在我的节点应用程序中,我需要删除一个目录,其中有一些文件,但fs。Rmdir只适用于空目录。我该怎么做呢?


当前回答

如果你正在使用的节点8+想要异步,不想要外部依赖,这里是async/await版本:

const path = require('path');
const fs = require('fs');
const util = require('util');

const readdir = util.promisify(fs.readdir);
const lstat = util.promisify(fs.lstat);
const unlink = util.promisify(fs.unlink);
const rmdir = util.promisify(fs.rmdir);

const removeDir = async (dir) => {
    try {
        const files = await readdir(dir);
        await Promise.all(files.map(async (file) => {
            try {
                const p = path.join(dir, file);
                const stat = await lstat(p);
                if (stat.isDirectory()) {
                    await removeDir(p);
                } else {
                    await unlink(p);
                    console.log(`Removed file ${p}`);
                }
            } catch (err) {
                console.error(err);
            }
        }))
        await rmdir(dir);
        console.log(`Removed dir ${dir}`);
    } catch (err) {
      console.error(err);
    }
}

其他回答

方法删除非空目录

rmdir(path,{recursive:true,force:true}
rm(path,{recursive:true,force:true}

将工作

代码片段:

const fsp = require("fs/promises");

deleteDirRecursively("./b");
removeRecursively("./BCD/b+");

async function deleteDirRecursively(dirPath) {
  try {
    // fsPromises.rmdir() on a file (not a directory) results in the promise being rejected
    // with an ENOENT error on Windows and an ENOTDIR error on POSIX.
    // To get a behavior similar to the rm -rf Unix command,
    // use fsPromises.rm() with options { recursive: true, force: true }.
    //will not thorw error if dir is empty
    //will thow error if dir is not present
    await fsp.rmdir(dirPath, { recursive: true, force: true });
    console.log(dirPath, "deleted successfully");
  } catch (err) {
    console.log(err);
  }

async function removeRecursively(path) {
  try {
    //has ability to remove both file and dir
    //can delete dir recursively and forcefully
    //will delete an empty dir.
    //will remove all the contents of a dir.
    // the only difference between rmdir and rm is that rmdir can only delete dir's
    await fsp.rm(path, { recursive: true, force: true });
    console.log(path, "deleted successfully");
  } catch (err) {
    console.log(err);
  }
}

我到达这里时,试图克服与大口,我正在写进一步达到。

对于gulp-rimraf,已弃用Gulp-clean Gulp-rimraf已弃用,支持delete-files-folders

当要使用del删除文件和文件夹时,应添加/**进行递归删除。

gulp.task('clean', function () {
    return del(['some/path/to/delete/**']);
});

❄️您可以使用graph-fs

directory.delete()

大多数在Node.js中使用fs的人都希望函数能够接近“Unix方式”来处理文件。我使用fs-extra来带来所有很酷的东西:

fs-extra包含了普通Node.js中不包含的方法 fs包。如mkdir -p、cp -r、rm -rf等。

更好的是,fs-extra是本地fs的替代品。fs中的所有方法都是未修改的,并附加到它。 这意味着你可以用fs-extra替换fs:

// this can be replaced
const fs = require('fs')

// by this
const fs = require('fs-extra')

然后你可以这样删除一个文件夹:

fs.removeSync('/tmp/myFolder'); 
//or
fs.remove('/tmp/myFolder', callback);

有一个模块叫做rimraf (https://npmjs.org/package/rimraf)。它提供了与rm -Rf相同的功能

异步用法:

var rimraf = require("rimraf");
rimraf("/some/directory", function () { console.log("done"); });

同步用法:

rimraf.sync("/some/directory");