那怎么办

js> [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,].filter(String).join(',')
1,2,3,3,0,4,4,5,6

可以使用带有索引和in运算符的筛选器

设a=[1，，2，，，3]；设b=a.filter（（x，i）=>a中的i）；console.log（｛a，b｝）；

如果有人想要清理整个阵列或对象，这可能会有所帮助。

var qwerty = {
    test1: null,
    test2: 'somestring',
    test3: 3,
    test4: {},
    test5: {
        foo: "bar"
    },
    test6: "",
    test7: undefined,
    test8: " ",
    test9: true,
    test10: [],
    test11: ["77","88"],
    test12: {
        foo: "foo",
        bar: {
            foo: "q",
            bar: {
                foo:4,
                bar:{}
            }
        },
        bob: {}
    }
}

var asdfg = [,,"", " ", "yyyy", 78, null, undefined,true, {}, {x:6}, [], [2,3,5]];

function clean_data(obj) {
    for (var key in obj) {
        // Delete null, undefined, "", " "
        if (obj[key] === null || obj[key] === undefined || obj[key] === "" || obj[key] === " ") {
            delete obj[key];
        }
        // Delete empty object
        // Note : typeof Array is also object
        if (typeof obj[key] === 'object' && Object.keys(obj[key]).length <= 0) {
            delete obj[key];
        }
        // If non empty object call function again
        if(typeof obj[key] === 'object'){
            clean_data(obj[key]);
        }
    }
    return obj;
}

var objData = clean_data(qwerty);
console.log(objData);
var arrayData = clean_data(asdfg);
console.log(arrayData);

输出：

删除任何null、undefined、“”、“”空对象或空数组

jsfiddle在这里

这是我清理空字段的解决方案。

从费用对象开始：仅获取可用属性（带贴图）筛选空字段（带筛选器）将结果解析为整数（带映射）

fees.map( ( e ) => e.avail ).filter( v => v!== '').map( i => parseInt( i ) );

这是另一种方法：

var arr = ["a", "b", undefined, undefined, "e", undefined, "g", undefined, "i", "", "k"]
var cleanArr = arr.join('.').split(/\.+/);

简单ES6

['a','b','',,,'w','b'].filter(v => v);