我有3个任务:
private async Task<Cat> FeedCat() {}
private async Task<House> SellHouse() {}
private async Task<Tesla> BuyCar() {}
它们都需要在我的代码继续之前运行，我也需要每个结果。这些结果之间没有任何共同之处
我如何调用和等待3个任务完成，然后得到结果?
当前回答
给定三个任务——FeedCat()、SellHouse()和BuyCar()，有两种有趣的情况:要么它们都同步完成(出于某种原因，可能是缓存或错误)，要么它们不同步完成。
假设我们有，从这个问题
Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
// what here?
}
现在，一个简单的方法是:
Task.WhenAll(x, y, z);
但是…这样不方便处理结果;我们通常会等待:
async Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
await Task.WhenAll(x, y, z);
// presumably we want to do something with the results...
return DoWhatever(x.Result, y.Result, z.Result);
}
但是这会产生很多开销，并分配各种数组(包括params Task[]数组)和列表(内部)。这是可行的，但在我看来并不是很好。在许多方面，使用异步操作并依次等待每个操作会更简单:
async Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
// do something with the results...
return DoWhatever(await x, await y, await z);
}
与上面的一些评论相反，使用await而不是Task。WhenAll对任务的运行方式(并发、顺序等)没有影响。在最高级别，任务。WhenAll在编译器支持async/await之前就已经存在了，在那些东西不存在的时候非常有用。当你有一个任意的任务数组，而不是3个离散的任务时，它也很有用。
但是:我们仍然有async/await为continuation生成大量编译器噪声的问题。如果有可能这些任务实际上是同步完成的，那么我们可以通过构建带有异步回退的同步路径来优化:
Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
if(x.Status == TaskStatus.RanToCompletion &&
y.Status == TaskStatus.RanToCompletion &&
z.Status == TaskStatus.RanToCompletion)
return Task.FromResult(
DoWhatever(a.Result, b.Result, c.Result));
// we can safely access .Result, as they are known
// to be ran-to-completion
return Awaited(x, y, z);
}
async Task Awaited(Task<Cat> a, Task<House> b, Task<Tesla> c) {
return DoWhatever(await x, await y, await z);
}
这种“同步路径与异步回退”方法越来越普遍，特别是在同步完成相对频繁的高性能代码中。注意，如果补全总是异步的，这一点帮助都没有。
适用于这里的其他事项:
with recent C#, a common pattern is for the async fallback method is commonly implemented as a local function: Task<string> DoTheThings() { async Task<string> Awaited(Task<Cat> a, Task<House> b, Task<Tesla> c) { return DoWhatever(await a, await b, await c); } Task<Cat> x = FeedCat(); Task<House> y = SellHouse(); Task<Tesla> z = BuyCar(); if(x.Status == TaskStatus.RanToCompletion && y.Status == TaskStatus.RanToCompletion && z.Status == TaskStatus.RanToCompletion) return Task.FromResult( DoWhatever(a.Result, b.Result, c.Result)); // we can safely access .Result, as they are known // to be ran-to-completion return Awaited(x, y, z); } prefer ValueTask<T> to Task<T> if there is a good chance of things ever completely synchronously with many different return values: ValueTask<string> DoTheThings() { async ValueTask<string> Awaited(ValueTask<Cat> a, Task<House> b, Task<Tesla> c) { return DoWhatever(await a, await b, await c); } ValueTask<Cat> x = FeedCat(); ValueTask<House> y = SellHouse(); ValueTask<Tesla> z = BuyCar(); if(x.IsCompletedSuccessfully && y.IsCompletedSuccessfully && z.IsCompletedSuccessfully) return new ValueTask<string>( DoWhatever(a.Result, b.Result, c.Result)); // we can safely access .Result, as they are known // to be ran-to-completion return Awaited(x, y, z); } if possible, prefer IsCompletedSuccessfully to Status == TaskStatus.RanToCompletion; this now exists in .NET Core for Task, and everywhere for ValueTask<T>
其他回答
如果您试图记录所有错误，请确保您保留任务。代码中的WhenAll行，很多注释建议您可以删除它并等待单个任务。的任务。WhenAll对于错误处理非常重要。如果没有这一行，您可能会为未观察到的异常打开代码。
var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();
await Task.WhenAll(catTask, houseTask, carTask);
var cat = await catTask;
var house = await houseTask;
var car = await carTask;
假设FeedCat在以下代码中抛出异常:
var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();
var cat = await catTask;
var house = await houseTask;
var car = await carTask;
在这种情况下，您将永远不会等待houseTask或carTask。这里有3种可能的场景:
SellHouse is already completed successfully when FeedCat failed. In this case you are fine. SellHouse is not complete and fails with exception at some point. Exception is not observed and will be rethrown on finalizer thread. SellHouse is not complete and contains awaits inside it. In case your code runs in ASP.NET SellHouse will fail as soon as some of the awaits will completed inside it. This happens because you basically made fire & forget call and synchronization context was lost as soon as FeedCat failed.
