https://pypi.python.org/pypi/python-subprocess2提供了子流程模块的扩展，允许您等待一段时间，否则将终止。

因此，等待最多10秒的进程终止，否则kill:

pipe  = subprocess.Popen('...')

timeout =  10

results = pipe.waitOrTerminate(timeout)

这与windows和unix兼容。"results"是一个字典，它包含"returnCode"，这是应用程序的返回(或None，如果它必须被杀死)，以及"actionTaken"。如果流程正常完成，则为“SUBPROCESS2_PROCESS_COMPLETED”，或者根据所采取的操作，为“SUBPROCESS2_PROCESS_TERMINATED”和SUBPROCESS2_PROCESS_KILLED(详细信息请参阅文档)

我有一个问题，我想终止一个多线程子进程，如果它花费的时间超过给定的超时长度。我想在Popen()中设置一个超时，但它不起作用。然后，我意识到Popen().wait()等于call()，所以我有了在.wait(timeout=xxx)方法中设置超时的想法，这最终工作了。因此，我是这样解决的:

import os
import sys
import signal
import subprocess
from multiprocessing import Pool

cores_for_parallelization = 4
timeout_time = 15  # seconds

def main():
    jobs = [...YOUR_JOB_LIST...]
    with Pool(cores_for_parallelization) as p:
        p.map(run_parallel_jobs, jobs)

def run_parallel_jobs(args):
    # Define the arguments including the paths
    initial_terminal_command = 'C:\\Python34\\python.exe'  # Python executable
    function_to_start = 'C:\\temp\\xyz.py'  # The multithreading script
    final_list = [initial_terminal_command, function_to_start]
    final_list.extend(args)

    # Start the subprocess and determine the process PID
    subp = subprocess.Popen(final_list)  # starts the process
    pid = subp.pid

    # Wait until the return code returns from the function by considering the timeout. 
    # If not, terminate the process.
    try:
        returncode = subp.wait(timeout=timeout_time)  # should be zero if accomplished
    except subprocess.TimeoutExpired:
        # Distinguish between Linux and Windows and terminate the process if 
        # the timeout has been expired
        if sys.platform == 'linux2':
            os.kill(pid, signal.SIGTERM)
        elif sys.platform == 'win32':
            subp.terminate()

if __name__ == '__main__':
    main()

Jcollado的答案可以使用线程来简化。定时器类:

import shlex
from subprocess import Popen, PIPE
from threading import Timer

def run(cmd, timeout_sec):
    proc = Popen(shlex.split(cmd), stdout=PIPE, stderr=PIPE)
    timer = Timer(timeout_sec, proc.kill)
    try:
        timer.start()
        stdout, stderr = proc.communicate()
    finally:
        timer.cancel()

# Examples: both take 1 second
run("sleep 1", 5)  # process ends normally at 1 second
run("sleep 5", 1)  # timeout happens at 1 second

虽然我还没有广泛地研究它，但我在ActiveState中发现的这个装饰器似乎对这类事情非常有用。伴随着subprocess.Popen(…， close_fds=True)，至少我已经准备好在Python中编写shell脚本。

timeout现在由子进程模块中的call()和communication()支持(从Python3.3开始):

import subprocess

subprocess.call("command", timeout=20, shell=True)

这将调用该命令并引发异常

subprocess.TimeoutExpired

如果命令在20秒后还没有完成。

然后你可以处理异常来继续你的代码，就像这样:

try:
    subprocess.call("command", timeout=20, shell=True)
except subprocess.TimeoutExpired:
    # insert code here

希望这能有所帮助。

python 2.7

import time
import subprocess

def run_command(cmd, timeout=0):
    start_time = time.time()
    df = subprocess.Popen(cmd, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
    while timeout and df.poll() == None:
        if time.time()-start_time >= timeout:
            df.kill()
            return -1, ""
    output = '\n'.join(df.communicate()).strip()
    return df.returncode, output