我有一个叫做people的mongodb集合 其架构如下:

people: {
         name: String, 
         friends: [{firstName: String, lastName: String}]
        }

现在,我有一个非常基本的快速应用程序连接到数据库,并成功地创建“人”与一个空的朋友数组。

在应用程序的次要位置,有一个添加好友的表单。表单接收firstName和lastName,然后是带有名称字段的POSTs,同样用于引用适当的people对象。

我有一个困难的时间做的是创建一个新的朋友对象,然后“推”到朋友数组。

我知道当我通过mongo控制台这样做时,我使用$push作为查找标准后的第二个参数的更新函数,但我似乎找不到合适的方法让猫鼬这样做。

db.people.update({name: "John"}, {$push: {friends: {firstName: "Harry", lastName: "Potter"}}});

当前回答

这就是你如何推送一个项目——官方文档

const schema = Schema({ nums: [Number] });
const Model = mongoose.model('Test', schema);

const doc = await Model.create({ nums: [3, 4] });
doc.nums.push(5); // Add 5 to the end of the array
await doc.save();

// You can also pass an object with `$each` as the
// first parameter to use MongoDB's `$position`
doc.nums.push({
  $each: [1, 2],
  $position: 0
});
doc.nums;

其他回答

使用$push更新文档并在数组中插入新值。

发现:

db.getCollection('noti').find({})

查找结果:

{
    "_id" : ObjectId("5bc061f05a4c0511a9252e88"),
    "count" : 1.0,
    "color" : "green",
    "icon" : "circle",
    "graph" : [ 
        {
            "date" : ISODate("2018-10-24T08:55:13.331Z"),
            "count" : 2.0
        }
    ],
    "name" : "online visitor",
    "read" : false,
    "date" : ISODate("2018-10-12T08:57:20.853Z"),
    "__v" : 0.0
}

更新:

db.getCollection('noti').findOneAndUpdate(
   { _id: ObjectId("5bc061f05a4c0511a9252e88") }, 
   { $push: { 
             graph: {
               "date" : ISODate("2018-10-24T08:55:13.331Z"),
               "count" : 3.0
               }  
           } 
   })

更新结果:

{
    "_id" : ObjectId("5bc061f05a4c0511a9252e88"),
    "count" : 1.0,
    "color" : "green",
    "icon" : "circle",
    "graph" : [ 
        {
            "date" : ISODate("2018-10-24T08:55:13.331Z"),
            "count" : 2.0
        }, 
        {
            "date" : ISODate("2018-10-24T08:55:13.331Z"),
            "count" : 3.0
        }
    ],
    "name" : "online visitor",
    "read" : false,
    "date" : ISODate("2018-10-12T08:57:20.853Z"),
    "__v" : 0.0
}

我也遇到过这个问题。我的解决办法是创建一个子模式。请参见下面的模型示例。

----人物模型

const mongoose = require('mongoose');
const SingleFriend = require('./SingleFriend');
const Schema   = mongoose.Schema;

const productSchema = new Schema({
  friends    : [SingleFriend.schema]
});

module.exports = mongoose.model('Person', personSchema);

* * *重要:SingleFriend。Schema ->确保模式使用小写

——子图式

const mongoose = require('mongoose');
const Schema   = mongoose.Schema;

const SingleFriendSchema = new Schema({
  Name: String
});

module.exports = mongoose.model('SingleFriend', SingleFriendSchema);

就我而言,我是这样做的

  const eventId = event.id;
  User.findByIdAndUpdate(id, { $push: { createdEvents: eventId } }).exec();

首先,我尝试了这个代码

const peopleSchema = new mongoose.Schema({
  name: String,
  friends: [
    {
      firstName: String,
      lastName: String,
    },
  ],
});
const People = mongoose.model("person", peopleSchema);
const first = new Note({
  name: "Yash Salvi",
  notes: [
    {
      firstName: "Johnny",
      lastName: "Johnson",
    },
  ],
});
first.save();
const friendNew = {
  firstName: "Alice",
  lastName: "Parker",
};
People.findOneAndUpdate(
  { name: "Yash Salvi" },
  { $push: { friends: friendNew } },
  function (error, success) {
    if (error) {
      console.log(error);
    } else {
      console.log(success);
    }
  }
);

但我注意到,只有第一个朋友(即约翰尼约翰逊)得到保存和目标,以推动数组元素在现有的“朋友”数组似乎不工作,因为当我运行代码,在数据库中只显示“第一个朋友”和“朋友”数组只有一个元素! 所以简单的解决方案写在下面

const peopleSchema = new mongoose.Schema({
  name: String,
  friends: [
    {
      firstName: String,
      lastName: String,
    },
  ],
});
const People = mongoose.model("person", peopleSchema);
const first = new Note({
  name: "Yash Salvi",
  notes: [
    {
      firstName: "Johnny",
      lastName: "Johnson",
    },
  ],
});
first.save();
const friendNew = {
  firstName: "Alice",
  lastName: "Parker",
};
People.findOneAndUpdate(
  { name: "Yash Salvi" },
  { $push: { friends: friendNew } },
  { upsert: true }
);

添加“{upsert: true}”在我的情况下解决了问题,一旦代码被保存,我运行它,我看到“朋友”数组现在有2个元素! 如果对象不存在,upsert = true选项将创建该对象。默认设置为false。

如果它不工作,使用下面的片段

People.findOneAndUpdate(
  { name: "Yash Salvi" },
  { $push: { friends: friendNew } },
).exec();

要做到这一点,一个简单的方法是使用以下方法:

var John = people.findOne({name: "John"});
John.friends.push({firstName: "Harry", lastName: "Potter"});
John.save();