使用importlib，唯一需要添加的是

from importlib import import_module
from pathlib import Path

__all__ = [
    import_module(f".{f.stem}", __package__)
    for f in Path(__file__).parent.glob("*.py")
    if "__" not in f.stem
]
del import_module, Path

列出当前文件夹中的所有python (.py)文件，并将它们作为__init__.py中的__all__变量

from os.path import dirname, basename, isfile, join
import glob
modules = glob.glob(join(dirname(__file__), "*.py"))
__all__ = [ basename(f)[:-3] for f in modules if isfile(f) and not f.endswith('__init__.py')]

注意你的__init__.py定义了__all__。模块-包文档说

The __init__.py files are required to make Python treat the directories as containing packages; this is done to prevent directories with a common name, such as string, from unintentionally hiding valid modules that occur later on the module search path. In the simplest case, __init__.py can just be an empty file, but it can also execute initialization code for the package or set the __all__ variable, described later. ... The only solution is for the package author to provide an explicit index of the package. The import statement uses the following convention: if a package’s __init__.py code defines a list named __all__, it is taken to be the list of module names that should be imported when from package import * is encountered. It is up to the package author to keep this list up-to-date when a new version of the package is released. Package authors may also decide not to support it, if they don’t see a use for importing * from their package. For example, the file sounds/effects/__init__.py could contain the following code: __all__ = ["echo", "surround", "reverse"] This would mean that from sound.effects import * would import the three named submodules of the sound package.

这是我迄今为止发现的最好的方法:

from os.path import dirname, join, isdir, abspath, basename
from glob import glob
pwd = dirname(__file__)
for x in glob(join(pwd, '*.py')):
    if not x.startswith('__'):
        __import__(basename(x)[:-3], globals(), locals())

扩展Mihail的回答，我认为非黑客的方式(即不直接处理文件路径)如下:

在Foo/下创建一个空的__init__.py文件 执行

import pkgutil
import sys


def load_all_modules_from_dir(dirname):
    for importer, package_name, _ in pkgutil.iter_modules([dirname]):
        full_package_name = '%s.%s' % (dirname, package_name)
        if full_package_name not in sys.modules:
            module = importer.find_module(package_name
                        ).load_module(full_package_name)
            print module


load_all_modules_from_dir('Foo')

你会得到:

<module 'Foo.bar' from '/home/.../Foo/bar.pyc'>
<module 'Foo.spam' from '/home/.../Foo/spam.pyc'>

2017年更新:你可能想用importlib代替。

通过添加__init__.py使Foo目录成为一个包。在__init__.py中添加:

import bar
import eggs
import spam

因为你希望它是动态的(这可能是也可能不是一个好主意)，用list dir列出所有的py-files，然后像这样导入它们:

import os
for module in os.listdir(os.path.dirname(__file__)):
    if module == '__init__.py' or module[-3:] != '.py':
        continue
    __import__(module[:-3], locals(), globals())
del module

然后，从你的代码这样做:

import Foo

您现在可以使用

Foo.bar
Foo.eggs
Foo.spam

从Foo导入*不是一个好主意，有几个原因，包括名称冲突，使其难以分析代码。