如果你有一张图片，试试这个:

-(void)setBackgroundImage:(UIImage *)image forState:(UIControlState)state;

或者看看showsTouchWhenHighlighted是否足够。

简单的是只使用UIButton扩展

extension UIButton {

    func setBackgroundColor(color: UIColor, forState: UIControl.State) {
        self.clipsToBounds = true  // add this to maintain corner radius
        UIGraphicsBeginImageContext(CGSize(width: 1, height: 1))
        if let context = UIGraphicsGetCurrentContext() {
            context.setFillColor(color.cgColor)
            context.fill(CGRect(x: 0, y: 0, width: 1, height: 1))
            let colorImage = UIGraphicsGetImageFromCurrentImageContext()
            UIGraphicsEndImageContext()
            self.setBackgroundImage(colorImage, for: forState)
        }
    }

}

然后用这个

 optionButton.setBackgroundColor(color: UIColor(red:0.09, green:0.42, blue:0.82, alpha:1.0), forState: .selected)

 optionButton.setBackgroundColor(color: UIColor(red:0.96, green:0.96, blue:0.96, alpha:1.0), forState: .highlighted)

 optionButton.setBackgroundColor(color: UIColor(red:0.96, green:0.96, blue:0.96, alpha:1.0), forState: .normal)

试试tintColor:

_button.tintColor = [UIColor redColor];

在Swift中，你可以重写高亮显示(或选中)属性的访问器，而不是重写setHighlighted方法

override var highlighted: Bool {
        get {
            return super.highlighted
        }
        set {
            if newValue {
                backgroundColor = UIColor.blackColor()
            }
            else {
                backgroundColor = UIColor.whiteColor()
            }
            super.highlighted = newValue
        }
    }

试试这个!!!!

TouchedDown事件设置一种颜色，TouchUpInside设置另一种颜色。

- (IBAction)touchedDown:(id)sender {
    NSLog(@"Touched Down");
    btn1.backgroundColor=[UIColor redColor];
}

- (IBAction)touchUpInside:(id)sender {
    NSLog(@"TouchUpInside");
    btn1.backgroundColor=[UIColor whiteColor];    
}

如果你不重写 只需要设置两个动作 触地得分 touchUpInside