有人能为我提供一个导入整个模块目录的好方法吗? 我有一个这样的结构:
/Foo
bar.py
spam.py
eggs.py
我尝试通过添加__init__.py并从Foo import *将其转换为一个包,但它没有按我希望的方式工作。
有人能为我提供一个导入整个模块目录的好方法吗? 我有一个这样的结构:
/Foo
bar.py
spam.py
eggs.py
我尝试通过添加__init__.py并从Foo import *将其转换为一个包,但它没有按我希望的方式工作。
当前回答
我有一个嵌套的目录结构,即在包含python模块的主目录中有多个目录。
我在__init__.py文件中添加了以下脚本以导入所有模块
import glob, re, os
module_parent_directory = "path/to/the/directory/containing/__init__.py/file"
owd = os.getcwd()
if not owd.endswith(module_parent_directory): os.chdir(module_parent_directory)
module_paths = glob.glob("**/*.py", recursive = True)
for module_path in module_paths:
if not re.match( ".*__init__.py$", module_path):
import_path = module_path[:-3]
import_path = import_path.replace("/", ".")
exec(f"from .{import_path} import *")
os.chdir(owd)
也许这不是实现这一目标的最佳方式,但除此之外我没有别的办法。
其他回答
包含一个目录下的所有文件:
专为那些无法上手的新手准备的。
Make a folder /home/el/foo and make a file main.py under /home/el/foo Put this code in there: from hellokitty import * spam.spamfunc() ham.hamfunc() Make a directory /home/el/foo/hellokitty Make a file __init__.py under /home/el/foo/hellokitty and put this code in there: __all__ = ["spam", "ham"] Make two python files: spam.py and ham.py under /home/el/foo/hellokitty Define a function inside spam.py: def spamfunc(): print("Spammity spam") Define a function inside ham.py: def hamfunc(): print("Upgrade from baloney") Run it: el@apollo:/home/el/foo$ python main.py spammity spam Upgrade from baloney
列出当前文件夹中的所有python (.py)文件,并将它们作为__init__.py中的__all__变量
from os.path import dirname, basename, isfile, join
import glob
modules = glob.glob(join(dirname(__file__), "*.py"))
__all__ = [ basename(f)[:-3] for f in modules if isfile(f) and not f.endswith('__init__.py')]
只需通过importlib导入它们,并在包的__init__.py中递归地将它们添加到__all__(添加操作是可选的)。
/Foo
bar.py
spam.py
eggs.py
__init__.py
# __init__.py
import os
import importlib
pyfile_extes = ['py', ]
__all__ = [importlib.import_module('.%s' % filename, __package__) for filename in [os.path.splitext(i)[0] for i in os.listdir(os.path.dirname(__file__)) if os.path.splitext(i)[1] in pyfile_extes] if not filename.startswith('__')]
del os, importlib, pyfile_extes
注意你的__init__.py定义了__all__。模块-包文档说
The __init__.py files are required to make Python treat the directories as containing packages; this is done to prevent directories with a common name, such as string, from unintentionally hiding valid modules that occur later on the module search path. In the simplest case, __init__.py can just be an empty file, but it can also execute initialization code for the package or set the __all__ variable, described later. ... The only solution is for the package author to provide an explicit index of the package. The import statement uses the following convention: if a package’s __init__.py code defines a list named __all__, it is taken to be the list of module names that should be imported when from package import * is encountered. It is up to the package author to keep this list up-to-date when a new version of the package is released. Package authors may also decide not to support it, if they don’t see a use for importing * from their package. For example, the file sounds/effects/__init__.py could contain the following code: __all__ = ["echo", "surround", "reverse"] This would mean that from sound.effects import * would import the three named submodules of the sound package.
将__all__变量添加到__init__.py,包含:
__all__ = ["bar", "spam", "eggs"]
参见http://docs.python.org/tutorial/modules.html