方法删除非空目录

rmdir(path,{recursive:true,force:true}
rm(path,{recursive:true,force:true}

将工作

代码片段:

const fsp = require("fs/promises");

deleteDirRecursively("./b");
removeRecursively("./BCD/b+");

async function deleteDirRecursively(dirPath) {
  try {
    // fsPromises.rmdir() on a file (not a directory) results in the promise being rejected
    // with an ENOENT error on Windows and an ENOTDIR error on POSIX.
    // To get a behavior similar to the rm -rf Unix command,
    // use fsPromises.rm() with options { recursive: true, force: true }.
    //will not thorw error if dir is empty
    //will thow error if dir is not present
    await fsp.rmdir(dirPath, { recursive: true, force: true });
    console.log(dirPath, "deleted successfully");
  } catch (err) {
    console.log(err);
  }

async function removeRecursively(path) {
  try {
    //has ability to remove both file and dir
    //can delete dir recursively and forcefully
    //will delete an empty dir.
    //will remove all the contents of a dir.
    // the only difference between rmdir and rm is that rmdir can only delete dir's
    await fsp.rm(path, { recursive: true, force: true });
    console.log(path, "deleted successfully");
  } catch (err) {
    console.log(err);
  }
}

我通常不复活旧线程，但这里有很多关于搅动和没有rimraf的答案，这些对我来说似乎都太复杂了。

首先，在现代Node (>= v8.0.0)中，你可以只使用节点核心模块来简化过程，完全异步，并在5行函数中并行化文件的解链接，并且仍然保持可读性:

const fs = require('fs');
const path = require('path');
const { promisify } = require('util');
const readdir = promisify(fs.readdir);
const rmdir = promisify(fs.rmdir);
const unlink = promisify(fs.unlink);

exports.rmdirs = async function rmdirs(dir) {
  let entries = await readdir(dir, { withFileTypes: true });
  await Promise.all(entries.map(entry => {
    let fullPath = path.join(dir, entry.name);
    return entry.isDirectory() ? rmdirs(fullPath) : unlink(fullPath);
  }));
  await rmdir(dir);
};

另一方面，路径遍历攻击的保护不适合此函数，因为

It is out of scope based on the Single Responsibility Principle. Should be handled by the caller not this function. This is akin to the command-line rm -rf in that it takes an argument and will allow the user to rm -rf / if asked to. It would be the responsibility of a script to guard not the rm program itself. This function would be unable to determine such an attack since it does not have a frame of reference. Again that is the responsibility of the caller who would have the context of intent which would provide it a reference to compare the path traversal. Sym-links are not a concern as .isDirectory() is false for sym-links and are unlinked not recursed into.

最后但并非最不重要的是，有一种罕见的竞争条件，即在运行递归时，如果在正确的时间在脚本之外取消链接或删除其中一个条目，则递归可能会出错。由于这种情况在大多数环境中并不典型，因此可能会被忽略。然而，如果需要(对于一些边缘情况)，这个问题可以通过下面这个稍微复杂一点的例子来缓解:

exports.rmdirs = async function rmdirs(dir) {
  let entries = await readdir(dir, { withFileTypes: true });
  let results = await Promise.all(entries.map(entry => {
    let fullPath = path.join(dir, entry.name);
    let task = entry.isDirectory() ? rmdirs(fullPath) : unlink(fullPath);
    return task.catch(error => ({ error }));
  }));
  results.forEach(result => {
    // Ignore missing files/directories; bail on other errors
    if (result && result.error.code !== 'ENOENT') throw result.error;
  });
  await rmdir(dir);
};

编辑:使isDirectory()成为一个函数。最后删除实际目录。修复丢失的递归。

我希望有一种方法可以做到这一点，而不需要为如此微小和常见的东西添加额外的模块，但这是我能想到的最好的方法。

更新: 现在应该在Windows上工作(测试Windows 10)，也应该在Linux/Unix/BSD/Mac系统上工作。

const
    execSync = require("child_process").execSync,
    fs = require("fs"),
    os = require("os");

let removeDirCmd, theDir;

removeDirCmd = os.platform() === 'win32' ? "rmdir /s /q " : "rm -rf ";

theDir = __dirname + "/../web-ui/css/";

// WARNING: Do not specify a single file as the windows rmdir command will error.
if (fs.existsSync(theDir)) {
    console.log(' removing the ' + theDir + ' directory.');
    execSync(removeDirCmd + '"' + theDir + '"', function (err) {
        console.log(err);
    });
}

方法删除非空目录

rmdir(path,{recursive:true,force:true}
rm(path,{recursive:true,force:true}

将工作

代码片段:

const fsp = require("fs/promises");

deleteDirRecursively("./b");
removeRecursively("./BCD/b+");

async function deleteDirRecursively(dirPath) {
  try {
    // fsPromises.rmdir() on a file (not a directory) results in the promise being rejected
    // with an ENOENT error on Windows and an ENOTDIR error on POSIX.
    // To get a behavior similar to the rm -rf Unix command,
    // use fsPromises.rm() with options { recursive: true, force: true }.
    //will not thorw error if dir is empty
    //will thow error if dir is not present
    await fsp.rmdir(dirPath, { recursive: true, force: true });
    console.log(dirPath, "deleted successfully");
  } catch (err) {
    console.log(err);
  }

async function removeRecursively(path) {
  try {
    //has ability to remove both file and dir
    //can delete dir recursively and forcefully
    //will delete an empty dir.
    //will remove all the contents of a dir.
    // the only difference between rmdir and rm is that rmdir can only delete dir's
    await fsp.rm(path, { recursive: true, force: true });
    console.log(path, "deleted successfully");
  } catch (err) {
    console.log(err);
  }
}

我到达这里时，试图克服与大口，我正在写进一步达到。

对于gulp-rimraf，已弃用Gulp-clean Gulp-rimraf已弃用，支持delete-files-folders

当要使用del删除文件和文件夹时，应添加/**进行递归删除。

gulp.task('clean', function () {
    return del(['some/path/to/delete/**']);
});

2020的答案

如果你想在npm脚本中完成它，如果你使用npx命令，你不需要预先安装任何第三方包

例如，如果你想在运行npm run clean时删除dist和.cache文件夹，那么只需将此命令添加到package.json中

{
  "scripts": {
    "clean": "npx rimraf dist .cache"
  }
}

它适用于任何操作系统