简单而基本的方法(guzzle6):

$client = new Client([
    'headers' => [ 'Content-Type' => 'application/json' ]
]);

$response = $client->post('http://api.com/CheckItOutNow',
    ['body' => json_encode(
        [
            'hello' => 'World'
        ]
    )]
);

为了获得响应状态代码和主体的内容，我这样做:

echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';

对于《Guzzle 5》，《Guzzle 6》和《Guzzle 7》，你是这样做的:

use GuzzleHttp\Client;

$client = new Client();

$response = $client->post('url', [
    GuzzleHttp\RequestOptions::JSON => ['foo' => 'bar'] // or 'json' => [...]
]);

Docs

对于Guzzle <= 4:

这是一个原始的post请求，所以把JSON放在body中解决了这个问题

$request = $this->client->post(
    $url,
    [
        'content-type' => 'application/json'
    ],
);
$request->setBody($data); #set body!
$response = $request->send();

解决方案$客户端->请求('POST'，…

对于那些使用$client->请求的人，这是如何创建JSON请求的:

$client = new Client();
$res = $client->request('POST', "https://some-url.com/api", [
    'json' => [
        'paramaterName' => "parameterValue",
        'paramaterName2' => "parameterValue2",
    ]
    'headers' => [
    'Content-Type' => 'application/json',
    ]
]);

Guzzle JSON请求参考

简单地使用它将工作

   $auth = base64_encode('user:'.config('mailchimp.api_key'));
    //API URL
    $urll = "https://".config('mailchimp.data_center').".api.mailchimp.com/3.0/batches";
    //API authentication Header
    $headers = array(
        'Accept'     => 'application/json',
        'Authorization' => 'Basic '.$auth
    );
    $client = new Client();
    $req_Memeber = new Request('POST', $urll, $headers, $userlist);
    // promise
    $promise = $client->sendAsync($req_Memeber)->then(function ($res){
            echo "Synched";
        });
      $promise->wait();

简单而基本的方法(guzzle6):

$client = new Client([
    'headers' => [ 'Content-Type' => 'application/json' ]
]);

$response = $client->post('http://api.com/CheckItOutNow',
    ['body' => json_encode(
        [
            'hello' => 'World'
        ]
    )]
);

为了获得响应状态代码和主体的内容，我这样做:

echo '<pre>' . var_export($response->getStatusCode(), true) . '</pre>';
echo '<pre>' . var_export($response->getBody()->getContents(), true) . '</pre>';