在我的节点应用程序中,我需要删除一个目录,其中有一些文件,但fs。Rmdir只适用于空目录。我该怎么做呢?
当前回答
我通常不复活旧线程,但这里有很多关于搅动和没有rimraf的答案,这些对我来说似乎都太复杂了。
首先,在现代Node (>= v8.0.0)中,你可以只使用节点核心模块来简化过程,完全异步,并在5行函数中并行化文件的解链接,并且仍然保持可读性:
const fs = require('fs');
const path = require('path');
const { promisify } = require('util');
const readdir = promisify(fs.readdir);
const rmdir = promisify(fs.rmdir);
const unlink = promisify(fs.unlink);
exports.rmdirs = async function rmdirs(dir) {
let entries = await readdir(dir, { withFileTypes: true });
await Promise.all(entries.map(entry => {
let fullPath = path.join(dir, entry.name);
return entry.isDirectory() ? rmdirs(fullPath) : unlink(fullPath);
}));
await rmdir(dir);
};
另一方面,路径遍历攻击的保护不适合此函数,因为
It is out of scope based on the Single Responsibility Principle. Should be handled by the caller not this function. This is akin to the command-line rm -rf in that it takes an argument and will allow the user to rm -rf / if asked to. It would be the responsibility of a script to guard not the rm program itself. This function would be unable to determine such an attack since it does not have a frame of reference. Again that is the responsibility of the caller who would have the context of intent which would provide it a reference to compare the path traversal. Sym-links are not a concern as .isDirectory() is false for sym-links and are unlinked not recursed into.
最后但并非最不重要的是,有一种罕见的竞争条件,即在运行递归时,如果在正确的时间在脚本之外取消链接或删除其中一个条目,则递归可能会出错。由于这种情况在大多数环境中并不典型,因此可能会被忽略。然而,如果需要(对于一些边缘情况),这个问题可以通过下面这个稍微复杂一点的例子来缓解:
exports.rmdirs = async function rmdirs(dir) {
let entries = await readdir(dir, { withFileTypes: true });
let results = await Promise.all(entries.map(entry => {
let fullPath = path.join(dir, entry.name);
let task = entry.isDirectory() ? rmdirs(fullPath) : unlink(fullPath);
return task.catch(error => ({ error }));
}));
results.forEach(result => {
// Ignore missing files/directories; bail on other errors
if (result && result.error.code !== 'ENOENT') throw result.error;
});
await rmdir(dir);
};
编辑:使isDirectory()成为一个函数。最后删除实际目录。修复丢失的递归。
其他回答
在Node.js的最新版本(12.10.0或更高版本)中,rmdir样式函数fs.rmdir()、fs.rmdirSync()和fs.promises.rmdir()有一个新的实验性选项递归,允许删除非空目录,例如:
fs.rmdir(path, { recursive: true });
GitHub上的相关PR: https://github.com/nodejs/node/pull/29168
同步删除文件夹
const fs = require('fs');
const Path = require('path');
const deleteFolderRecursive = function (directoryPath) {
if (fs.existsSync(directoryPath)) {
fs.readdirSync(directoryPath).forEach((file, index) => {
const curPath = path.join(directoryPath, file);
if (fs.lstatSync(curPath).isDirectory()) {
// recurse
deleteFolderRecursive(curPath);
} else {
// delete file
fs.unlinkSync(curPath);
}
});
fs.rmdirSync(directoryPath);
}
};
2020年更新
从12.10.0版本开始,为选项添加了recursiveOption。
注意,递归删除是实验性的。
所以你会做同步:
fs.rmdirSync(dir, {recursive: true});
或者async:
fs.rmdir(dir, {recursive: true});
2020的答案
如果你想在npm脚本中完成它,如果你使用npx命令,你不需要预先安装任何第三方包
例如,如果你想在运行npm run clean时删除dist和.cache文件夹,那么只需将此命令添加到package.json中
{
"scripts": {
"clean": "npx rimraf dist .cache"
}
}
它适用于任何操作系统
方法删除非空目录
rmdir(path,{recursive:true,force:true}
rm(path,{recursive:true,force:true}
将工作
代码片段:
const fsp = require("fs/promises");
deleteDirRecursively("./b");
removeRecursively("./BCD/b+");
async function deleteDirRecursively(dirPath) {
try {
// fsPromises.rmdir() on a file (not a directory) results in the promise being rejected
// with an ENOENT error on Windows and an ENOTDIR error on POSIX.
// To get a behavior similar to the rm -rf Unix command,
// use fsPromises.rm() with options { recursive: true, force: true }.
//will not thorw error if dir is empty
//will thow error if dir is not present
await fsp.rmdir(dirPath, { recursive: true, force: true });
console.log(dirPath, "deleted successfully");
} catch (err) {
console.log(err);
}
async function removeRecursively(path) {
try {
//has ability to remove both file and dir
//can delete dir recursively and forcefully
//will delete an empty dir.
//will remove all the contents of a dir.
// the only difference between rmdir and rm is that rmdir can only delete dir's
await fsp.rm(path, { recursive: true, force: true });
console.log(path, "deleted successfully");
} catch (err) {
console.log(err);
}
}
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