对于android版本>= LOLLIPOP_MR1:

增加权限:

叫它:

 val subscriptionManager =
        getSystemService(Context.TELEPHONY_SUBSCRIPTION_SERVICE) as SubscriptionManager
    
if (ActivityCompat.checkSelfPermission(this, Manifest.permission.READ_PHONE_STATE) == PackageManager.PERMISSION_GRANTED) {
        
val list = subscriptionManager.activeSubscriptionInfoList
        for (info in list) {
            Log.d(TAG, "number " + info.number)
            Log.d(TAG, "network name : " + info.carrierName)
            Log.d(TAG, "country iso " + info.countryIso)
        }
    }

这是一个更简单的答案:

public String getMyPhoneNumber()
{
    return ((TelephonyManager) getSystemService(TELEPHONY_SERVICE))
            .getLine1Number();
}

所以这就是你如何通过Play服务API请求一个电话号码，而没有许可和黑客。源代码和完整的示例。

在你的构建中。Gradle(版本10.2。X及以上要求):

compile "com.google.android.gms:play-services-auth:$gms_version"

在你的活动中(代码被简化了):

@Override
protected void onCreate(Bundle savedInstanceState) {
    // ...
    googleApiClient = new GoogleApiClient.Builder(this)
            .addApi(Auth.CREDENTIALS_API)
            .build();
    requestPhoneNumber(result -> {
        phoneET.setText(result);
    });
}

public void requestPhoneNumber(SimpleCallback<String> callback) {
    phoneNumberCallback = callback;
    HintRequest hintRequest = new HintRequest.Builder()
            .setPhoneNumberIdentifierSupported(true)
            .build();

    PendingIntent intent = Auth.CredentialsApi.getHintPickerIntent(googleApiClient, hintRequest);
    try {
        startIntentSenderForResult(intent.getIntentSender(), PHONE_NUMBER_RC, null, 0, 0, 0);
    } catch (IntentSender.SendIntentException e) {
        Logs.e(TAG, "Could not start hint picker Intent", e);
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if (requestCode == PHONE_NUMBER_RC) {
        if (resultCode == RESULT_OK) {
            Credential cred = data.getParcelableExtra(Credential.EXTRA_KEY);
            if (phoneNumberCallback != null){
                phoneNumberCallback.onSuccess(cred.getId());
            }
        }
        phoneNumberCallback = null;
    }
}

这会生成一个这样的对话框:

更新:这个答案不再可用，因为Whatsapp已经停止将电话号码作为帐户名，请忽略这个答案。

实际上，如果你不能通过电话服务获得它，你可以考虑另一种解决方案。

到今天为止，你可以依靠另一个大型应用程序Whatsapp，使用AccountManager。数以百万计的设备安装了这个应用程序，如果你不能通过TelephonyManager获得电话号码，你可以试试这个。

许可:

<uses-permission android:name="android.permission.GET_ACCOUNTS" />

代码:

AccountManager am = AccountManager.get(this);
Account[] accounts = am.getAccounts();

for (Account ac : accounts) {
    String acname = ac.name;
    String actype = ac.type;
    // Take your time to look at all available accounts
    System.out.println("Accounts : " + acname + ", " + actype);
}

检查WhatsApp帐户的actype

if(actype.equals("com.whatsapp")){
    String phoneNumber = ac.name;
}

当然，如果用户没有安装WhatsApp，你可能不会得到它，但无论如何都值得一试。 记住，你应该总是询问用户的确认。

我注意到有几个回复都发了同样的东西。首先，从2021年开始，onActivityResult已弃用。下面是不弃用的解决方案。

private fun requestHint() {

    val hintRequest = HintRequest.Builder()
        .setPhoneNumberIdentifierSupported(true)
        .build()

    val intent = Credentials.getClient(this).getHintPickerIntent(hintRequest)
    val intentSender = IntentSenderRequest.Builder(intent.intentSender).build()

    val resultLauncher = registerForActivityResult(
        ActivityResultContracts.StartIntentSenderForResult()
    ) { result ->
        if (result.resultCode == Activity.RESULT_OK) {
            val credential: Credential? = result.data?.getParcelableExtra(Credential.EXTRA_KEY)
            // Phone number with country code
            Log.i("mTag", "Selected phone No: ${credential?.id}")
        }
    }
    resultLauncher.launch(intentSender)
}

注意:虽然很多人认为这可以让你检索用户的手机号码。通常情况并非如此。谷歌播放服务缓存了几个电话号码，有时对话框显示电话号码，其中不属于用户。

一个重要的导入。com.google.android.gms.auth.api.credentials.Credential

参考文档提供了详细信息，但代码有些不推荐。

有一个新的Android api，允许用户选择他们的电话号码，而不需要权限。来看看: https://android-developers.googleblog.com/2017/10/effective-phone-number-verification.html

// Construct a request for phone numbers and show the picker
private void requestHint() {
    HintRequest hintRequest = new HintRequest.Builder()
       .setPhoneNumberIdentifierSupported(true)
       .build();

    PendingIntent intent = Auth.CredentialsApi.getHintPickerIntent(
        apiClient, hintRequest);
    startIntentSenderForResult(intent.getIntentSender(),
        RESOLVE_HINT, null, 0, 0, 0);
}