我有一个嵌套的目录结构，即在包含python模块的主目录中有多个目录。

我在__init__.py文件中添加了以下脚本以导入所有模块

import glob, re, os 

module_parent_directory = "path/to/the/directory/containing/__init__.py/file"

owd = os.getcwd()
if not owd.endswith(module_parent_directory): os.chdir(module_parent_directory)

module_paths = glob.glob("**/*.py", recursive = True)

for module_path in module_paths:
    if not re.match( ".*__init__.py$", module_path):
        import_path = module_path[:-3]
        import_path = import_path.replace("/", ".")
        exec(f"from .{import_path} import *")

os.chdir(owd)

也许这不是实现这一目标的最佳方式，但除此之外我没有别的办法。

2017年更新:你可能想用importlib代替。

通过添加__init__.py使Foo目录成为一个包。在__init__.py中添加:

import bar
import eggs
import spam

因为你希望它是动态的(这可能是也可能不是一个好主意)，用list dir列出所有的py-files，然后像这样导入它们:

import os
for module in os.listdir(os.path.dirname(__file__)):
    if module == '__init__.py' or module[-3:] != '.py':
        continue
    __import__(module[:-3], locals(), globals())
del module

然后，从你的代码这样做:

import Foo

您现在可以使用

Foo.bar
Foo.eggs
Foo.spam

从Foo导入*不是一个好主意，有几个原因，包括名称冲突，使其难以分析代码。

我知道我正在更新一个相当旧的帖子，我尝试使用automodinit，但发现它的设置过程对python3是坏的。所以，基于Luca的回答，我想出了一个更简单的答案——可能不适合。zip——来解决这个问题，所以我想我应该在这里分享它:

在你的包的__init__.py模块中:

#!/usr/bin/env python
import os, pkgutil
__all__ = list(module for _, module, _ in pkgutil.iter_modules([os.path.dirname(__file__)]))

在你的包下面的另一个包里:

from yourpackage import *

然后，您将加载包中放置的所有模块，如果您编写了一个新模块，它也将被自动导入。当然，要小心使用这些东西，能力越大责任越大。

列出当前文件夹中的所有python (.py)文件，并将它们作为__init__.py中的__all__变量

from os.path import dirname, basename, isfile, join
import glob
modules = glob.glob(join(dirname(__file__), "*.py"))
__all__ = [ basename(f)[:-3] for f in modules if isfile(f) and not f.endswith('__init__.py')]

我有一个嵌套的目录结构，即在包含python模块的主目录中有多个目录。

我在__init__.py文件中添加了以下脚本以导入所有模块

import glob, re, os 

module_parent_directory = "path/to/the/directory/containing/__init__.py/file"

owd = os.getcwd()
if not owd.endswith(module_parent_directory): os.chdir(module_parent_directory)

module_paths = glob.glob("**/*.py", recursive = True)

for module_path in module_paths:
    if not re.match( ".*__init__.py$", module_path):
        import_path = module_path[:-3]
        import_path = import_path.replace("/", ".")
        exec(f"from .{import_path} import *")

os.chdir(owd)

也许这不是实现这一目标的最佳方式，但除此之外我没有别的办法。

注意你的__init__.py定义了__all__。模块-包文档说

The __init__.py files are required to make Python treat the directories as containing packages; this is done to prevent directories with a common name, such as string, from unintentionally hiding valid modules that occur later on the module search path. In the simplest case, __init__.py can just be an empty file, but it can also execute initialization code for the package or set the __all__ variable, described later. ... The only solution is for the package author to provide an explicit index of the package. The import statement uses the following convention: if a package’s __init__.py code defines a list named __all__, it is taken to be the list of module names that should be imported when from package import * is encountered. It is up to the package author to keep this list up-to-date when a new version of the package is released. Package authors may also decide not to support it, if they don’t see a use for importing * from their package. For example, the file sounds/effects/__init__.py could contain the following code: __all__ = ["echo", "surround", "reverse"] This would mean that from sound.effects import * would import the three named submodules of the sound package.