我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
当前回答
在java中你可以使用这种方法。
private String getHmaa(long seconds) {
String string;
int hours = (int) seconds / 3600;
int remainder = (int) seconds - hours * 3600;
int mins = remainder / 60;
//remainder = remainder - mins * 60;
//int secs = remainder;
if (hours < 12 && hours > 0) {
if (mins < 10) {
string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
} else {
string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? mins : "0") + " AM");
}
} else if (hours >= 12) {
if (mins < 10) {
string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? "0" + mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
} else {
string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
}
} else {
if (mins < 10) {
string = String.valueOf("0" + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
} else {
string = String.valueOf("0" + ":" + (mins > 0 ? mins : "0") + " AM");
}
}
return string;
}
其他回答
试试这个:
date("H:i:s",-57600 + 685);
从 http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss
$given = 685;
/*
* In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
* We would need to take this into consideration, and so we will first
* check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
* and then after multiplying it by the number of hours in a day (24), we
* will just use "floor" to get the number of hours as the rest would
* be the minutes and seconds anyways.
*
* We can also have minutes and seconds combined in one variable,
* e.g. $min_sec = gmdate( "i:s", $given );
* But for versatility sake, I have taken them separately.
*/
$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );
$min = gmdate( "i", $given );
$sec = gmdate( "s", $given );
echo $formatted_string = $hours.':'.$min.':'.$sec;
将其转换为函数:
function getHoursFormat( $given ){
$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );
$min = gmdate( "i", $given );
$sec = gmdate( "s", $given );
$formatted_string = $hours.':'.$min.':'.$sec;
return $formatted_string;
}
仅当秒数小于86400(1天)时使用函数gmdate():
$seconds = 8525;
echo gmdate('H:i:s', $seconds);
# 02:22:05
参见: gmdate()
运行Demo
将秒转换为“脚”格式无限制*:
$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05
参见:floor(), sprintf(),算术运算符
运行Demo
DateTime扩展的示例使用:
$seconds = 8525;
$zero = new DateTime("@0");
$offset = new DateTime("@$seconds");
$diff = $zero->diff($offset);
echo sprintf("%02d:%02d:%02d", $diff->days * 24 + $diff->h, $diff->i, $diff->s);
# 02:22:05
参见:DateTime::__construct(), DateTime::modify(), clone, sprintf ()
运行Demo
MySQL示例的结果范围被限制为TIME数据类型,从-838:59:59到838:59:59:
SELECT SEC_TO_TIME(8525);
# 02:22:05
看:SEC_TO_TIME
运行Demo
PostgreSQL的例子:
SELECT TO_CHAR('8525 second'::interval, 'HH24:MI:SS');
# 02:22:05
运行Demo
不知道为什么还没有提出这个建议,但是这里有一个使用DateInterval的变体,它的优点是秒> 86400不是问题(只是不要期望小时< 24)
noteable:该函数返回DateInterval对象,因此输出格式由调用者决定
function seconds2interval($seconds) {
$s = intval($seconds);
$hrs = floor($s / 3600);
$min = floor(($s - ($hrs * 3600)) / 60);
$sec = $s % 60;
$duration = sprintf('PT%dH%dM%dS', $hrs, $min, $sec);
$d = new DateInterval($duration);
return $d;
}
$d = seconds2interval(93837.3113);
echo $d->format('%H:%I:%s'); // 26:03:57
其他解决方案使用gmdate,但在超过86400秒的边缘情况下会失败。为了解决这个问题,我们可以自己简单地计算小时数,然后让gmdate将剩余的秒计算为分/秒。
echo floor($seconds / 3600) . gmdate(":i:s", $seconds % 3600);
输入:6030 输出:1:40:30
输入:2000006030 输出:555557:13:50