如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
当前回答
var data= {
myAction: function(array){
return array.filter(function(el){
return (el !== (undefined || null || ''));
}).join(" ");
}
};
var string = data.myAction(["I", "am","", "working", "", "on","", "nodejs", "" ]);
console.log(string);
输出:
我正在研究nodejs
它将从数组中删除空元素并显示其他元素。
其他回答
那怎么办
js> [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,].filter(String).join(',')
1,2,3,3,0,4,4,5,6
如果有人想要清理整个阵列或对象,这可能会有所帮助。
var qwerty = {
test1: null,
test2: 'somestring',
test3: 3,
test4: {},
test5: {
foo: "bar"
},
test6: "",
test7: undefined,
test8: " ",
test9: true,
test10: [],
test11: ["77","88"],
test12: {
foo: "foo",
bar: {
foo: "q",
bar: {
foo:4,
bar:{}
}
},
bob: {}
}
}
var asdfg = [,,"", " ", "yyyy", 78, null, undefined,true, {}, {x:6}, [], [2,3,5]];
function clean_data(obj) {
for (var key in obj) {
// Delete null, undefined, "", " "
if (obj[key] === null || obj[key] === undefined || obj[key] === "" || obj[key] === " ") {
delete obj[key];
}
// Delete empty object
// Note : typeof Array is also object
if (typeof obj[key] === 'object' && Object.keys(obj[key]).length <= 0) {
delete obj[key];
}
// If non empty object call function again
if(typeof obj[key] === 'object'){
clean_data(obj[key]);
}
}
return obj;
}
var objData = clean_data(qwerty);
console.log(objData);
var arrayData = clean_data(asdfg);
console.log(arrayData);
输出:
删除任何null、undefined、“”、“”空对象或空数组
jsfiddle在这里
您应该使用filter获取不含空元素的数组。ES6示例
const array = [1, 32, 2, undefined, 3];
const newArray = array.filter(arr => arr);
就地解决方案:
function pack(arr) { // remove undefined values
let p = -1
for (let i = 0, len = arr.length; i < len; i++) {
if (arr[i] !== undefined) { if (p >= 0) { arr[p] = arr[i]; p++ } }
else if (p < 0) p = i
}
if (p >= 0) arr.length = p
return arr
}
let a = [1, 2, 3, undefined, undefined, 4, 5, undefined, null]
console.log(JSON.stringify(a))
pack(a)
console.log(JSON.stringify(a))
可以使用带有索引和in运算符的筛选器
设a=[1,,2,,,3];设b=a.filter((x,i)=>a中的i);console.log({a,b});