考虑一下我的代码:

import os


def readFile(filename):
    filehandle = open(filename)
    print filehandle.read()
    filehandle.close()



fileDir = os.path.dirname(os.path.realpath('__file__'))
print fileDir

#For accessing the file in the same folder
filename = "same.txt"
readFile(filename)

#For accessing the file in a folder contained in the current folder
filename = os.path.join(fileDir, 'Folder1.1/same.txt')
readFile(filename)

#For accessing the file in the parent folder of the current folder
filename = os.path.join(fileDir, '../same.txt')
readFile(filename)

#For accessing the file inside a sibling folder.
filename = os.path.join(fileDir, '../Folder2/same.txt')
filename = os.path.abspath(os.path.realpath(filename))
print filename
readFile(filename)

对我有用的是使用sys.path.insert。然后我指定了我需要访问的目录。例如，我只需要到一个目录。

import sys
sys.path.insert(0, '../')

考虑一下我的代码:

import os


def readFile(filename):
    filehandle = open(filename)
    print filehandle.read()
    filehandle.close()



fileDir = os.path.dirname(os.path.realpath('__file__'))
print fileDir

#For accessing the file in the same folder
filename = "same.txt"
readFile(filename)

#For accessing the file in a folder contained in the current folder
filename = os.path.join(fileDir, 'Folder1.1/same.txt')
readFile(filename)

#For accessing the file in the parent folder of the current folder
filename = os.path.join(fileDir, '../same.txt')
readFile(filename)

#For accessing the file inside a sibling folder.
filename = os.path.join(fileDir, '../Folder2/same.txt')
filename = os.path.abspath(os.path.realpath(filename))
print filename
readFile(filename)

例子

下面是一个用Python '3.9.5 '测试的例子:

您的当前目录:'c:\project1\code\' 你想要访问以下文件夹:'c:\project1\dataset\train\'。 然后您可以使用以下地址访问该文件夹:“../dataset/train/”

参考文献

如果你想了解更多关于Python中路径的信息，请阅读以下内容:

Pep - 355 Pep - 519

我认为要在所有系统中使用“ntpath”而不是“os.path”。如今，它在Windows、Linux和Mac OSX上都能很好地工作。

import ntpath
import os
dirname = ntpath.dirname(__file__)
filename = os.path.join(dirname, 'relative/path/to/file/you/want')

一个简单的解决办法是

import os
os.chdir(os.path.dirname(__file__))