我试图使用Node.js获取目录中所有文件的名称列表。我希望输出文件名数组。我该怎么做?
当前回答
这是一个TypeScript,可选递归,可选错误日志和异步解决方案。可以为要查找的文件名指定正则表达式。
我使用了fs extra,因为这是对fs的一个简单的超集改进。
import * as FsExtra from 'fs-extra'
/**
* Finds files in the folder that match filePattern, optionally passing back errors .
* If folderDepth isn't specified, only the first level is searched. Otherwise anything up
* to Infinity is supported.
*
* @static
* @param {string} folder The folder to start in.
* @param {string} [filePattern='.*'] A regular expression of the files you want to find.
* @param {(Error[] | undefined)} [errors=undefined]
* @param {number} [folderDepth=0]
* @returns {Promise<string[]>}
* @memberof FileHelper
*/
public static async findFiles(
folder: string,
filePattern: string = '.*',
errors: Error[] | undefined = undefined,
folderDepth: number = 0
): Promise<string[]> {
const results: string[] = []
// Get all files from the folder
let items = await FsExtra.readdir(folder).catch(error => {
if (errors) {
errors.push(error) // Save errors if we wish (e.g. folder perms issues)
}
return results
})
// Go through to the required depth and no further
folderDepth = folderDepth - 1
// Loop through the results, possibly recurse
for (const item of items) {
try {
const fullPath = Path.join(folder, item)
if (
FsExtra.statSync(fullPath).isDirectory() &&
folderDepth > -1)
) {
// Its a folder, recursively get the child folders' files
results.push(
...(await FileHelper.findFiles(fullPath, filePattern, errors, folderDepth))
)
} else {
// Filter by the file name pattern, if there is one
if (filePattern === '.*' || item.search(new RegExp(filePattern, 'i')) > -1) {
results.push(fullPath)
}
}
} catch (error) {
if (errors) {
errors.push(error) // Save errors if we wish
}
}
}
return results
}
其他回答
IMO完成此类任务最方便的方法是使用glob工具。这是node.js的glob包
npm install glob
然后使用通配符匹配文件名(示例取自软件包的网站)
var glob = require("glob")
// options is optional
glob("**/*.js", options, function (er, files) {
// files is an array of filenames.
// If the `nonull` option is set, and nothing
// was found, then files is ["**/*.js"]
// er is an error object or null.
})
如果您计划使用globby,这里有一个示例来查找当前文件夹下的任何xml文件
var globby = require('globby');
const paths = await globby("**/*.xml");
这是一个异步递归版本。
function ( path, callback){
// the callback gets ( err, files) where files is an array of file names
if( typeof callback !== 'function' ) return
var
result = []
, files = [ path.replace( /\/\s*$/, '' ) ]
function traverseFiles (){
if( files.length ) {
var name = files.shift()
fs.stat(name, function( err, stats){
if( err ){
if( err.errno == 34 ) traverseFiles()
// in case there's broken symbolic links or a bad path
// skip file instead of sending error
else callback(err)
}
else if ( stats.isDirectory() ) fs.readdir( name, function( err, files2 ){
if( err ) callback(err)
else {
files = files2
.map( function( file ){ return name + '/' + file } )
.concat( files )
traverseFiles()
}
})
else{
result.push(name)
traverseFiles()
}
})
}
else callback( null, result )
}
traverseFiles()
}
我最近为此开发了一个工具,它可以做到这一点。。。它异步获取目录并返回项目列表。您可以获取目录、文件或两者,首先是文件夹。如果不想获取整个文件夹,也可以对数据进行分页。
https://www.npmjs.com/package/fs-browser
这是链接,希望它能帮助到某人!
如果上面的许多选项看起来太复杂,或者不是您想要的,这里是另一种使用node-dir的方法https://github.com/fshost/node-dir
npm install node-dir
下面是一个somple函数,用于列出在子目录中搜索的所有.xml文件
import * as nDir from 'node-dir' ;
listXMLs(rootFolderPath) {
let xmlFiles ;
nDir.files(rootFolderPath, function(err, items) {
xmlFiles = items.filter(i => {
return path.extname(i) === '.xml' ;
}) ;
console.log(xmlFiles) ;
});
}
这是一个TypeScript,可选递归,可选错误日志和异步解决方案。可以为要查找的文件名指定正则表达式。
我使用了fs extra,因为这是对fs的一个简单的超集改进。
import * as FsExtra from 'fs-extra'
/**
* Finds files in the folder that match filePattern, optionally passing back errors .
* If folderDepth isn't specified, only the first level is searched. Otherwise anything up
* to Infinity is supported.
*
* @static
* @param {string} folder The folder to start in.
* @param {string} [filePattern='.*'] A regular expression of the files you want to find.
* @param {(Error[] | undefined)} [errors=undefined]
* @param {number} [folderDepth=0]
* @returns {Promise<string[]>}
* @memberof FileHelper
*/
public static async findFiles(
folder: string,
filePattern: string = '.*',
errors: Error[] | undefined = undefined,
folderDepth: number = 0
): Promise<string[]> {
const results: string[] = []
// Get all files from the folder
let items = await FsExtra.readdir(folder).catch(error => {
if (errors) {
errors.push(error) // Save errors if we wish (e.g. folder perms issues)
}
return results
})
// Go through to the required depth and no further
folderDepth = folderDepth - 1
// Loop through the results, possibly recurse
for (const item of items) {
try {
const fullPath = Path.join(folder, item)
if (
FsExtra.statSync(fullPath).isDirectory() &&
folderDepth > -1)
) {
// Its a folder, recursively get the child folders' files
results.push(
...(await FileHelper.findFiles(fullPath, filePattern, errors, folderDepth))
)
} else {
// Filter by the file name pattern, if there is one
if (filePattern === '.*' || item.search(new RegExp(filePattern, 'i')) > -1) {
results.push(fullPath)
}
}
} catch (error) {
if (errors) {
errors.push(error) // Save errors if we wish
}
}
}
return results
}