下面是运行任意命令返回其标准输出数据的Python代码，或在非零退出码上引发异常:
proc = subprocess.Popen(
cmd,
stderr=subprocess.STDOUT, # Merge stdout and stderr
stdout=subprocess.PIPE,
shell=True)
communication用于等待进程退出:
stdoutdata, stderrdata = proc.communicate()
子进程模块不支持超时——杀死运行超过X秒的进程的能力——因此，通信可能需要很长时间才能运行。
在Windows和Linux上运行的Python程序中实现超时的最简单方法是什么?
当前回答
https://pypi.python.org/pypi/python-subprocess2提供了子流程模块的扩展，允许您等待一段时间，否则将终止。
因此，等待最多10秒的进程终止，否则kill:
pipe = subprocess.Popen('...')
timeout = 10
results = pipe.waitOrTerminate(timeout)
这与windows和unix兼容。"results"是一个字典，它包含"returnCode"，这是应用程序的返回(或None，如果它必须被杀死)，以及"actionTaken"。如果流程正常完成，则为“SUBPROCESS2_PROCESS_COMPLETED”，或者根据所采取的操作，为“SUBPROCESS2_PROCESS_TERMINATED”和SUBPROCESS2_PROCESS_KILLED(详细信息请参阅文档)
其他回答
Jcollado的答案可以使用线程来简化。定时器类:
import shlex
from subprocess import Popen, PIPE
from threading import Timer
def run(cmd, timeout_sec):
proc = Popen(shlex.split(cmd), stdout=PIPE, stderr=PIPE)
timer = Timer(timeout_sec, proc.kill)
try:
timer.start()
stdout, stderr = proc.communicate()
finally:
timer.cancel()
# Examples: both take 1 second
run("sleep 1", 5) # process ends normally at 1 second
run("sleep 5", 1) # timeout happens at 1 second
对于python 2.6+，使用gevent
from gevent.subprocess import Popen, PIPE, STDOUT
def call_sys(cmd, timeout):
p= Popen(cmd, shell=True, stdout=PIPE)
output, _ = p.communicate(timeout=timeout)
assert p.returncode == 0, p. returncode
return output
call_sys('./t.sh', 2)
# t.sh example
sleep 5
echo done
exit 1
This solution kills the process tree in case of shell=True, passes parameters to the process (or not), has a timeout and gets the stdout, stderr and process output of the call back (it uses psutil for the kill_proc_tree). This was based on several solutions posted in SO including jcollado's. Posting in response to comments by Anson and jradice in jcollado's answer. Tested in Windows Srvr 2012 and Ubuntu 14.04. Please note that for Ubuntu you need to change the parent.children(...) call to parent.get_children(...).
def kill_proc_tree(pid, including_parent=True):
parent = psutil.Process(pid)
children = parent.children(recursive=True)
for child in children:
child.kill()
psutil.wait_procs(children, timeout=5)
if including_parent:
parent.kill()
parent.wait(5)
def run_with_timeout(cmd, current_dir, cmd_parms, timeout):
def target():
process = subprocess.Popen(cmd, cwd=current_dir, shell=True, stdout=subprocess.PIPE, stdin=subprocess.PIPE, stderr=subprocess.PIPE)
# wait for the process to terminate
if (cmd_parms == ""):
out, err = process.communicate()
else:
out, err = process.communicate(cmd_parms)
errcode = process.returncode
thread = Thread(target=target)
thread.start()
thread.join(timeout)
if thread.is_alive():
me = os.getpid()
kill_proc_tree(me, including_parent=False)
thread.join()
我使用的解决方案是在shell命令前面加上timelimit。如果命令花费的时间太长，timelimit将停止它，Popen将有一个由timelimit设置的返回码。如果它是> 128，它意味着时间限制杀死进程。
参见python subprocess with timeout and large output (>64K)
如果你正在使用python2，请尝试一下
import subprocess32
try:
output = subprocess32.check_output(command, shell=True, timeout=3)
except subprocess32.TimeoutExpired as e:
print e