下面是你将得到的case(3)的错误:
System.AggregateException: A Task's exception(s) were not observed either by Waiting on the Task or accessing its Exception property. As a result, the unobserved exception was rethrown by the finalizer thread. ---> System.NullReferenceException: Object reference not set to an instance of an object.
at System.Web.ThreadContext.AssociateWithCurrentThread(Boolean setImpersonationContext)
at System.Web.HttpApplication.OnThreadEnterPrivate(Boolean setImpersonationContext)
at System.Web.HttpApplication.System.Web.Util.ISyncContext.Enter()
at System.Web.Util.SynchronizationHelper.SafeWrapCallback(Action action)
at System.Threading.Tasks.Task.Execute()
--- End of inner exception stack trace ---
---> (Inner Exception #0) System.NullReferenceException: Object reference not set to an instance of an object.
at System.Web.ThreadContext.AssociateWithCurrentThread(Boolean setImpersonationContext)
at System.Web.HttpApplication.OnThreadEnterPrivate(Boolean setImpersonationContext)
at System.Web.HttpApplication.System.Web.Util.ISyncContext.Enter()
at System.Web.Util.SynchronizationHelper.SafeWrapCallback(Action action)
at System.Threading.Tasks.Task.Execute()<---
对于情况(2)，您将得到类似的错误，但原始异常堆栈跟踪。
对于. net 4.0及更高版本，您可以使用TaskScheduler.UnobservedTaskException捕获未观察到的异常。对于。net 4.5及以后的版本，未观察到的异常将被默认接受，而对于。net 4.0，未观察到的异常将使您的进程崩溃。
更多详细信息请参见。net 4.5中的任务异常处理
你可以把它们存储在任务中，然后等待它们:
var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();
await Task.WhenAll(catTask, houseTask, carTask);
Cat cat = await catTask;
House house = await houseTask;
Car car = await carTask;
await语句不是使代码按顺序运行吗?考虑以下代码
class Program
{
static Stopwatch _stopwatch = new();
static async Task Main(string[] args)
{
Console.WriteLine($"fire hot");
_stopwatch.Start();
var carTask = BuyCar();
var catTask = FeedCat();
var houseTask = SellHouse();
await carTask;
await catTask;
await houseTask;
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} done!");
Console.WriteLine($"using await");
_stopwatch.Restart();
await BuyCar();
await FeedCat();
await SellHouse();
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} done!");
}
static async Task BuyCar()
{
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} buy car started");
await Task.Delay(2000);
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} buy car done");
}
static async Task FeedCat()
{
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} feed cat started");
await Task.Delay(1000);
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} feed cat done");
}
static async Task SellHouse()
{
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} sell house started");
await Task.Delay(10);
Console.WriteLine($"{_stopwatch.ElapsedMilliseconds} sell house done");
}
}
fire hot
0 buy car started
3 feed cat started
4 sell house started
18 sell house done
1004 feed cat done
2013 buy car done
2014 done!
using await
0 buy car started
2012 buy car done
2012 feed cat started
3018 feed cat done
3018 sell house started
3033 sell house done
3034 done!
给定三个任务——FeedCat()、SellHouse()和BuyCar()，有两种有趣的情况:要么它们都同步完成(出于某种原因，可能是缓存或错误)，要么它们不同步完成。
假设我们有，从这个问题
Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
// what here?
