我如何通过编程方式获得正在运行我的android应用程序的设备的电话号码?
当前回答
private String getMyPhoneNumber(){
TelephonyManager mTelephonyMgr;
mTelephonyMgr = (TelephonyManager)
getSystemService(Context.TELEPHONY_SERVICE);
return mTelephonyMgr.getLine1Number();
}
private String getMy10DigitPhoneNumber(){
String s = getMyPhoneNumber();
return s != null && s.length() > 2 ? s.substring(2) : null;
}
代码摘自http://www.androidsnippets.com/get-my-phone-number
其他回答
以下是我找到的解决方案的组合(这里是示例项目,如果你也想检查自动填充):
清单
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
build.gradle
implementation "com.google.android.gms:play-services-auth:17.0.0"
MainActivity.kt
class MainActivity : AppCompatActivity() {
private lateinit var googleApiClient: GoogleApiClient
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
tryGetCurrentUserPhoneNumber(this)
googleApiClient = GoogleApiClient.Builder(this).addApi(Auth.CREDENTIALS_API).build()
if (phoneNumber.isEmpty()) {
val hintRequest = HintRequest.Builder().setPhoneNumberIdentifierSupported(true).build()
val intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest)
try {
startIntentSenderForResult(intent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0);
} catch (e: IntentSender.SendIntentException) {
Toast.makeText(this, "failed to show phone picker", Toast.LENGTH_SHORT).show()
}
} else
onGotPhoneNumberToSendTo()
}
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
if (requestCode == REQUEST_PHONE_NUMBER) {
if (resultCode == Activity.RESULT_OK) {
val cred: Credential? = data?.getParcelableExtra(Credential.EXTRA_KEY)
phoneNumber = cred?.id ?: ""
if (phoneNumber.isEmpty())
Toast.makeText(this, "failed to get phone number", Toast.LENGTH_SHORT).show()
else
onGotPhoneNumberToSendTo()
}
}
}
private fun onGotPhoneNumberToSendTo() {
Toast.makeText(this, "got number:$phoneNumber", Toast.LENGTH_SHORT).show()
}
companion object {
private const val REQUEST_PHONE_NUMBER = 1
private var phoneNumber = ""
@SuppressLint("MissingPermission", "HardwareIds")
private fun tryGetCurrentUserPhoneNumber(context: Context): String {
if (phoneNumber.isNotEmpty())
return phoneNumber
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
val subscriptionManager = context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
try {
subscriptionManager.activeSubscriptionInfoList?.forEach {
val number: String? = it.number
if (!number.isNullOrBlank()) {
phoneNumber = number
return number
}
}
} catch (ignored: Exception) {
}
}
try {
val telephonyManager = context.getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
val number = telephonyManager.line1Number ?: ""
if (!number.isBlank()) {
phoneNumber = number
return number
}
} catch (e: Exception) {
}
return ""
}
}
}
首先在Intent中初始化你的符号
private val signInIntent = registerForActivityResult(ActivityResultContracts.StartIntentSenderForResult()) { result ->
try {
val phoneNumber = Identity.getSignInClient(requireContext()).getPhoneNumberFromIntent(result.data)
// Note phone number will be in country code + phone number format
} catch (e: Exception) {
}
}
要打开谷歌播放意图,并显示与谷歌帐户相关联的电话号码,请使用此
val phoneNumberHintIntentRequest = GetPhoneNumberHintIntentRequest.builder()
.build()
Identity.getSignInClient(requireContext())
.getPhoneNumberHintIntent(phoneNumberHintIntentRequest)
.addOnSuccessListener { pendingIntent ->
signInIntent.launch(IntentSenderRequest.Builder(pendingIntent).build())
}.addOnFailureListener {
it.printStackTrace()
}
注意:
如果用户禁用电话号码共享,此操作将失败。如果是这样,用户必须从设置->谷歌->自动填充->电话号码共享 如果您正在使用播放服务不可用的模拟设备,这将不起作用
这是一个更简单的答案:
public String getMyPhoneNumber()
{
return ((TelephonyManager) getSystemService(TELEPHONY_SERVICE))
.getLine1Number();
}
这个问题没有保证的解决方案,因为电话号码不是物理地存储在所有sim卡上,也不是从网络广播到电话上。在一些需要物理地址验证的国家尤其如此,只有在验证之后才会分配号码。电话号码分配是在网络上进行的,并且可以在不改变SIM卡或设备的情况下进行更改(例如,这就是支持移植的方式)。
我知道这很痛苦,但最有可能的最好的解决方案是让用户输入一次他/她的电话号码并存储它。
有一个新的Android api,允许用户选择他们的电话号码,而不需要权限。来看看: https://android-developers.googleblog.com/2017/10/effective-phone-number-verification.html
// Construct a request for phone numbers and show the picker
private void requestHint() {
HintRequest hintRequest = new HintRequest.Builder()
.setPhoneNumberIdentifierSupported(true)
.build();
PendingIntent intent = Auth.CredentialsApi.getHintPickerIntent(
apiClient, hintRequest);
startIntentSenderForResult(intent.getIntentSender(),
RESOLVE_HINT, null, 0, 0, 0);
}
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