如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
如何在JavaScript中删除数组中的空元素?
是否有一种简单的方法,或者我需要循环并手动删除它们?
当前回答
这可能会帮助您:https://lodash.com/docs/4.17.4#remove
var details = [
{
reference: 'ref-1',
description: 'desc-1',
price: 1
}, {
reference: '',
description: '',
price: ''
}, {
reference: 'ref-2',
description: 'desc-2',
price: 200
}, {
reference: 'ref-3',
description: 'desc-3',
price: 3
}, {
reference: '',
description: '',
price: ''
}
];
scope.removeEmptyDetails(details);
expect(details.length).toEqual(3);
scope.removeEmptyDetails = function(details){
_.remove(details, function(detail){
return (_.isEmpty(detail.reference) && _.isEmpty(detail.description) && _.isEmpty(detail.price));
});
};
其他回答
几个简单的方法:
var arr = [1,2,,3,,-3,null,,0,,undefined,4,,4,,5,,6,,,,];
arr.filter(n => n)
// [1, 2, 3, -3, 4, 4, 5, 6]
arr.filter(Number)
// [1, 2, 3, -3, 4, 4, 5, 6]
arr.filter(Boolean)
// [1, 2, 3, -3, 4, 4, 5, 6]
或-(仅适用于“text”类型的单个数组项)
['','1','2',3,,'4',,undefined,,,'5'].join('').split('');
// output: ["1","2","3","4","5"]
或-经典方式:简单迭代
var arr = [1,2,null, undefined,3,,3,,,0,,,[],,{},,5,,6,,,,],
len = arr.length, i;
for(i = 0; i < len; i++ )
arr[i] && arr.push(arr[i]); // copy non-empty values to the end of the array
arr.splice(0 , len); // cut the array and leave only the non-empty values
// [1,2,3,3,[],Object{},5,6]
jQuery:
var arr = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
arr = $.grep(arr, n => n == 0 || n);
// [1, 2, 3, 3, 0, 4, 4, 5, 6]
以上答案都不适用于所有类型。下面的解决方案将删除null、undefined、{}[]、NaN,并保留日期字符串,最好的是它甚至从嵌套对象中删除。
function removeNil(obj) {
// recursively remove null and undefined from nested object too.
return JSON.parse(JSON.stringify(obj), (k,v) => {
if(v === null || v === '') return undefined;
// convert date string to date.
if (typeof v === "string" && /^\d\d\d\d-\d\d-\d\dT\d\d:\d\d:\d\d.\d\d\dZ$/.test(v))
return new Date(v);
// remove empty array and object.
if(typeof v === 'object' && !Object.keys(v).length) return undefined;
return v;
});
}
函数removeNil(obj){//递归地从嵌套对象中删除null和undefined。返回JSON.parse(JSON.stringify(obj),(k,v)=>{如果(v===null||v==='')返回undefined;//将日期字符串转换为日期。if(typeof v==“string”&&/^\d\d\d\d-\d\dT\dd:\d\d:\d\d.d.d\dZ$/.test(v))返回新日期(v);//删除空数组和对象。if(typeof v=='object'&&!object.keys(v).length)返回undefined;返回v;});}常量ob={s: “a”,b: 43中,国家:['a','b','c'],l: 空,n: {ks:“a”,efe:null,ce:“”},d: new Date(),nan:nan,k: 未定义,emptyO:{},emptyArr:[],}常量输出=removeNil(ob);console.log(输出);console.log('测试:',ob.countries.length,typeof(ob.d))
如果有人想要清理整个阵列或对象,这可能会有所帮助。
var qwerty = {
test1: null,
test2: 'somestring',
test3: 3,
test4: {},
test5: {
foo: "bar"
},
test6: "",
test7: undefined,
test8: " ",
test9: true,
test10: [],
test11: ["77","88"],
test12: {
foo: "foo",
bar: {
foo: "q",
bar: {
foo:4,
bar:{}
}
},
bob: {}
}
}
var asdfg = [,,"", " ", "yyyy", 78, null, undefined,true, {}, {x:6}, [], [2,3,5]];
function clean_data(obj) {
for (var key in obj) {
// Delete null, undefined, "", " "
if (obj[key] === null || obj[key] === undefined || obj[key] === "" || obj[key] === " ") {
delete obj[key];
}
// Delete empty object
// Note : typeof Array is also object
if (typeof obj[key] === 'object' && Object.keys(obj[key]).length <= 0) {
delete obj[key];
}
// If non empty object call function again
if(typeof obj[key] === 'object'){
clean_data(obj[key]);
}
}
return obj;
}
var objData = clean_data(qwerty);
console.log(objData);
var arrayData = clean_data(asdfg);
console.log(arrayData);
输出:
删除任何null、undefined、“”、“”空对象或空数组
jsfiddle在这里
这是可行的,我在AppJet中测试了它(你可以复制粘贴代码到它的IDE上,然后按“reload”查看它的工作情况,不需要创建帐户)
/* appjet:version 0.1 */
function Joes_remove(someArray) {
var newArray = [];
var element;
for( element in someArray){
if(someArray[element]!=undefined ) {
newArray.push(someArray[element]);
}
}
return newArray;
}
var myArray2 = [1,2,,3,,3,,,0,,,4,,4,,5,,6,,,,];
print("Original array:", myArray2);
print("Clenased array:", Joes_remove(myArray2) );
/*
Returns: [1,2,3,3,0,4,4,5,6]
*/
要从数组中删除未定义的元素,只需使用
常量数组=[{name:“tim”,年龄:1},未定义,{姓名:“ewrfer”,年龄:22岁},{姓名:“3tf5gh”,年龄:56},无效的{姓名:“kygm”,年龄:19岁},未定义,];console.log(array.filter(布尔));