}
现在，一个简单的方法是:
Task.WhenAll(x, y, z);
但是…这样不方便处理结果;我们通常会等待:
async Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
await Task.WhenAll(x, y, z);
// presumably we want to do something with the results...
return DoWhatever(x.Result, y.Result, z.Result);
}
但是这会产生很多开销，并分配各种数组(包括params Task[]数组)和列表(内部)。这是可行的，但在我看来并不是很好。在许多方面，使用异步操作并依次等待每个操作会更简单:
async Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
// do something with the results...
return DoWhatever(await x, await y, await z);
}
与上面的一些评论相反，使用await而不是Task。WhenAll对任务的运行方式(并发、顺序等)没有影响。在最高级别，任务。WhenAll在编译器支持async/await之前就已经存在了，在那些东西不存在的时候非常有用。当你有一个任意的任务数组，而不是3个离散的任务时，它也很有用。
但是:我们仍然有async/await为continuation生成大量编译器噪声的问题。如果有可能这些任务实际上是同步完成的，那么我们可以通过构建带有异步回退的同步路径来优化:
Task<string> DoTheThings() {
Task<Cat> x = FeedCat();
Task<House> y = SellHouse();
Task<Tesla> z = BuyCar();
if(x.Status == TaskStatus.RanToCompletion &&
y.Status == TaskStatus.RanToCompletion &&
z.Status == TaskStatus.RanToCompletion)
return Task.FromResult(
DoWhatever(a.Result, b.Result, c.Result));
// we can safely access .Result, as they are known
// to be ran-to-completion
return Awaited(x, y, z);
}
async Task Awaited(Task<Cat> a, Task<House> b, Task<Tesla> c) {
return DoWhatever(await x, await y, await z);
}
这种“同步路径与异步回退”方法越来越普遍，特别是在同步完成相对频繁的高性能代码中。注意，如果补全总是异步的，这一点帮助都没有。
适用于这里的其他事项:
with recent C#, a common pattern is for the async fallback method is commonly implemented as a local function: Task<string> DoTheThings() { async Task<string> Awaited(Task<Cat> a, Task<House> b, Task<Tesla> c) { return DoWhatever(await a, await b, await c); } Task<Cat> x = FeedCat(); Task<House> y = SellHouse(); Task<Tesla> z = BuyCar(); if(x.Status == TaskStatus.RanToCompletion && y.Status == TaskStatus.RanToCompletion && z.Status == TaskStatus.RanToCompletion) return Task.FromResult( DoWhatever(a.Result, b.Result, c.Result)); // we can safely access .Result, as they are known // to be ran-to-completion return Awaited(x, y, z); } prefer ValueTask<T> to Task<T> if there is a good chance of things ever completely synchronously with many different return values: ValueTask<string> DoTheThings() { async ValueTask<string> Awaited(ValueTask<Cat> a, Task<House> b, Task<Tesla> c) { return DoWhatever(await a, await b, await c); } ValueTask<Cat> x = FeedCat(); ValueTask<House> y = SellHouse(); ValueTask<Tesla> z = BuyCar(); if(x.IsCompletedSuccessfully && y.IsCompletedSuccessfully && z.IsCompletedSuccessfully) return new ValueTask<string>( DoWhatever(a.Result, b.Result, c.Result)); // we can safely access .Result, as they are known // to be ran-to-completion return Awaited(x, y, z); } if possible, prefer IsCompletedSuccessfully to Status == TaskStatus.RanToCompletion; this now exists in .NET Core for Task, and everywhere for ValueTask<T>
当你使用WhenAll后，你可以用await单独拉出结果:
var catTask = FeedCat();
var houseTask = SellHouse();
var carTask = BuyCar();
await Task.WhenAll(catTask, houseTask, carTask);
var cat = await catTask;
var house = await houseTask;
var car = await carTask;
[注意异步方法总是返回“热”(已经启动的)任务。]
你也可以使用Task。结果(因为此时您知道它们都已成功完成)。但是，我推荐使用await，因为它显然是正确的，而Result在其他场景中可能会导致问题。
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