我如何通过编程方式获得正在运行我的android应用程序的设备的电话号码?
当前回答
对于android版本>= LOLLIPOP_MR1:
增加权限:
叫它:
val subscriptionManager =
getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
val list = subscriptionManager.activeSubscriptionInfoList
for (info in list) {
Log.d(TAG, "number " + info.number)
Log.d(TAG, "network name : " + info.carrierName)
Log.d(TAG, "country iso " + info.countryIso)
}
}
其他回答
如果我从voiceMailNumer得到数字,那么它工作得很好-
val telephonyManager = getSystemService(TELEPHONY_SERVICE) as TelephonyManager
if (ActivityCompat.checkSelfPermission(this,
Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED
) {
Log.d("number", telephonyManager.voiceMailNumber.toString())
}
以下是我找到的解决方案的组合(这里是示例项目,如果你也想检查自动填充):
清单
<uses-permission android:name="android.permission.READ_PHONE_STATE" />
build.gradle
implementation "com.google.android.gms:play-services-auth:17.0.0"
MainActivity.kt
class MainActivity : AppCompatActivity() {
private lateinit var googleApiClient: GoogleApiClient
override fun onCreate(savedInstanceState: Bundle?) {
super.onCreate(savedInstanceState)
setContentView(R.layout.activity_main)
tryGetCurrentUserPhoneNumber(this)
googleApiClient = GoogleApiClient.Builder(this).addApi(Auth.CREDENTIALS_API).build()
if (phoneNumber.isEmpty()) {
val hintRequest = HintRequest.Builder().setPhoneNumberIdentifierSupported(true).build()
val intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest)
try {
startIntentSenderForResult(intent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0);
} catch (e: IntentSender.SendIntentException) {
Toast.makeText(this, "failed to show phone picker", Toast.LENGTH_SHORT).show()
}
} else
onGotPhoneNumberToSendTo()
}
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
if (requestCode == REQUEST_PHONE_NUMBER) {
if (resultCode == Activity.RESULT_OK) {
val cred: Credential? = data?.getParcelableExtra(Credential.EXTRA_KEY)
phoneNumber = cred?.id ?: ""
if (phoneNumber.isEmpty())
Toast.makeText(this, "failed to get phone number", Toast.LENGTH_SHORT).show()
else
onGotPhoneNumberToSendTo()
}
}
}
private fun onGotPhoneNumberToSendTo() {
Toast.makeText(this, "got number:$phoneNumber", Toast.LENGTH_SHORT).show()
}
companion object {
private const val REQUEST_PHONE_NUMBER = 1
private var phoneNumber = ""
@SuppressLint("MissingPermission", "HardwareIds")
private fun tryGetCurrentUserPhoneNumber(context: Context): String {
if (phoneNumber.isNotEmpty())
return phoneNumber
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.M) {
val subscriptionManager = context.getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
try {
subscriptionManager.activeSubscriptionInfoList?.forEach {
val number: String? = it.number
if (!number.isNullOrBlank()) {
phoneNumber = number
return number
}
}
} catch (ignored: Exception) {
}
}
try {
val telephonyManager = context.getSystemService(Context.TELEPHONY_SERVICE) as TelephonyManager
val number = telephonyManager.line1Number ?: ""
if (!number.isBlank()) {
phoneNumber = number
return number
}
} catch (e: Exception) {
}
return ""
}
}
}
while working on a security app which needed to get the phone number of who so ever my phone might get into their hands, I had to do this; 1. receive Boot completed and then try getting Line1_Number from telephonyManager which returns a string result. 2. compare the String result with my own phone number and if they don't match or string returns null then, 3. secretly send an SMS containing the string result plus a special sign to my office number. 4. if message sending fails, start a service and keep trying after each hour until sent SMS pending intent returns successful. With this steps I could get the number of the person using my lost phone. it doesn't matter if the person is charged.
不建议使用TelephonyManager,因为它要求应用程序在运行时需要READ_PHONE_STATE权限。
<uses-permission android:name="android.permission.READ_PHONE_STATE"/>
应该使用谷歌的播放服务进行身份验证,它将能够允许用户选择使用哪个phoneNumber,并处理多个SIM卡,而不是我们试图猜测哪一个是主SIM卡。
implementation "com.google.android.gms:play-services-auth:$play_service_auth_version"
fun main() {
val googleApiClient = GoogleApiClient.Builder(context)
.addApi(Auth.CREDENTIALS_API).build()
val hintRequest = HintRequest.Builder()
.setPhoneNumberIdentifierSupported(true)
.build()
val hintPickerIntent = Auth.CredentialsApi.getHintPickerIntent(
googleApiClient, hintRequest
)
startIntentSenderForResult(
hintPickerIntent.intentSender, REQUEST_PHONE_NUMBER, null, 0, 0, 0
)
}
override fun onActivityResult(requestCode: Int, resultCode: Int, data: Intent?) {
super.onActivityResult(requestCode, resultCode, data)
when (requestCode) {
REQUEST_PHONE_NUMBER -> {
if (requestCode == Activity.RESULT_OK) {
val credential = data?.getParcelableExtra<Credential>(Credential.EXTRA_KEY)
val selectedPhoneNumber = credential?.id
}
}
}
}
这是一个更简单的答案:
public String getMyPhoneNumber()
{
return ((TelephonyManager) getSystemService(TELEPHONY_SERVICE))
.getLine1Number();
}
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