/resources/middleware/cors.html#configuring-cors获得参考

2019-03-15 09:02:13

我发现用npm request包(https://www.npmjs.com/package/request)非常容易做到这一点。

然后我根据这个帖子http://blog.javascripting.com/2015/01/17/dont-hassle-with-cors/给出了我的解决方案

'use strict'

const express = require('express');
const request = require('request');

let proxyConfig = {
    url : {
        base: 'http://servertoreach.com?id=',
    }
}

/* setting up and configuring node express server for the application */
let server = express();
server.set('port', 3000);


/* methods forwarded to the servertoreach proxy  */
server.use('/somethingElse', function(req, res)
{
    let url = proxyConfig.url.base + req.query.id;
    req.pipe(request(url)).pipe(res);
});


/* start the server */
server.listen(server.get('port'), function() {
    console.log('express server with a proxy listening on port ' + server.get('port'));
});

2016-02-10 13:06:18

我在我的server.js文件中使用了下面的方法。这里的关键部分是从请求头中获取起源，然后在服务器响应中允许它，此时我们可以设置将返回的头，包括如果找到匹配则允许的起源。

    **const origin = req.headers.origin;**

      let decoder = new StringDecoder('utf-8');
      let buffer = '';
      req.on('data', function (data) {
        buffer += decoder.write(data);
      });
      req.on('end', function () {
        buffer += decoder.end();

        let chosenHandler = typeof (server.router[trimmedPath]) !== 'undefined' ? server.router[trimmedPath] : handlers.notFound;

const data = { ....data object vars}

// should be wrapped in try catch block
      chosenHandler(data, function (statusCode, payload, contentType) {
        server.processHandlerResponse(res, method, trimmedPath, statusCode, payload, contentType, **origin**);


server.processHandlerResponse = function (res, method, trimmedPath, statusCode, payload, contentType, origin) {
  contentType = typeof (contentType) == 'string' ? contentType : 'json';

  statusCode = typeof (statusCode) == 'number' ? statusCode : 200;

  let payloadString = '';
  if (contentType == 'json') {
    res.setHeader('Content-Type', 'application/json');

    const allowedOrigins = ['https://www.domain1.com', 'https://someotherdomain','https://yetanotherdomain',
    ...// as many as you need
  ];
    **if (allowedOrigins.indexOf(origin) > -1) {
        res.setHeader('Access-Control-Allow-Origin', origin);
    }**
    payload = typeof (payload) == 'object' ? payload : {};
    payloadString = JSON.stringify(payload);
  }

... //  if (other content type) ...rinse and repeat..

2019-03-02 07:40:51

在你的主js文件中试试这个:

app.use((req, res, next) => {
res.header("Access-Control-Allow-Origin", "*");
res.header(
  "Access-Control-Allow-Headers",
  "Authorization, X-API-KEY, Origin, X-Requested-With, Content-Type, Accept, Access-Control-Allow-Request-Method"
);
res.header("Access-Control-Allow-Methods", "GET, POST, OPTIONS, PUT, DELETE");
res.header("Allow", "GET, POST, OPTIONS, PUT, DELETE");
next();
});

这应该能解决你的问题

2020-04-10 20:20:43

为什么不添加CORS头选项路由允许浏览器访问我的API?

推荐文章

最新文章

标签