日历火

从那里你可以看到那个日历。month_name[3]将返回March，数组索引为0是空字符串，因此也不需要担心零索引。

datetime -基本日期和时间类型- Python文档

所有strftime格式代码的列表。月份的名称，以及格式化左零填充之类的好东西。阅读整页的内容，比如“天真”参数的规则。以下是清单的简要内容:

%a  Sun, Mon, …, Sat 
%A  Sunday, Monday, …, Saturday 
%w  Weekday as number, where 0 is Sunday 
%d  Day of the month 01, 02, …, 31
%b  Jan, Feb, …, Dec
%B  January, February, …, December
%m  Month number as a zero-padded 01, 02, …, 12
%y  2 digit year zero-padded 00, 01, …, 99
%Y  4 digit Year 1970, 1988, 2001, 2013
%H  Hour (24-hour clock) zero-padded 00, 01, …, 23
%I  Hour (12-hour clock) zero-padded 01, 02, …, 12
%p  AM or PM.
%M  Minute zero-padded 00, 01, …, 59
%S  Second zero-padded 00, 01, …, 59
%f  Microsecond zero-padded 000000, 000001, …, 999999
%z  UTC offset in the form +HHMM or -HHMM   +0000, -0400, +1030
%Z  Time zone name  UTC, EST, CST
%j  Day of the year zero-padded 001, 002, …, 366
%U  Week number of the year zero padded, Days before the first Sunday are week 0
%W  Week number of the year (Monday as first day)
%c  Locale’s date and time representation. Tue Aug 16 21:30:00 1988
%x  Locale’s date representation. 08/16/1988 (en_US)
%X  Locale’s time representation. 21:30:00 
%%  literal '%' character.

import datetime
mydate = datetime.datetime.now()
mydate.strftime("%B") # 'December'
mydate.strftime("%b") # 'dec'

这就是我要做的:

from datetime import *

months = ["Unknown",
          "January",
          "Febuary",
          "March",
          "April",
          "May",
          "June",
          "July",
          "August",
          "September",
          "October",
          "November",
          "December"]

now = (datetime.now())
year = (now.year)
month = (months[now.month])
print(month)

输出:

>>> September

(这是我写这篇文章的真实日期)

这个脚本展示了如何获得数据帧中月份变量/列的日历月缩写。注意，假设month列/变量的值都是数字，可能会有一些缺失的值。

# Import the calendar module
  import calendar
    
# Extract month as a number from the date column
  df['Month']=pd.DatetimeIndex(df['Date']).month

# Using list comprehension extract month abbreviations for each month number
 df['Month_abbr']=[calendar.month_abbr[int(i)] if pd.notna(i) else i for i in df['Month']]

对于任意范围的月份数字

month_integer=range(0,100)
map(lambda x: calendar.month_name[x%12+start],month_integer)

将产生正确的列表。从月份-整数列表中一月份开始的位置调整start-parameter。