我如何通过编程方式获得正在运行我的android应用程序的设备的电话号码?
当前回答
虽然你可以有多个语音信箱帐号,但当你用自己的号码打电话时,运营商会把你转到语音信箱。因此,telephonymanager。getvoicemailnumber()或telephonymanager。getcompletevoicemailnumber(),这取决于你需要的风格。
希望这能有所帮助。
其他回答
以下是我找到的解决方案的组合(这里是示例项目,如果你也想检查自动填充):
清单
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
build.gradle
implementation "com.google.android.gms:play-services-auth:17.0.0"
MainActivity.kt
class MainActivity : AppCompatActivity() {
private lateinit var googleApiClient: GoogleApiClient
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
tryGetCurrentUserPhoneNumber(this)
googleApiClient = GoogleApiClient.Builder(this).addApi(Auth.CREDENTIALS_API).build()
if (phoneNumber.isEmpty()) {
val hintRequest = HintRequest.Builder().setPhoneNumberIdentifierSupported(true).build()
val intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest)
try {
startIntentSenderForResult(intent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0);
} catch (e: IntentSender.SendIntentException) {
Toast.makeText(this, "failed to show phone picker", Toast.LENGTH_SHORT).show()
}
} else
onGotPhoneNumberToSendTo()
}
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
if (requestCode == REQUEST_PHONE_NUMBER) {
if (resultCode == Activity.RESULT_OK) {
val cred: Credential? = data?.getParcelableExtra(Credential.EXTRA_KEY)
phoneNumber = cred?.id ?: ""
if (phoneNumber.isEmpty())
Toast.makeText(this, "failed to get phone number", Toast.LENGTH_SHORT).show()
else
onGotPhoneNumberToSendTo()
}
}
}
private fun onGotPhoneNumberToSendTo() {
Toast.makeText(this, "got number:$phoneNumber", Toast.LENGTH_SHORT).show()
}
companion object {
private const val REQUEST_PHONE_NUMBER = 1
private var phoneNumber = ""
@SuppressLint("MissingPermission", "HardwareIds")
private fun tryGetCurrentUserPhoneNumber(context: Context): String {
if (phoneNumber.isNotEmpty())
return phoneNumber
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
val subscriptionManager = context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
try {
subscriptionManager.activeSubscriptionInfoList?.forEach {
val number: String? = it.number
if (!number.isNullOrBlank()) {
phoneNumber = number
return number
}
}
} catch (ignored: Exception) {
}
}
try {
val telephonyManager = context.getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
val number = telephonyManager.line1Number ?: ""
if (!number.isBlank()) {
phoneNumber = number
return number
}
} catch (e: Exception) {
}
return ""
}
}
}
只是想在以上回答中对以上解释做一点补充。这也会为其他人节省时间。
在我的情况下,这个方法没有返回任何手机号码,返回一个空字符串。这是由于我把我的号码移植到新的sim卡上的情况。所以如果我进入设置>关于电话>状态>我的电话号码,它显示我“未知”。
不建议使用TelephonyManager,因为它要求应用程序在运行时需要READ_PHONE_STATE权限。
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
应该使用谷歌的播放服务进行身份验证,它将能够允许用户选择使用哪个phoneNumber,并处理多个SIM卡,而不是我们试图猜测哪一个是主SIM卡。
implementation "com.google.android.gms:play-services-auth:$play_service_auth_version"
fun main() {
val googleApiClient = GoogleApiClient.Builder(context)
.addApi(Auth.CREDENTIALS_API).build()
val hintRequest = HintRequest.Builder()
.setPhoneNumberIdentifierSupported(true)
.build()
val hintPickerIntent = Auth.CredentialsApi.getHintPickerIntent(
googleApiClient, hintRequest
)
startIntentSenderForResult(
hintPickerIntent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0
)
}
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
when (requestCode) {
REQUEST_PHONE_NUMBER -> {
if (requestCode == Activity.RESULT_OK) {
val credential = data?.getParcelableExtra<Credential>(Credential.EXTRA_KEY)
val selectedPhoneNumber = credential?.id
}
}
}
}
有时,下面的代码返回null或空白字符串。
TelephonyManager tMgr = (TelephonyManager)mAppContext.getSystemService(Context.TELEPHONY_SERVICE);
String mPhoneNumber = tMgr.getLine1Number();
经以下许可
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
还有另一种方法,你将能够得到你的电话号码,我还没有在多个设备上测试,但上述代码不是每次都能工作。
试试下面的代码:
String main_data[] = {"data1", "is_primary", "data3", "data2", "data1", "is_primary", "photo_uri", "mimetype"};
Object object = getContentResolver().query(Uri.withAppendedPath(android.provider.ContactsContract.Profile.CONTENT_URI, "data"),
main_data, "mimetype=?",
new String[]{"vnd.android.cursor.item/phone_v2"},
"is_primary DESC");
if (object != null) {
do {
if (!((Cursor) (object)).moveToNext())
break;
// This is the phoneNumber
String s1 = ((Cursor) (object)).getString(4);
} while (true);
((Cursor) (object)).close();
}
您需要添加这两个权限。
<uses-permission android:name="android.permission.READ_CONTACTS" />
<uses-permission android:name="android.permission.READ_PROFILE" />
希望这能有所帮助, 谢谢!
这是一个更简单的答案:
public String getMyPhoneNumber()
{
return ((TelephonyManager) getSystemService(TELEPHONY_SERVICE))
.getLine1Number();
}
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