我使用下面的代码，工作非常可靠。

JSON数据在参数$request中传递，特定的请求类型在变量$searchType中传递。

该代码包含一个陷阱，用于检测和报告不成功或无效的调用，然后返回false。

如果调用成功，json_decode ($result->getBody()， $return=true)返回一个结果数组。

    public function callAPI($request, $searchType) {
    $guzzleClient = new GuzzleHttp\Client(["base_uri" => "https://example.com"]);

    try {
        $result = $guzzleClient->post( $searchType, ["json" => $request]);
    } catch (Exception $e) {
        $error = $e->getMessage();
        $error .= '<pre>'.print_r($request, $return=true).'</pre>';
        $error .= 'No returnable data';
        Event::logError(__LINE__, __FILE__, $error);
        return false;
    }
    return json_decode($result->getBody(), $return=true);
}

$client = new \GuzzleHttp\Client(['base_uri' => 'http://example.com/api']);

$response = $client->post('/save', [
    'json' => [
        'name' => 'John Doe'
    ]
]);

return $response->getBody();

$client = new \GuzzleHttp\Client();

$body['grant_type'] = "client_credentials";
$body['client_id'] = $this->client_id;
$body['client_secret'] = $this->client_secret;

$res = $client->post($url, [ 'body' => json_encode($body) ]);

$code = $res->getStatusCode();
$result = $res->json();

对于《Guzzle 5》，《Guzzle 6》和《Guzzle 7》，你是这样做的:

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);

Docs

上述答案对我来说并不管用。但这对我来说很好。

 $client = new Client('' . $appUrl['scheme'] . '://' . $appUrl['host'] . '' . $appUrl['path']);

 $request = $client->post($base_url, array('content-type' => 'application/json'), json_encode($appUrl['query']));

@user3379466是正确的，但在这里我重写了全文:

-package that you need:

 "require": {
    "php"  : ">=5.3.9",
    "guzzlehttp/guzzle": "^3.8"
},

-php code (Digest is a type so pick different type if you need to, i have to include api server for authentication in this paragraph, some does not need to authenticate. If you use json you will need to replace any text 'xml' with 'json' and the data below should be a json string too):

$client = new Client('https://api.yourbaseapiserver.com/incidents.xml', array('version' => 'v1.3', 'request.options' => array('headers' => array('Accept' => 'application/vnd.yourbaseapiserver.v1.1+xml', 'Content-Type' => 'text/xml'), 'auth' => array('username@gmail.com', 'password', 'Digest'),)));

$url = "https://api.yourbaseapiserver.com/incidents.xml"; $data = '<事件> <名称>事件Title2a < /名称> <优先>中> < /优先 <请求者> < >电子邮件dsss@mail.ca < /电子邮件> < /请求者> <描述> description2a > < /描述 > < /事件”;

    $request = $client->post($url, array('content-type' => 'application/xml',));

    $request->setBody($data); #set body! this is body of request object and not a body field in the header section so don't be confused.

    $response = $request->send(); #you must do send() method!
    echo $response->getBody(); #you should see the response body from the server on success
    die;

解决*暴饮暴食6 * - -你需要的包:

 "require": {
    "php"  : ">=5.5.0",
    "guzzlehttp/guzzle": "~6.0"
},

$client = new Client([
                             // Base URI is used with relative requests
                             'base_uri' => 'https://api.compay.com/',
                             // You can set any number of default request options.
                             'timeout'  => 3.0,
                             'auth'     => array('you@gmail.ca', 'dsfddfdfpassword', 'Digest'),
                             'headers' => array('Accept'        => 'application/vnd.comay.v1.1+xml',
                                                'Content-Type'  => 'text/xml'),
                         ]);

$url = "https://api.compay.com/cases.xml";
    $data string variable is defined same as above.


    // Provide the body as a string.
    $r = $client->request('POST', $url, [
        'body' => $data
    ]);

    echo $r->getBody();
    die;