我试图使用Node.js获取目录中所有文件的名称列表。我希望输出文件名数组。我该怎么做?
当前回答
采用@湖南罗斯托米扬的一般方法,使其更加简洁,并添加了excludeDirs论点。使用includeDirs进行扩展很简单,只需遵循相同的模式:
import * as fs from 'fs';
import * as path from 'path';
function fileList(dir, excludeDirs?) {
return fs.readdirSync(dir).reduce(function (list, file) {
const name = path.join(dir, file);
if (fs.statSync(name).isDirectory()) {
if (excludeDirs && excludeDirs.length) {
excludeDirs = excludeDirs.map(d => path.normalize(d));
const idx = name.indexOf(path.sep);
const directory = name.slice(0, idx === -1 ? name.length : idx);
if (excludeDirs.indexOf(directory) !== -1)
return list;
}
return list.concat(fileList(name, excludeDirs));
}
return list.concat([name]);
}, []);
}
示例用法:
console.log(fileList('.', ['node_modules', 'typings', 'bower_components']));
其他回答
这将起作用,并将结果存储在test.txt文件中,该文件将位于同一目录中
fs.readdirSync(__dirname).forEach(file => {
fs.appendFileSync("test.txt", file+"\n", function(err){
})
})
如果上面的许多选项看起来太复杂,或者不是您想要的,这里是另一种使用node-dir的方法https://github.com/fshost/node-dir
npm install node-dir
下面是一个somple函数,用于列出在子目录中搜索的所有.xml文件
import * as nDir from 'node-dir' ;
listXMLs(rootFolderPath) {
let xmlFiles ;
nDir.files(rootFolderPath, function(err, items) {
xmlFiles = items.filter(i => {
return path.extname(i) === '.xml' ;
}) ;
console.log(xmlFiles) ;
});
}
我通常使用:FS Extra。
const fileNameArray = Fse.readdir('/some/path');
结果:
[
"b7c8a93c-45b3-4de8-b9b5-a0bf28fb986e.jpg",
"daeb1c5b-809f-4434-8fd9-410140789933.jpg"
]
它只有2行代码:
fs=require('fs')
fs.readdir("./img/", (err,filename)=>console.log(filename))
图像:
这是一个TypeScript,可选递归,可选错误日志和异步解决方案。可以为要查找的文件名指定正则表达式。
我使用了fs extra,因为这是对fs的一个简单的超集改进。
import * as FsExtra from 'fs-extra'
/**
* Finds files in the folder that match filePattern, optionally passing back errors .
* If folderDepth isn't specified, only the first level is searched. Otherwise anything up
* to Infinity is supported.
*
* @static
* @param {string} folder The folder to start in.
* @param {string} [filePattern='.*'] A regular expression of the files you want to find.
* @param {(Error[] | undefined)} [errors=undefined]
* @param {number} [folderDepth=0]
* @returns {Promise<string[]>}
* @memberof FileHelper
*/
public static async findFiles(
folder: string,
filePattern: string = '.*',
errors: Error[] | undefined = undefined,
folderDepth: number = 0
): Promise<string[]> {
const results: string[] = []
// Get all files from the folder
let items = await FsExtra.readdir(folder).catch(error => {
if (errors) {
errors.push(error) // Save errors if we wish (e.g. folder perms issues)
}
return results
})
// Go through to the required depth and no further
folderDepth = folderDepth - 1
// Loop through the results, possibly recurse
for (const item of items) {
try {
const fullPath = Path.join(folder, item)
if (
FsExtra.statSync(fullPath).isDirectory() &&
folderDepth > -1)
) {
// Its a folder, recursively get the child folders' files
results.push(
...(await FileHelper.findFiles(fullPath, filePattern, errors, folderDepth))
)
} else {
// Filter by the file name pattern, if there is one
if (filePattern === '.*' || item.search(new RegExp(filePattern, 'i')) > -1) {
results.push(fullPath)
}
}
} catch (error) {
if (errors) {
errors.push(error) // Save errors if we wish
}
}
}
return results
}