我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
我需要将秒转换为“小时:分钟:秒”。
例如:“685”转换为“00:11:25”
我怎样才能做到这一点呢?
当前回答
在java中你可以使用这种方法。
private String getHmaa(long seconds) {
String string;
int hours = (int) seconds / 3600;
int remainder = (int) seconds - hours * 3600;
int mins = remainder / 60;
//remainder = remainder - mins * 60;
//int secs = remainder;
if (hours < 12 && hours > 0) {
if (mins < 10) {
string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
} else {
string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? mins : "0") + " AM");
}
} else if (hours >= 12) {
if (mins < 10) {
string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? "0" + mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
} else {
string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
}
} else {
if (mins < 10) {
string = String.valueOf("0" + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
} else {
string = String.valueOf("0" + ":" + (mins > 0 ? mins : "0") + " AM");
}
}
return string;
}
其他回答
下面是一个处理负秒和超过1天的秒的一行程序。
sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));
例如:
$seconds= -24*60*60 - 2*60*60 - 3*60 - 4; // minus 1 day 2 hours 3 minutes 4 seconds
echo sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));
输出:26:03:04
See:
/**
* Convert number of seconds into hours, minutes and seconds
* and return an array containing those values
*
* @param integer $inputSeconds Number of seconds to parse
* @return array
*/
function secondsToTime($inputSeconds) {
$secondsInAMinute = 60;
$secondsInAnHour = 60 * $secondsInAMinute;
$secondsInADay = 24 * $secondsInAnHour;
// extract days
$days = floor($inputSeconds / $secondsInADay);
// extract hours
$hourSeconds = $inputSeconds % $secondsInADay;
$hours = floor($hourSeconds / $secondsInAnHour);
// extract minutes
$minuteSeconds = $hourSeconds % $secondsInAnHour;
$minutes = floor($minuteSeconds / $secondsInAMinute);
// extract the remaining seconds
$remainingSeconds = $minuteSeconds % $secondsInAMinute;
$seconds = ceil($remainingSeconds);
// return the final array
$obj = array(
'd' => (int) $days,
'h' => (int) $hours,
'm' => (int) $minutes,
's' => (int) $seconds,
);
return $obj;
}
From:将秒转换为日、时、分和秒
给你
function format_time($t,$f=':') // t = seconds, f = separator
{
return sprintf("%02d%s%02d%s%02d", floor($t/3600), $f, ($t/60)%60, $f, $t%60);
}
echo format_time(685); // 00:11:25
仅当秒数小于86400(1天)时使用函数gmdate():
$seconds = 8525;
echo gmdate('H:i:s', $seconds);
# 02:22:05
参见: gmdate()
运行Demo
将秒转换为“脚”格式无限制*:
$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05
参见:floor(), sprintf(),算术运算符
运行Demo
DateTime扩展的示例使用:
$seconds = 8525;
$zero = new DateTime("@0");
$offset = new DateTime("@$seconds");
$diff = $zero->diff($offset);
echo sprintf("%02d:%02d:%02d", $diff->days * 24 + $diff->h, $diff->i, $diff->s);
# 02:22:05
参见:DateTime::__construct(), DateTime::modify(), clone, sprintf ()
运行Demo
MySQL示例的结果范围被限制为TIME数据类型,从-838:59:59到838:59:59:
SELECT SEC_TO_TIME(8525);
# 02:22:05
看:SEC_TO_TIME
运行Demo
PostgreSQL的例子:
SELECT TO_CHAR('8525 second'::interval, 'HH24:MI:SS');
# 02:22:05
运行Demo
gmdate("H:i:s", no_of_seconds);
如果no_of_seconds大于1天(一天中的秒数),将不会以H:i:s格式给出时间。 它将忽略日值,只给出小时:分钟:秒
例如:
gmdate("H:i:s", 89922); // returns 0:58:42 not (1 Day 0:58:42) or 24:58:42